• Join over 1.2 million students every month
  • Accelerate your learning by 29%
  • Unlimited access from just £6.99 per month

This experiment involves the decomposition of copper carbonate whereby we want to find out whether CuO(3/4) or Cu20(s) is formed upon the decomposition of copper carbonate when heated. I intend to use mole equations

Extracts from this document...


AS - Assessed Practical 1 Which Equation is Correct? Task: This experiment involves the decomposition of copper carbonate whereby we want to find out whether CuO(?) or Cu20(s) is formed upon the decomposition of copper carbonate when heated. I intend to use mole equations to find the volume of gas produced in both equations in order to solve the problem set. Equation 1 - 2CuCO3(s) Cu2O(s) + 2CO2(g) + 1/2O2 Equation 2 - CuCO3(s) CuO(s) + CO2(g) By using the formula for moles and the volume of gas, I am able to predict the volume of gas produced before I have actually implemented the experiment. Equipment and Reagents * Tripod and Mat * Bunsen Burner and Rubber Bung * Boss and Clamp Stand * 100ml Conical Flask * 100cm� Graduated Gas Syringe * Weighing Scale (�0.01g) * ?g of copper carbonate ( The mass will be decided later on because we are limited to 100cm� volume of gas in the syringe. Background Information Copper carbonate is a green solid when reacted. Once it decomposes upon heating a colour change from green to black will occur. ...read more.


Cu2O(s) + 2CO2(g) + 1/2O2 Mole ratio: 2 : 1 : 2 : 0.5 2CO2 : The ratio is the same as 2CuCO3, therefore the moles is also equal to 0.008 moles. Volume of Gas = Moles x 24dm� = 0.008 x 24 = 0.190dm� or (x1000) = 190cm� 1/2O2 : The ration is a 1/4 of the mole ratio, therefore the moles for oxygen is: =0.008/4 = 0.002 moles Volume of gas = Moles x 24dm� = 0.002 x 24 = 0.048dm� or (x1000) = 48.0cm� * The total amount of gas in the syringe therefore would be: 190cm� + 48.0cm� = 238.0cm� * This is a problem because the gas syringe cannot hold this amount of gas. * If I were to multiply the total gas by 3/10 we would get 71.4cm�total volume of gas. * This means that if we multiply the mass by 3/10, we would get 0.30g of copper carbonate. * Thus, I will use 0.30g of copper carbonate, and if this value produced a volume that was less than 100cm� in the second equation: Equation 2 - CuCO3(s) ...read more.


CuO(s) + CO2(g) * This equation will produce 58.3cm� of gas. The syringe, which collects the gas, has an accuracy to the nearest decimal place, �0.5cm�. The percentage error is: * (�0.5/58.3) � 100 = 0.86%. * The range of the syringe allows values between 58.2<cm�<58.4. * The total error for equation 2 is: * 0.86% + 1.67% = 2.53% * This indicates that these errors are insignificant and should not affect the results. * I think that this is the least error possible, because if the copper carbonate is not pure, then we will not produce these results and the accuracy. Precision * To make sure that I produce accurate results, I intend to repeat the experiment several times until I achieve consistent results. Safety * Lab coats must be worn during the experiment. * Goggles must be worn at all times. * Make sure that you not using any faulty equipment. * Make sure that the gas syringe moves smoothly and its slider does not get stuck when collecting the gas, which will increase the pressure exerted on it, causing it to break. * Allow the experiment to cool before clearing up because if the conical flask is washed immediately then it will break and also the equipment will be very hot. ...read more.

The above preview is unformatted text

This student written piece of work is one of many that can be found in our AS and A Level War Poetry section.

Found what you're looking for?

  • Start learning 29% faster today
  • 150,000+ documents available
  • Just £6.99 a month

Not the one? Search for your essay title...
  • Join over 1.2 million students every month
  • Accelerate your learning by 29%
  • Unlimited access from just £6.99 per month

See related essaysSee related essays

Related AS and A Level War Poetry essays

  1. Marked by a teacher

    The idea of the experiment is to determine which equation is correct. There are ...

    5 star(s)

    equation 2 is correct and if it turns red, then it shows presence of Cu2O which mean equation 1 is correct. I will also test the gas given off with a glowing splint. If it re ignites, this shows that oxygen is given off; also proving equation 1 is correct.

  2. The Thermal Decompasition Of Copper Carbonate

    Heat until the copper carbonate has entirely decomposed. This will be indicated by the fact that the gas syringe will stop moving and the powder has gone either black or red. Take the reading from the gas syringe and note down the volume of gas produced.

  1. The Decomposition of Copper Carbonate

    moles 2.5 According to the Eqn, the mole ratio of CuCO3 to CO2 is 2:2. This means we need 0.00266... moles CuCO3 to be decomposed in oreder to create the 80cm3 of gas. From this we can find the mass of CuCO3 to be used, by using the formula: Mass = moles x RFM (relative formula mass)

  2. Right equation

    that has to be kept the same is temperature, the collected gas should be kept at room temperature, and the gas syringe should be kept as far away as possible when heating the copper carbonate. The gas syringe should be cooled down for a short period of time after the copper carbonated has been heated.

  1. am trying to find out whether the equation 2CuCO3 Cu2O + 2CO2 ...

    Cu2O + 2CO2 + 1/2O2 Mol Ratio 1 : 0.5 : 1 : 0.25 Total number of mols of gas in equation one: 1.25 Equation 2: CuCO3 ? CuO + CO2 Mol Ratio: 1 : 1 : 1 Total number of mols of gas in equation two: 1 The total

  2. The aim of this experiment is to prove which of these two equations is ...

    The largest gas syringe available can hold 100cm�. It would not, however, be sensible to attempt to produce 100cm� because if Equation 1 turns out to be the correct one, which would mean oxygen is also produced and there would consequently be more gas.

  1. I need to produce a marketing strategy for a new or existing product. I ...

    Despite recent gas price rises their current annual gas bill is still on average �55 cheaper in real terms than in 1996 2. Place. This is where and how your product is distributed and sold. Will you sell it yourself, through a broker, or a distributor?

  2. Decompose copper carbonate by heating and measure the amount of gas produced.

    Wash the affected area thoroughly. If spilt in Lab:- Wear Eye protection. Scoop up as much Solid as possible without raising too much dust. Wipe area repeatedly with a damp cloth until all solid is removed. Disposal:- Add 1kg of sand and place in refuse.

  • Over 160,000 pieces
    of student written work
  • Annotated by
    experienced teachers
  • Ideas and feedback to
    improve your own work