Determination of dissolved oxygen in a water sample (Winkler Method)

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V6 Determination of dissolved oxygen in a water sample (Winkler Method)

Objective

To find out the oxygen content of a water sample by adding MnSO4 and alkaline KI into the solution. Mn2+ was oxidized into Mn3+. Then Mn3+ was reduced back into Mn2+ and I- was oxidized to I2. The solution was titrated against sodium thiosulphate solution and the oxygen content could be calculated.

Result

Calculation

No of moles of Na2S2O3 used =

2S2O32- + I2 → S4O62- + 2I-

No. of moles of I2 in 100 cm3 solution =  = 1.1825

2Mn(OH)3 + 2I- + 6H+ →I2 + 2Mn2+ + 6H2O

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No. of moles of Mn(OH)3 in 100 cm3 solution = 1.1825 X 2 = 2.365

4 Mn(OH)2 + O2 + 2 H2O → 4 Mn(OH)3

No. of moles of O2 in 100 cm3 solution = 2.365

Oxygen content = 18.92 mg dm-3


Discussion

Reason of filling the whole volumetric flask

During the experiment, the water sample was allowed to fill with the whole volumetric flask, this is because we have to prevent oxygen from dissolving from the air into the water sample.

Reason of using a magnetic stirrer

When conducting the experiment, insoluble manganese (III) hydroxide was formed. It would dissolve in potassium iodide ...

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