Find how changing the amount of voltage (potential difference) coming out of the power pack will affect the current while it is flowing through a filament bulb of 24W.

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Physics Coursework

Filament Bulbs

Aim:

My aim is to find how changing the amount of voltage (potential difference) coming out of the power pack will affect the current while it is flowing through a filament bulb of 24W.

Diagram:

The power pack supplies a direct current (DC) to the circuit. The voltmeter is in parallel to measure the potential difference across the bulb and the ammeter is in series to measure the current flowing through the circuit.

Method:

  1. Get all the equipment and set it up as shown in the diagram.
  2. Set power pack so that the voltage shows 10V on the voltmeter.
  3. Record the number of amps that are flowing through the circuit by reading the ammeter.
  4. Repeat steps 2 + 3 for 20, 30, 40 and 50 Volts.
  5. Repeat the steps 2 through 4 two more times to get three sets of results. Make an average and this leaves you with a set of good, accurate results.

Fair Test:

To make my experiment a fair test I will have to make sure I keep many things the same. First of all, the power pack; I will have to use the same power pack for each test as they will all give out slightly varied voltages to each other. I will also have to use the voltmeter to judge how much voltage is coming out as the power pack dial is more than likely inaccurate. In addition, I must use the same light bulb as each bulb will have a slightly different resistance, therefore giving us a different current reading. I will also need to keep the same volt meter and ammeter as they will vary in sensitivity. Finally, I will keep the wires the same as (like the bulb) they will have slightly different resistance values.

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Key Variables:

        The key variables that could alter my results are the equipment and atmospheric conditions. The temperature of the room and bulb will affect my final results, as temperature affects the resistance of a component. The hotter the component, the higher the resistance. Broken links (for example broken wires) will drastically change my results as the circuit will not even work.

Prediction:

        My prediction for my experiment is that the higher the current is, the higher the voltage will be.

Ohms law states that:

V (voltage) = I (current) x R (resistance)

This means ...

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