A2 CHEMESTRY IMPLEMENTATION

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NEELIMA Nathawat,

Centre Number: - 10508

Candidate Number: - 2485

The preparation of ions containing vanadium in two oxidation states

Aim: - To prepare the two oxidation states of vanadium ions.

Introduction:-  

Vanadium has the chemical symbol V with an atomic number of 23. Vanadium is transition metal and has 4 different oxidation states ranging from 5+ to 2+. The usual source of vanadium in the 5+ oxidation state is ammonium metavanadate (NH4VO3). Ammonium metavanadate can be reduced using zinc and an acid, usually moderately concentrated acid. In the case of my experiment, I will be using sulphuric               acid (H2S04) with zinc to reduce ammonium vanadate to an oxidation state of 2+.

The exact vanadium ion present in the solution is very complicated and it varies with the pH of the solution. The reaction is done under acidic conditions when the vanadium present is VO2+ and this ion is called dioxovanadium (V) ion.

Safety and Precautions:-

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Actions taken to increase accuracy of the procedure:-

Method 1:-

Preparing the solution for the changes in oxidation states of vanadium:-

 

  1. Take a conical flask and pour 25 cm3 of Ammonium Vanadate (V) and 25 cm3 of Sulphuric acid using a pipette filler. Then add 40cm3 of distilled water using measuring cylinder. Measure 5.00g of ...

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