• Join over 1.2 million students every month
  • Accelerate your learning by 29%
  • Unlimited access from just £6.99 per month

Comparative Newspaper Project

Extracts from this document...

Introduction

Statistics Coursework Comparative Newspaper Project In this investigation I am going to look at the difference between two types of newspaper: tabloids, and broadsheets. I could compare the number of letters in a word, the proportion of text to images, or the perhaps the number of words with 3 or more syllables, but I have chosen to compare the lengths of sentences. This is because I think broadsheets will have longer sentences on average, as they are more 'intellectual' newspapers. They are not like tabloids that are easy to dip into for news for busy working class people, but are there specifically for people who want to, and have the time to, to read the news fully, and in more depth. In addition, this will not be too complicated to find out, as, for example, finding the proportion of text to images is more open to error. For this investigation I am going to take a sample size of 175 for two different newspapers, one national tabloid, and one national broadsheet, the parent population being sentence lengths in national daily newspapers across the country. I'm assuming that all broadsheets and all tabloids are similar. I've used a sample size of 175, as it is large enough to be reasonably accurate, but not too large that it would take too long to collect the data. ...read more.

Middle

However, the data from both newspapers is slightly positively skewed. To look at this in more detail, I will draw a frequency density graphs. Frequency Density Graphs: Telegraph: Class Interval f From To Class Width F.D. 0 - 9 35 -0.5 9.5 10 35 / 10 = 3.50 10 - 14 23 9.5 14.5 5 23 / 5 = 4.60 15 - 19 26 14.5 20.5 5 26 / 5 = 5.20 20 - 24 23 20.5 24.5 5 23 / 5 = 4.60 25 - 29 25 24.5 29.5 5 25 / 5 = 5.00 30 - 34 18 29.5 34.5 5 18 / 5 = 3.60 35 - 54 25 34.5 54.5 20 25 / 20 = 1.25 Sun: Class Interval f From To Class Width F.D. 0 - 9 24 -0.5 9.5 10 24 / 10 = 2.40 10 - 14 21 9.5 14.5 5 21 / 5 = 4.20 15 - 19 55 14.5 20.5 5 55 / 5 = 11.00 20 - 24 41 20.5 24.5 5 41 / 5 = 8.20 25 - 29 23 24.5 29.5 5 23 / 5 = 4.60 30 - 34 7 29.5 34.5 5 7 / 5 = 1.40 35 - 54 4 34.5 54.5 20 4 / 20 = 0.20 See separate sheet - Frequency Density Graphs These frequency density graphs show that... ...read more.

Conclusion

A limitation that I had was that I only looked at one tabloid and one broadsheet. The newspapers that we selected may not be typical of those kinds of paper, so it would have been an advantage to sample more papers. If I were to repeat this investigation, or extend it I would sample more newspapers, but it was not possible to do it this time because it would be so time-consuming. If it were feasible to collect data like this for many samples, then I'd plot an accurate graph for the means of the means of the sample, which would be normally distributed, as long as the sample were large enough - The Central Limit Theorem states that 'If the sample size is large enough then the distribution of the sample means is approximately Normal, irrespective of the distribution of the parent population.' It would then be easier to predict more accurately the mean of the parent populations. To develop this investigation, I can use the data already collected to find out other information, such as how many sentences from a sample of, say, 100 chosen from a tabloid newspaper at random are 24 lines long or more. To do this I am assuming that the population is normal. X ~ N(18.217, ) Z =0.696257 ?? ?? ?? ?? Sarah Ruston ...read more.

The above preview is unformatted text

This student written piece of work is one of many that can be found in our AS and A Level Probability & Statistics section.

Found what you're looking for?

  • Start learning 29% faster today
  • 150,000+ documents available
  • Just £6.99 a month

Not the one? Search for your essay title...
  • Join over 1.2 million students every month
  • Accelerate your learning by 29%
  • Unlimited access from just £6.99 per month

See related essaysSee related essays

Related AS and A Level Probability & Statistics essays

  1. Standard addition was used to accurately quantify for quinine in an unknown urine sample ...

    The reference beam passes through an attenuator that reduces its power to approximately that of the fluorescence radiation. Signals from the reference are then fed into a difference amplifier whose output is displayed by a meter. Fig.2 Components Of A Fluorescence Spectrophotometer The Standard Addition Technique Standard addition is an alternate calibration technique to external standardisation.

  2. GCSE Mathematics Coursework: Statistics Project

    Q2 = 16 - " " =QUARTILE(I2:I101,2) Q3 = 24 - " " =QUARTILE(I2:I101,3) Max. value = 170 " " =MAX(I2:I101) Min. value = 1 " " =MIN(I2:I101) As a simple rule, points that lie more than 1.5 times the interquartile range above Q3 or below Q1 on a box plot are considered to be outliers.

  1. Statistics. The purpose of this coursework is to investigate the comparative relationships between the ...

    I think this is the case because as soon as a car is bought, the ownership status is converted to "second hand", and the value greatly goes down. A good correlation is displayed here: R2=0.5424 and any R2 greater than 0.3 is a strong correlation.

  2. Guestimate - investigate how well people estimate the length of lines and the size ...

    Frequency Cumulative Frequency Upper Class Boundary 0 < l < 2 0 0 2 2 < l < 4 3 3 4 4 < l < 6 17 20 6 6 < l < 8 6 26 8 8 < l < 10 4 30 10 10 < l <

  1. Teenagers and Computers Data And Statistics Project

    x 12 = 96 The 3 face corners will always be 8 6. Formula Explanation The first formula that I worked out was the total no of cubes, this was simple as to measure the volume of a cube is to cube the length that you have.

  2. Design an investigation to see if there is a significant relationship between the number ...

    This is as the seaweed on the middle shore will be exposed to these factors for a longer period of time than the Fucus vesiculosus on the lower shore. These factors cause desiccation and affect the rate of transpiration, and so may affect the distribution of seaweed on the shoreline.

  1. Estimating the length of the line and the size of the angle

    91.8 50 855 80 1283 6.9 165.4 4 95.8 35 890 70 1353 Mean of line 1 = 8.27cm Mean of line 2 = 4.79cm Mean of Angle 1 = 44.5� Mean of Angle 2 = 67.65� Now that I have found out the mean of each of the two

  2. The average pupil.

    Range Class width Frequency Frequency density 0<total mark<10 10 2 0.2 10<total mark<13 3 22 7.3 13<total mark<15 2 16 8 15<total mark<20 5 10 2 Yet again, comparing it with the year 7's distributions, the majority of the students lay somewhere in the middle with an average mark of

  • Over 160,000 pieces
    of student written work
  • Annotated by
    experienced teachers
  • Ideas and feedback to
    improve your own work