• Join over 1.2 million students every month
  • Accelerate your learning by 29%
  • Unlimited access from just £6.99 per month

Catalase Investigation

Extracts from this document...

Introduction

Catalase Investigation Introduction: This investigation is to see how the concentration of hydrogen peroxide affects the rate of reaction between catalase and hydrogen peroxide. An enzyme is a catalyst that is found inside living organisms. Catalase is found inside the cells of living organisms, both animal and plants. Catalase breaks down the hydrogen peroxide that is produced in the cells through other reactions. Hydrogen peroxide is dangerous to the cells so it has to be broken down by the catalase quickly. The equation for what catalase does is: Hydrogen Peroxide + Catalase = Water + Oxygen. 2H2O2 = 2H2O + O2 An enzyme is made of protein and is designed specially to break down or to make one type of molecule. An enzyme has an active site into which its substrate fits exactly. The active site of catalase is just the right size for a hydrogen peroxide molecule. So the hydrogen peroxide molecule fits exactly into the active site of the catalase and the hydrogen peroxide is split into water and hydrogen, leaving the catalase unaltered ready to accept another hydrogen peroxide molecule. ...read more.

Middle

Concentration of catalase: The higher the concentration of catalase the more hydrogen peroxide that can be broken down at once. This will increase the rate of the test. Concentration of substrate: If you increase the amount of hydrogen peroxide then the time it takes for the catalase to collide with it is decreased so the catalase works more efficiently. This would increase the amount of hydrogen gas so the 10cm� would be collected quicker. This is the variable that I am going to change. I am going to do this by diluting the hydrogen peroxide with water. Variables I will keep constant: I am going to keep concentration of catalase, temperature and surface area the same. I am not going to change these variables in order to keep the test fair otherwise I wouldn't know which variable it was that caused the rate of reaction to change. Apparatus: Boiling tube rack Boiling tube x 6 Hydrogen peroxide Water Ruler Diagram: Method: 1. Set up apparatus as shown in diagram. 2. Place 3cm� of liver puree in each test tube and record the height of froth in a table. ...read more.

Conclusion

When a successful collision occurs a reaction takes place with turns Hydrogen Peroxide into Water and Oxygen. Evaluation: This investigation was a success and easy to perform and the results collected clearly show an increase in height of froth when the concentration of Hydrogen Peroxide is increased. During the experiment I found that measuring the height of froth slightly harder than expected mainly because of the test-tube rack. I found that I had to either remove the test-tube from the rack to measure it, which meant the froth had time to disperse or I had to measure the height a few centimetres away from the test-tube, meaning if I did not look straight on in front of the test-tube and ruler it could give the illusion of being lower or higher froth than it actually was. Another problem is that glass is well known to distort light and therefore any measurements I was taking may not have been accurate because the froth could be at a different height than it appears. There doesn't appear to be an anomalous result on my graph. I know this because my line of best fit roughly goes through all of the points. ...read more.

The above preview is unformatted text

This student written piece of work is one of many that can be found in our AS and A Level Molecules & Cells section.

Found what you're looking for?

  • Start learning 29% faster today
  • 150,000+ documents available
  • Just £6.99 a month

Not the one? Search for your essay title...
  • Join over 1.2 million students every month
  • Accelerate your learning by 29%
  • Unlimited access from just £6.99 per month

See related essaysSee related essays

Related AS and A Level Molecules & Cells essays

  1. Investigate how concentration of the enzyme catalase in celery tissue alters the rate of ...

    (viii) Gradient of line between 1 and 2 minutes for 100% Celery Extract concentration = 0.8 cm3 9.75 seconds = 0.082051282 = 0.0821 cm3/sec (3 sig. fig) For example, compare (i) to (viii), the rate of the reaction decreases to 0.0821 cm3/sec from 0.222cm3/sec.

  2. To investigate the rate at which hydrogen peroxide is broken down by the enzyme ...

    7.5 7.0 6.5 7.0 3.0 2.5 2.5 2.7 50 8.5 8.5 8.0 8.3 3.5 3.5 3.0 3.3 60 9.5 9.5 9.0 9.3 3.5 3.5 3.5 3.5 Analysis: My initial thoughts on my results are that they seem to fit my predictions quite accurately.

  1. Reaction of Catalase and Hydrogen Peroxide

    Mechanism Of Enzyme Action Enzymes are thought to operate on a lock and key mechanism. In the same way that a key fits a lock very precisely, so the substrate fits accurately into the active site of the enzyme molecule.

  2. Investigating the effect of the Temperature on the Enzyme Catalase when it reacts with ...

    I can tell that the oxygen was formed because bubbles were given off when the catalase reacted with the hydrogen peroxide. As I drop the filter paper into the hydrogen peroxide solution, the filter paper sinks to the bottom of the hydrogen peroxide forming oxygen.

  1. The effect of Copper Sulphate concentration on Catalase activity on Hydrogen Peroxide.

    enzyme but tend to remain bound without change, blocking access by the normal substrate. As a result, the rate of the reaction slows. If the concentration of the inhibitor becomes high enough, the reaction may stop completely. Inhibition of this type is called competitive because the inhibitor competes with the normal substrate for binding to the active site.

  2. Catalyse Investigation

    Leaf peroxisomes are important in the process of photorespiration in which they are part of the photorespiratory pathway involving (obviously) chloroplasts and mitochondria, the three organelles often being in close proximity within the cell.

  1. An Investigation on the Effect of Enzyme Concentration on rate of hydrogen peroxide breakdown.

    As a result, there will be twice as many active sites available, twice as many substrates can undergo reaction at any one time and therefore the volume of O2 produced should double i.e. the rate of reaction doubles. To represent direct proportionality between enzyme concentration and rate of reaction/ O2

  2. I am going to investigate the rate of reaction between catalase and hydrogen peroxide.

    The active site is where the substrate (`key') binds and the chemical reaction takes place. But if their shapes do not fit correctly then they do not bind. This could also occur if the enzyme collides with the substrate in the wrong position.

  • Over 160,000 pieces
    of student written work
  • Annotated by
    experienced teachers
  • Ideas and feedback to
    improve your own work