I aim at 30 cm³ volume of gas, so I can ensure all gas is measured.
Thus, if 1 mole of copper carbonate produces 24360 cm³ of CO2, to produce 30 cm³ we need:
- number of moles = volume cm³/24360 cm³
= 30 cm³ /24360 cm³
= 0.0012315271 moles of gas
- Mr of CuCO3 = 63.5+12+(3*16)= 123.5
- Mass= moles* Mr = 0.0012315271 moles* 123.5 =0.1520935969 g =0.15 g ( 2 d.p.) of CuCO3
With equation 2 0,15g of CuCO3 will result in 30 cm³ gas.
I now calculate the expected volume of gas given equation one is correct:
Equation 1: 2 CuCO3 (s) ------------------------------> Cu2O (s) + 2 CO2 (g) + ½ O2 (g)
- The molar ratio in equation one is 2:2.5
- number of moles = mass/Mr
= 0.1520935969 g /123.5 = 0.0012315271 moles of copper carbonate
- 0.0012315271 moles * 1.25= 0.0015394089 moles of gas
---> to find moles of gas I multiply moles of CuCO3 by 1.25, as 2.5/2 = 1.25.
- 0.0015394089 moles * 24360 cm³ = 37.5 cm³
At 20°C, 100kPa the two possible results are 30 and 37.5 cm³ respectively.
Fair test/ Sources of Error
- copper carbonate has to be weighed out exactly to two decimal places
- bung has to be inserted tightly into test tube before the reaction occurs
- ensure that delivery tube is underneath burette and that burette is vertical
- do not stop reaction as long as bubbles are created
- wait circa 10 min (gas to reach room temperature) after ending of reaction to measure gas evolved
- ensure that there are no air bubbles in the burette
- perform experiment accordingly without CuCO3 and measure collected gas. This volume is to be deducted from the actual results (temperature effect)
- ensure that all copper carbonate has been fully decomposed (colour change)
- precise reading for temperature and air pressure
Variables
controlled variables:
- the pressure of the room, to measure with a barometer for the final calculation.
- the temperature. An increase in temperature may cause an increase in the volume of gas given out by the expansion of the air.
- degree of decomposition of copper carbonate. The green copper carbonate has to turn black completely and has to be heated evenly(heating time).
Dependent variable:
Independent variable
Risk assessment
- copper carbonate is toxic and it can irritate lungs and eyes
- copper(1)oxide is harmful if swallowed and can irritate lungs and eyes
- carbon dioxide has a low hazard symbol. It is asphyxiate and lowers the oxygen content of the air.
- use the Bunsen burner careful and turn on safety flame when not in use
- wear goggles and lab coat all the time.
- when something is spoiled it should be rinsed up immediately
Apparatus list
- 1 Bunsen burner for heating
- 1 test tube, good for small weighted sample and, only little air enclosed
- 1 delivery tube to deliver gas to burette
- 1 pair of goggles for safety
- 2 clamp stands for holding test tube and burette
- 1 50 cm³ burette, accurate to 0.05 cm³, used to collect the evolved gas
- 1 heat mat underneath Bunsen burner
- 1 bung to close test tube, leak proofed
- 1 spatula to deliver CuCO3
- 1 top pan balance, accurate to 0.005g , is used to weigh copper carbonate
- 1 100 cm³ beaker, container to keep end of burette under water
- 1 Thermometer for correct measurement of temperature
- barometer (not available)
Sketch
Method
- wear goggles and lab coat. Pin hair up
- collect all apparatus in front of you
- set up apparatus as shown in the sketch above
- put a piece of paper on the top ban balance and reset the scale
- put copper carbonate with a spatula onto the piece of paper and weigh exactly 0.15g
- transfer CuCO3 into middle of test tube and insert the bung tightly (no air gaps)
- measure temperature
- begin heating powder gently with Bunsen burner
- gas is led into vertical burette
- when no more gas bubbles are formed, lift end of delivery tube out of water and stop heating
- after 10 minutes read and note exactly volume of gas (reading minus 50 cm³) (2 d.p.)
- repeat experiment three times
- work out average volume of gas evolved
The volume of gas is temperature and pressure dependent. Therefore you have to use a barometer (not available at school) and a thermometer to calculate the correct volume. I reduce the temperature effect of the heated gas by waiting 10 minutes before measuring it.
General gas equation
P*V= n*R*T
P= Pressure
V= Volume
n=moles of gas
R= gas constant =8.314 J k?' mol?'
T= temperature
Example calculation:
P*V=n*R*T
V= (n*R*T)/P
= (1 mol*8.314J k?' mol?' *293 kelvin)/100kPa
= 24.36 dm³ at 20 °C and 100kPa pressure
After calculating an average volume of gas produced you can compare this with the theoretical results of 30 cm³ for equation two and 37.5 cm³ for equation one. As mentioned above I predict equation 2 to be correct, thus 30 cm³, or closest to this, of gas should be measured. Due to the small amount of reactants already small deviations in measurement of weight, temperature and pressure could, when added up, show a certain margin of error. Thus more accurate tools (e.g. analytical balance), increased mass of reactants and standardized heating will improve accuracy of results.
Alternatively use gravimetric measurement of CuCO3 and CuO respectively.
Bibliography
- Hazcard references from the school laboratory
- www.wikipedia.org/wiki/copper%28
- Advanced Chemistry by Michael Clugston and Rosalind Flemming, page 114-122
- Holleman- Wiberg, Lehrbuch der Anorganischen Chemie, page 784-796
- Hans Rudolf Christen, Chemie, page 147-150