GCSE maths coursework: Emma's dilemma

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Firstly we arrange EMMA's Name.

)EAMM 7)MAEM

2)EMAM 8)MAME

3)MEMA 9)AMME

4)MEAM 10)AEMM

5)MMEA 11)AMEM

6)MMAE 12)EMMA

.

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Secondly we arrange Lucy's name.

)Lucy 12)Cyul 22)Yulc

2)Luyc 13)Culy 23)Ycul

4)Lycu 14)Culy 24)Yluc

5)Lcuy 15)Cylu 25)Ucyl

6)Lcyu 16)Clyu

7)Ulcy 17)Cuyl

8)Ucly 18)Yluc

9)Uycl 19)Yucl

10)Ulyc 20)Yclu

11)Uylc 21)Ylcu

From these 2 investigation I worked out a method, To Use My Method I Preferred To Convert Letters into Numbers, It Makes No Difference:

Step1: 1234---Do the last two number first then you get 1243.

1243---Do the last three numbers and try the possibility. 1423. 1432. 1342.1324, because the number 2 has been the first number of last three numbers, so we don't do it again.

Step2: we have list all arrangements of 1 go front, so we do 2 go front. 2134 and we do same thing to it, it will look like this:

2134---2143, 2143---2431,2413,2314,2341

Step3: We have finished 2 go first, then let's do 3 go ahead.

3124---3142, 3142---3241,3214,3412,3421

Step4: We have finished 3 go ahead, then try 4

4123---4132, 4132---4231,4213,4312,4321

We have list all arrangement of 1234, use this method we can arrange the number which has 5 figures or more.

We are trying to work out a formula which can calculate the number of arrangement when we look at a number.

Let's list all the arrangement for 1234:

234 4123

243 4132

324 --- 6 arrangement 4231 ---- 6 arrangement

342 4213

432 4321

423 4312

2134 3124

2143 3143

2341 ---- 6 arrangements 3241 --- 6 arrangements

2314 3214

2413 3412

2431 3421

So if we multiply 6 by 4, we would get 24, and we can get the total arrangements of 24.

Let's try 5 figures:

2345 13245

2354 13254

2435 --- 6 arrangements 13452 --- 6 arrangements

2453 13425

2534 13524

2543 13542

4235 15432

4253 15423

4352 --- 6 arrangements 15324 ---- 6 arrangements

4523 15342

4532 15243

4325 15234

Don't you notice the arrangements of last 4 numbers added up, it equal 24, so if we times 24 by 5, and get 120, and 120 is the total of arrangements.

if a number has 6 figures, then the total of arrangement should be 120 times by 6, and get 720, and 720 is the total of arrangements.
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Carry on, if a number has 7 figures, then the total of arrangement should be 720 times by 7, and get 5040, the total of arrangement is 5040.

This is my prediction, let's work it out a formula, and confirm it.

3 figure with different number it has 6 arrangements

4 4*6

5 4*6*5

6 4*6*5*6

7 4*6*5*6*7

8 4*6*5*6*7*8

so on

We can rewrite it as:

fig 1

2 fig 1*2

3 fig 1*2*3

4 fig 1*2*3*4

5 fig 1*2*3*4*5

6 fig ...

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