• Join over 1.2 million students every month
  • Accelerate your learning by 29%
  • Unlimited access from just £6.99 per month

Centripetal Motion

Extracts from this document...


Centripetal motion The aim of the experiment was to test the formula F= (mv2))/r to see if it works. During this experiment results will be collected and analysed to answer the aim. Method In this experiment a bung was attached to the end of a string and the string threaded through a hollow glass cylinder with a weight that can be incremented or decremented attached at the other end. The person carrying out the experiment would then hold onto the glass cylinder and swing the bung around making sure that the radius, or length of string that is in rotation with the bung, is constant thus requiring a specific force. As part of this experiment the weight was varied, which would in turn vary the force needed to keep the bung in circulation and at a constant speed while keeping the radius the same. ...read more.


7.89 7.84 7.74 7.823333 61.20454 Bung mass/g Radius/m 13.6 0.3 Mass/kg Time to turn 10 times 0.02 8.88 0.012682 0.03 7.4 0.018262 0.04 6.78 0.021754 0.05 6.22 0.025848 0.06 5.28 0.03587 0.07 4.69 0.045463 0.08 4.5 0.049383 Graphs From looking at the graphs it can be seen that a trend line can be plotted fairly easily through the points which demonstrates that relationships in each case are fairly strong. I can infer from these graphs that they shall be fairly useful in demonstrating whether the relationship of F= (mv2))/r is true as it shall allow us to compare values obtained from the gradients of the graphs above to the values calculated by the formula in this case. Analysis Mg=F = (mv2)/r = (m4?2r2)/rt2 = (m4?2r)/t2 For the 1 over t2 against mass graph: the gradient = (Ff + Mg) / (4?2m) which can be related the equation of a straight line y = mx + c or more importantly the gradient of the line of best fit. ...read more.


= 0.018 0.018 is fairly close the gradient of the graph 1 over t2 against mass which is 0.0152. Using a different formula 4*?2*m*r and comparing it to the value of gradient for the first graph, period squared against radius, one should get a similar value. 4* ?2*0.136*0.3 =1.61 which is relatively close to 1.26. Summary From the results I was able to find that values of gradients from the graphs were in fact relatively similar to those that could be found using the different formulas. However it can be observed that somewhere in the results/working one is a factor or ten out; however it does not seem that obvious to one who has looked hard as to where that discrepancy is and how it can be fixed. Overall it could be said that the experiment was a success in proving that the relationship F= (mv2))/r is true. This can be said from looking the proportional relationships displayed on the graphs and the similarities of the gradients of the graphs and the values calculated from the formulas. ?? ?? ?? ?? Josh Hargreaves ...read more.

The above preview is unformatted text

This student written piece of work is one of many that can be found in our AS and A Level Fields & Forces section.

Found what you're looking for?

  • Start learning 29% faster today
  • 150,000+ documents available
  • Just £6.99 a month

Not the one? Search for your essay title...
  • Join over 1.2 million students every month
  • Accelerate your learning by 29%
  • Unlimited access from just £6.99 per month

See related essaysSee related essays

Related AS and A Level Fields & Forces essays

  1. Investigating the relationship of projectile range and projectile motion using a ski jump.

    I will use a meter ruler stating centimetres and millimetres to measure the height of the ramp from the table to the point of launch and measure the range between the table and the point at which the ball baring contacted the ground.

  2. What are the physical quantities that affect the value of centripetal force when a ...

    that affect the value of centripetal force when a body in circular motion? Since T=m?2L , L =r/sin? the centripetal force is affected by mass of the object , angular velocity ,the r between the centre of the circle and the object and the?

  1. Centripetal motion experiment. Objective To study the relationship between the angular speed and ...

    After eliminating those errors, we can get a result approximately to the theorectical result. From Figure b, we can also know that the higher the angular speed, the higher the tension. Since the nylon spread is assumed to be on a horizontal plane, so the centripetal force equals to the tension.

  2. Experiment test for F = m2L by whirling a rubber bung (centripetal force)

    As the diagram shown below. where ? is the angle made by the nylon string with the vertical 7. The rubber bung was required to whirl 50 complete circles. The time required for performing 50 complete circles = t The period of one circular motion (T)

  1. Force of friction

    Maximum uncertainty in slope Maximum uncertainty in slope Thus, slope y-intercept ?The coefficient of kinetic friction was found to be . C. Contact surface area Number of blocks 2 3 4 Pile up Side by side Pile up Side by side Pile up Side by side Applied Force F /N (Kinetic friction )

  2. Nonrelativistic string equation

    This is why a guitar string makes a higher note when it is tightened. But that's for a nonrelativistic string, one with a wave velocity much smaller than the speed of light. How do we write the equation for a relativistic string?

  • Over 160,000 pieces
    of student written work
  • Annotated by
    experienced teachers
  • Ideas and feedback to
    improve your own work