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# Useing decision maths to help me find out what I have to do in the process of planning a party.

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Introduction

Samantha White Feb 03 USING DECISION MATHS TO ORGANISE A PARTY... In this coursework I am going to use decision maths to help me find out what I have to do in the process of planning a party. This is a good topic to choose because there are many factors that go into organising a party, and they take certain times and a number of workers to make it possible. Because of this it would be easy to use organising a party for decision maths. Another reason I chose this project instead of for example building a house, was because it would appeal to me more, and I think id find it interesting. The results that I find are going to be helpful for people who want to organise a party in this manner. Firstly I will plan out a precedence table for what to do when organising a party, and then develop from this an activity network, forward and backward passes and other techniques used in decision maths... IDENTIFYING THE PROBLEM: I have been asked to set out a rota for organising an 18th birthday party. I have to make sure that everything that needs to be done is included in this list... ...read more.

Middle

18 0 M 1 18 18 19 19 0 N 1 4 18 4 19 14 O 1 3 18 4 19 15 INTERPRETATION: From this table, and the activity network the fastest time it will take to organise a party this way, would be 19 days. The critical path for the activity network for organising a party is: A, C, D, E, G, J, L and M. I am now gong to construct a cascade chart with both the earliest and latest starts and finishes and the critical path to see how many workers would be needed to complete this activity (page 1 of appendix). The cascade chart with both the earliest and latest starts and the critical path shows that more than two workers will be needed to complete these tasks in the set time. I am now going to construct a cascade chart using both the earliest and latest starts to try and get the least amount of workers to complete the tasks in the minimum time. However, here I also have to take into consideration the immediate predecessors. This is because I have to make sure that each activity is placed in a place where its immediate predecessors have already happened (page 2 of appendix). ...read more.

Conclusion

Latest Start: (page 5 and 6 of appendix) From the histogram on page 6 of the appendix showing the latest possible times, the maximum number of workers needed is 7. CONCLUSION: In conclusion the histograms show that using the earliest possible start times is the most efficient way, as fewer workers are needed to get the tasks completed in the minimum time. All the work I have completed in this coursework helps lead up to this conclusion. This is a practical way of arranging a party, and throughout the whole of the coursework the immediate predecessors are taken into consideration. This means that my answers are precise, and everything is done in the correct order. Changes: If I were to change anything about this coursework I would have researched further whether each of the activities can be completed in a different order, and at a quicker speed. However, I feel my information is correct, and relevant to the task at hand. The changes that I would make to allow this to be more accurate would be, there would be more time allowed to complete all of the tasks. This way you can make sure everything is done in the correct way and more accurately. Trying to do things in the minimum time using decision maths could sometimes, in reality, make the task be done not up to the correct standard. Samantha White Page 1 4/27/2007 ...read more.

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