• Join over 1.2 million students every month
  • Accelerate your learning by 29%
  • Unlimited access from just £6.99 per month

Comparative Newspaper Project

Extracts from this document...

Introduction

Statistics Coursework Comparative Newspaper Project In this investigation I am going to look at the difference between two types of newspaper: tabloids, and broadsheets. I could compare the number of letters in a word, the proportion of text to images, or the perhaps the number of words with 3 or more syllables, but I have chosen to compare the lengths of sentences. This is because I think broadsheets will have longer sentences on average, as they are more 'intellectual' newspapers. They are not like tabloids that are easy to dip into for news for busy working class people, but are there specifically for people who want to, and have the time to, to read the news fully, and in more depth. In addition, this will not be too complicated to find out, as, for example, finding the proportion of text to images is more open to error. For this investigation I am going to take a sample size of 175 for two different newspapers, one national tabloid, and one national broadsheet, the parent population being sentence lengths in national daily newspapers across the country. I'm assuming that all broadsheets and all tabloids are similar. I've used a sample size of 175, as it is large enough to be reasonably accurate, but not too large that it would take too long to collect the data. ...read more.

Middle

However, the data from both newspapers is slightly positively skewed. To look at this in more detail, I will draw a frequency density graphs. Frequency Density Graphs: Telegraph: Class Interval f From To Class Width F.D. 0 - 9 35 -0.5 9.5 10 35 / 10 = 3.50 10 - 14 23 9.5 14.5 5 23 / 5 = 4.60 15 - 19 26 14.5 20.5 5 26 / 5 = 5.20 20 - 24 23 20.5 24.5 5 23 / 5 = 4.60 25 - 29 25 24.5 29.5 5 25 / 5 = 5.00 30 - 34 18 29.5 34.5 5 18 / 5 = 3.60 35 - 54 25 34.5 54.5 20 25 / 20 = 1.25 Sun: Class Interval f From To Class Width F.D. 0 - 9 24 -0.5 9.5 10 24 / 10 = 2.40 10 - 14 21 9.5 14.5 5 21 / 5 = 4.20 15 - 19 55 14.5 20.5 5 55 / 5 = 11.00 20 - 24 41 20.5 24.5 5 41 / 5 = 8.20 25 - 29 23 24.5 29.5 5 23 / 5 = 4.60 30 - 34 7 29.5 34.5 5 7 / 5 = 1.40 35 - 54 4 34.5 54.5 20 4 / 20 = 0.20 See separate sheet - Frequency Density Graphs These frequency density graphs show that... ...read more.

Conclusion

A limitation that I had was that I only looked at one tabloid and one broadsheet. The newspapers that we selected may not be typical of those kinds of paper, so it would have been an advantage to sample more papers. If I were to repeat this investigation, or extend it I would sample more newspapers, but it was not possible to do it this time because it would be so time-consuming. If it were feasible to collect data like this for many samples, then I'd plot an accurate graph for the means of the means of the sample, which would be normally distributed, as long as the sample were large enough - The Central Limit Theorem states that 'If the sample size is large enough then the distribution of the sample means is approximately Normal, irrespective of the distribution of the parent population.' It would then be easier to predict more accurately the mean of the parent populations. To develop this investigation, I can use the data already collected to find out other information, such as how many sentences from a sample of, say, 100 chosen from a tabloid newspaper at random are 24 lines long or more. To do this I am assuming that the population is normal. X ~ N(18.217, ) Z =0.696257 ?? ?? ?? ?? Sarah Ruston ...read more.

The above preview is unformatted text

This student written piece of work is one of many that can be found in our AS and A Level Probability & Statistics section.

Found what you're looking for?

  • Start learning 29% faster today
  • 150,000+ documents available
  • Just £6.99 a month

Not the one? Search for your essay title...
  • Join over 1.2 million students every month
  • Accelerate your learning by 29%
  • Unlimited access from just £6.99 per month

See related essaysSee related essays

Related AS and A Level Probability & Statistics essays

  1. Standard addition was used to accurately quantify for quinine in an unknown urine sample ...

    The reference beam passes through an attenuator that reduces its power to approximately that of the fluorescence radiation. Signals from the reference are then fed into a difference amplifier whose output is displayed by a meter. Fig.2 Components Of A Fluorescence Spectrophotometer The Standard Addition Technique Standard addition is an alternate calibration technique to external standardisation.

  2. GCSE Mathematics Coursework: Statistics Project

    IQR = Q3 - Q1 IQR = 24 - 11.5 IQR = 12.5 Lower boundary = Q1 - 1.5 x 12.5 = 11.5 - 18.75 = -7.25 - But in this case, the lowest possible value is 0 hours, as it is not possible to watch any less TV.

  1. Statistics. The purpose of this coursework is to investigate the comparative relationships between the ...

    1 -0.68 0.4624 1 -0.68 0.4624 1 -0.68 0.4624 1 -0.68 0.4624 1 -0.68 0.4624 1 -0.68 0.4624 1 -0.68 0.4624 2 0.32 0.1024 1 -0.68 0.4624 2 0.32 0.1024 1 -0.68 0.4624 2 0.32 0.1024 1 -0.68 0.4624 2 0.32 0.1024 1 -0.68 0.4624 3 1.32 1.7424 1 -0.68

  2. Teenagers and Computers Data And Statistics Project

    The one face was worked out by subtracting the 2 corner cubes from each length of 10 (N) then multiplying by 6. The actual sum was 10 - 2 = 8 x 8 = 64 x 6 = 384. The two face sum was worked out by 10 -2 =8

  1. Design an investigation to see if there is a significant relationship between the number ...

    This is an example of Survival of the Fittest in the natural environment. In addition, by conducting the investigation at this time of year I am also putting myself in the least amount of danger, as carrying out the investigation in winter would possibly bring treacherous weather conditions and more dangerous tidal movements due to lunar position.

  2. I want to find out if there is a connection between people's IQ and ...

    I can see that I am right due to the fact that the correlation of my scatter graph is positive. A positive correlation shows that as one variable increases, so does the other variable. In my case, as the average KS2 SATs result increases, so does the IQ.

  1. An Investigation Into An Aspect Of Human Variation.

    hand spans of females' shows a wide variation of hand span measurements. The hand span measurement of the greatest frequency is 18.5-19.5cm and there is a general bell shaped curve in the pattern of frequency distribution with fewer individuals with hand spans of the extreme values 14.5-15.5cm and 22.5-23.5cm and

  2. In this project I will be investigating three main hypotheses, which are all based ...

    One variable causes the change in the other variable.) I am able to draw a line of best fit. The line of best fit will pass through the mean average of each data set. You can see that as the number of bedrooms increase so does the price of that property.

  • Over 160,000 pieces
    of student written work
  • Annotated by
    experienced teachers
  • Ideas and feedback to
    improve your own work