• Join over 1.2 million students every month
  • Accelerate your learning by 29%
  • Unlimited access from just £6.99 per month

An Investigation into the Effect of the Catalase enzyme on Hydrogen Peroxide.

Extracts from this document...

Introduction

An Investigation into the Effect of the Catalase enzyme on Hydrogen Peroxide PLAN I am going to investigate the effect of the catalase enzyme on hydrogen peroxide, using starch for the catalase. Catalase is a biological enzyme which works best between 30 and 40 degrees, like most enzymes. It also has an optimum pH. Catalase breaks down Hydrogen Peroxide into water and oxygen. Plant and animal cells contain catalase. Variables Independent variables are things that I can change. Possible independent variables for this investigation are: � Temperature - the rate of reaction depends on the temperature as enzymes work best at certain temperatures. � Concentration of Catalase (enzyme) - the more concentrated the quicker the reaction. � Concentration of Hydrogen Peroxide - the more concentrated the quicker the reaction. � pH - enzymes have to be at the right pH to work properly. Dependent variables are things that change because of what I do. In this investigation possible dependent variables are � Volume of gas given off / evolved � Time I have chosen to measure the volume of oxygen given off over a period of 2.5 minutes, every ten seconds. I will make my investigation a FAIR TEST by controlling variables: � Concentration - always using 10ml of Hydrogen Peroxide. ...read more.

Middle

8) Then I put the bung in the test tube and immediately started the stopwatch. 9) Every ten seconds for 2.5 minutes I recorded how much gas had been made. I will repeat each test once. Amount of starch I will use is Starch Water 10ml 0ml 8ml 2ml 6ml 4ml 4ml 6ml 2ml 8ml Preliminary Experiment Before I started my main investigation I needed to know what a suitable range of water to use and how much Hydrogen peroxide and catalase to use. Here are my results for 10ml H2 O2 + 5ml starch + 5ml water Time (ins) Oxygen evolved (cm3) 0.5 1 1 3 1.5 4 2 4 2.5 5 Here are my results for 7ml H20 + 3ml Starch Time (ins) Oxygen evolved (cm3) 0.5 2 1 3 1.5 4 2 6 2.5 8 From this experiment I decided that I needed to use more starch for a quicker reaction and I decided that I should use 10ml of H2 02. I also decided to carry on my experiments, instead of using five minutes I chose 2.5 minutes. Obtaining evidence I obtained my results by carefully following my plan and method. The results I obtained were as follows: 21C Time (SCEs) ...read more.

Conclusion

There is one anomalous result for 6ml starch and 4ml water. This could be due to the fact that the stopwatch was misread or the bung might have been forced off the test tube during the experiment so that no gas was collected. My first graph shows that the optimum amount for catalase is10ml. This is because at 2ml the enzyme became denatured and could not form an enzyme substrate complex, therefore it produced no oxygen. At 4ml and 2ml there was less oxygen evolved because the water has diluted to and slowed the reaction by allot the Hydrogen Peroxide molecules had less kinetic energy and so there were fewer collisions and fewer enzyme-substrate complexes were formed, so less oxygen was evolved. Evaluation My results are really reliable and accurate as they prove my prediction, which was that, the catalase would break down the hydrogen peroxide down best when there was no water. My results are good enough to support a firm conclusion and my conclusion is safe. I have already identified anomalous results in the previous section. In my investigation I think the following areas should be improved next time: � More repeats � Checking bung regularly � Using a more reliable stopwatch. Overall, I think my investigation was successful. ...read more.

The above preview is unformatted text

This student written piece of work is one of many that can be found in our AS and A Level Molecules & Cells section.

Found what you're looking for?

  • Start learning 29% faster today
  • 150,000+ documents available
  • Just £6.99 a month

Not the one? Search for your essay title...
  • Join over 1.2 million students every month
  • Accelerate your learning by 29%
  • Unlimited access from just £6.99 per month

See related essaysSee related essays

Related AS and A Level Molecules & Cells essays

  1. The effect of Copper Sulphate concentration on Catalase activity on Hydrogen Peroxide.

    11.6 0 90 12.5 2.9 18.2 0 120 14.0 3.9 21.2 0 150 15.5 5.6 25.9 0 180 16.5 6.2 26.2 On the bases of the results that I obtained from our statistical test, classified them as outliers. I am now going to investigate into the possible explanations for why such results could have possibly been obtained.

  2. Catalyse Investigation

    It catalyses the decomposition of hydrogen peroxide, liberating oxygen gas as effervescence, each molecule of the globular protein decomposing 40,000 molecules of hydrogen peroxide per second at� zero degrees Celsius and capable of producing an amazing 1012 molecules of oxygen per second.

  1. Amylase Investigation

    In older names the suffix is added to the name of the substrate, as in amylase, an enzyme that breaks down the polysaccharide amylose. In newer names, the suffix is added to the type of reaction, as in lactase dehydrogenase, an enzyme that converts lactase to pyruvate by transferring a hydrogen atom to nicotinamide-adenine dinucleotide (NAD).

  2. To investigate the rate at which hydrogen peroxide is broken down by the enzyme ...

    tested to ensure that when the experiment is carried out and the results recorded the range of concentrations will give good accurate results, with a range wide enough to make a fair test and give a correct conclusion. I have decided to measure the volume of oxygen gas produced every

  1. Catalase investigation

    Enzymes also don't attack living cells. However, when a cell dies proteases quickly digest the cell so that the products, amino acids, can be used to rebuild other proteins. The reason the cells are not digested when they are alive is due to the fact that enzymes can't pass through the membrane of the cell when it's alive.

  2. Investigate how concentration of the enzyme catalase in celery tissue alters the rate of ...

    100% 75% Volume of Oxygen Gas produced (cm3) Anwar 12.5 18 20.5 8.5 15 19.5 Babu 12.2 15.5 17.7 11.1 14.1 20 Da Costa 10.2 13.4 16.1 9.4 11.7 13.8 Francis 5.5 7.8 12.2 8.1 11.2 13.7 Hussain 13.3 16.8 19.6 11.4 13.9 16.4 de Looze 17.5 3.8 3.5 14.6 5 3.3 MacDonald 12.7 13.7 15.3 11 13.1

  1. Reaction of Catalase and Hydrogen Peroxide

    This in turn will affect the number of enzyme-substrate complex being formed, which will affect the rate of reaction. 7. Temperature The temperature of a system is to some extent a measure of the kinetic energy of the molecules in the system.

  2. Investigating the effect of the Temperature on the Enzyme Catalase when it reacts with ...

    Below are the factors, which are kept constant. * Concentration of Hydrogen peroxide - use 1% concentration * Concentration of Catalase - use 50eu/cm3 of Catalase * Size of the paper (surface area) * Volume of Catalase - Use the same size and the same thickness of the filter paper

  • Over 160,000 pieces
    of student written work
  • Annotated by
    experienced teachers
  • Ideas and feedback to
    improve your own work