• Join over 1.2 million students every month
  • Accelerate your learning by 29%
  • Unlimited access from just £6.99 per month

Decompose copper carbonate by heating and measure the amount of gas produced.

Extracts from this document...


Chemistry Investigation Introduction: To find out the correct formula, I will need the aid of an experiment. I will have to decompose the copper carbonate by heating and measure the amount of gas produced. The volume of gas will help me determine which equation is correct. Method: 1. Set up the apparatus as shown below. 2. Measure out 0.25g of copper carbonate to the nearest 0.01g, remembering to turn the scales after placing the container in which to hold the copper carbonate. 3. Put the copper carbonate into a conical flask and attach a bung, which has a tube protruding from it, so that the rubber tube can be attached easily. 4. Attach the tube connected to the bung by a rubber tube, which is connected to the end of the glass syringe. 5. Make sure that the apparatus is fully connected so that the gas won't leak out. Place conical flask on top of the tripod and turn on the Bunsen burner. 6. Leave the Bunsen burner on until the syringe end stops moving, because reaction has finished therefore no more gas will be produced. ...read more.


+ CO (g) According to this equation, 1 moles of CuCO will produce 1 mole of gas. So the ratio of copper carbonate to gas is 1:1, to make both set of calculations become equal I am doubling the amount of copper carbonate, therefore the new ratio will be 2:2. To determine the amount of 2CuCO to use so that I will get a sensible amount of gas, I'm going to work out the weight of 1 mole of 2CuCO and use this to work out how much gas the reaction will produce: 2CuCO = 2(63.5+12+(16x3)) =247 This number can be rounded up to 250g as such a slight difference between the real mass and the mass used here won't make a big difference. 1 mole of gas will take up 24000cm� under standard conditions. If 250g of 2CuCO is used (250/250=1 mole of 2CuCO ) the amounts of gas produced will be: Equation 1- 2:21/2 volume of gas produced 21/2x24000=60000cm� Equation 2- 2:2 volume of gas produced 2x24000= 48000cm� This much gas is far too much to be collected in a normal experiment and the equipment needed is too difficult to find, so I will reduce the amount of 2CuCO . ...read more.


Clamp- to hold syringe in place. Rubber tubing is used as it is flexible and can create an airtight seal connecting the conical flask and syringe. Spatula- used for measuring out the amount of copper carbonate. Goggles- used for safety Experimental errors: � The leakage of gas, however many precautions you take under normal circumstances, can't ensure that there will be no leakage of gas. Some of the gas will escape. � The syringe is not totally accurate and there may be some human error whilst the syringe is being read, also it may be difficult to judge when exactly the gas will have cooled down and it may not have cooled down in 5 minutes. � The weight of the CuCO measured may not be totally accurate as it is measured to the nearest 0.01g. � The Bunsen burner may be turned off too quickly if it seems as if the reaction has stopped because the movement of the cylinder end has slowed down so much it seems to have stopped. Safety Precautions: An apron must be worn as well as goggles. Also the tripod must not be touched straight after the experiment as it may still be hot and may cause burns. ...read more.

The above preview is unformatted text

This student written piece of work is one of many that can be found in our AS and A Level War Poetry section.

Found what you're looking for?

  • Start learning 29% faster today
  • 150,000+ documents available
  • Just £6.99 a month

Not the one? Search for your essay title...
  • Join over 1.2 million students every month
  • Accelerate your learning by 29%
  • Unlimited access from just £6.99 per month

See related essaysSee related essays

Related AS and A Level War Poetry essays

  1. Which Equation is Correct?

    have chosen to use 0.4g of copper carbonate because the amount of gas I predict it to produce is a reasonable amount less than the maximum measuring capacity of the gas syringe. Calculations Moles = Mass/RMM RAM (relative atomic mass)

  2. Determination of the Value of the Gas Constant and the Molar Volume of Oxygen ...

    For this calculation, applying the Pressure Law, see that: (P1V1)/T1 = (P2V2)/T2 [(101300 N.m-1)(8.9x10-5 m3)]/(294.5 K) = [(101325 N.m-1)(V2)]/(273 K) V2 = [(101300 N.m-1)(8.9x10-5 m3)(273 K)]/[(294.5 K)(101325 N.m-1)] V2 = 8.25 x 10-5 m3 The actual volume of the same quantity of gas would have this value, but to

  1. Right equation

    � 75 = 0.30875g = 0.3 (1 d.p) ?Mass of CuCO3 that would develop 75cm3 of gas in equation 1 = 0.3g Now by using the same mass, I can find the volume of gas will be produced by equation 2 123.5 CuCO3 = 24 000cm3 1 CuCO3 = 24 � 123.5 Volume of gas = (24 � Mr)

  2. I need to produce a marketing strategy for a new or existing product. I ...

    During the first six months of this year complaint volumes to the Gas Consumers Council have continued to fall, down 23% on last year. Home Service's complaints were down by 7% and Gas Supply complaints were 26% lower. The efforts they have made, together with Ofgem, to improve and simplify

  1. Determine which of two equations below is the correct equation of the thermal decomposition ...

    1 mole of CuCO3 will decompose to give you 1 mole of CuO and 1 mole of CO2, it is a stoichyometric equation. Equation 1: 2CuCO3(s) Cu2O(s) + 2CO2(g) + 1/2O2(g) 1 : 1 Equation 2: CuCO3(s) CuO(s) + CO2(g)

  2. Determining the Correct Equation for the Decomposition of Copper Carbonate.

    We can the go on to replace n with the equation as above: Moles=mass R.A.M It then becomes: PV = mass x RT R.A.M We can then rearrange this formula to make the mass the subject: Mass = R.A.M x PV RT This then enables us to work out the mass.

  • Over 160,000 pieces
    of student written work
  • Annotated by
    experienced teachers
  • Ideas and feedback to
    improve your own work