• Join over 1.2 million students every month
  • Accelerate your learning by 29%
  • Unlimited access from just £6.99 per month

chemistry limewater experiment

Extracts from this document...


Chemistry-AS-Assessed Practical (Skills P and A) The aim of this experiment is to determine the concentration of limewater, in g dm-3, as accurately as possible using hydrochloric acid, HCl. In the experiment the hydrochloric acid must be diluted and then a titration can be done to find the concentration of limewater. The hydrochloric acid must be diluted as its concentration is too high. The concentration of the hydrochloric acid is exactly 2.00 mol dm-3 but it has to be to a similar concentration a calcium hydroxide so the titration can be done. The first step is to dilute the HCl and then the second step is to perform titration of the calcium hydroxide. The equation: 2HCl + Ca(OH)2 � CaCl2 + 2H20 This equation is a neutralisation reaction and will be used for the titration so the HCl that will be added to the limewater, that contains calcium hydroxide, will be neutralised. Equipments Burette- For measuring HCl as it is accurate. It can measure to 0.05cm3. Conical flask- For solutions to react in. ...read more.


The concentration for the HCl is 2molar, this makes it an irritant so you have to be careful when using it and make sure you are wearing eye protection, gloves and a lab coat. Ca(OH) 2 is also an irritant so precautions should be taken when dealing with it such as wearing eye protection, gloves and a lab coat. Quantities and concentration of reagents used In the experiment 250cm3 of limewater is provided which contains approximately 1dm-3 . With the information you can work out the concentration of limewater(Ca(OH)2. The relative molecular mass, Mr, of (Ca(OH)2) = 40 + 2(16 + 1) = 74 Then you use moles = mass / Mr which gives you 1 / 74 = 0.0135 mol dm-3 The HCL has a concentration of 2 mol dm-3 which is too high and has to be diluted to around 0.02 mol dm-3 so it is similar to the concentration of limewater so it can be neutralised in the titration. . Method Diluting the acid 1. ...read more.


6. Shake the beaker constantly so the reaction can take place. 7. Stop when the solution turns yellow as this is the point of where the calcium hydroxide is neutralised. 8. The value of HCl should be noted down as this can be used to work out the concentration of calcium hydroxide. 9. Repeat the experiment until three concordant values is produced. The average of the results produced can then be used to work out the concentration of the limewater. This is done by firstly working out the moles of HCl by, Moles = concentration / volume This gives, Moles = 2/volume of HCl acid used This gives you the moles of HCL used so this will allow you to do the calculations to work out the number of moles of calcium hydroxide which is, Moles of HCl / 2 = Moles of calcium hydroxide The mole of calcium hydroxide can be used with the volume of calcium hydroxide used to find the concentration using, Concentration = moles / volume To convert the mol dm-3 to gdm-3 , you have to multiply by the molar mass. Sources 1. CGP AS-Level Chemistry The Revision Guide pg18 2. Cambridge Advanced Sciences Chemistry 1 book pg25-28 ?? ?? ?? ?? ...read more.

The above preview is unformatted text

This student written piece of work is one of many that can be found in our AS and A Level Inorganic Chemistry section.

Found what you're looking for?

  • Start learning 29% faster today
  • 150,000+ documents available
  • Just £6.99 a month

Not the one? Search for your essay title...
  • Join over 1.2 million students every month
  • Accelerate your learning by 29%
  • Unlimited access from just £6.99 per month

See related essaysSee related essays

Related AS and A Level Inorganic Chemistry essays

  1. Peer reviewed

    Determining the concentration of acid in a given solution

    5 star(s)

    when I finished 'Titration 4' as I had 3 results within 0.1cm3. Analysis 8 The average titre is: (( 24.55 + 24.60 + 24.60 ) / 3 ) = 24.58cm3 I will round this up to 24.6cm3 as this is accurate to 3 significant figure.

  2. Peer reviewed

    Deducing the quantity of acid in a solution

    5 star(s)

    14 Procedure First of all, we rinse out the burette and the funnel with H2SO4 and the pipette filler and the conical flask with Na2CO3. This ensures us that the equipment is less contaminated and therefore, it is going to be more precise when reaching the endpoint.

  1. effects Concentration and Temperature on the Rate of Reaction

    n/a Beakers Used for reaction to take place in. 250ml White tile Allows easy observation of colour change against a white background. n/a Magnetic stirrer Allows me to concentrate on observing the colour change alone, rather than having to conduct stirring and observe colour change at the same time.

  2. The Chemistry oh Phosphorous

    smoke, and it also reacts with the air to form phosphoric acid, which is one of the main reason for its usage as a weapon. Once ignited, it will then continue to burn until deprived of oxygen or the reagent is used up.

  1. Scientific Practical Techniques

    Other thing that can improve the investigation using new measurement metre, as the old one has been used for so many years. 4) Looking at a growing yeast culture at 30 degree 1) The instruments I chose for this investigation are microscope, which helps to distinguish tiny object that can

  2. Determination of the solubility of calcium hydroxide

    This ensures that there is exactly 25cm-3 of the hydrochloric acid in the pipette, and that an accurate concentration of 0. 03moldm-3 will be produced. 4. I then add this into a clean and dry volumetric flask, wash it with distilled water and allow it to dry if it is not clean.

  1. The Effects of Strong and Weak Acids on the Order of a Reaction.

    The values on the syringe need to be shown clearly so that you can measure the amount of gas produced when the experiment is up and running. 3) Spiral the Magnesium Ribbon pieces around a pencil and do the same for the other pieces.

  2. Fission and Fusion (Open Book paper 2008)

    route, the nuclei fuse, simply adding together the protons and the neutrons together to form a larger nucleus. However, the second reaction of the second route is more complicated. The negative electron joins with one of the positive protons in beryllium-7, forming a neutron, [7] in a way that can be thought of as the reverse of beta-decay.

  • Over 160,000 pieces
    of student written work
  • Annotated by
    experienced teachers
  • Ideas and feedback to
    improve your own work