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# Find out what the cell strength of a potato is.

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Introduction

Aim: In my investigation I intend to find out what the cell strength of a potato is. Factors: The factors which I am going to change in my investigation are the strength of the solution. The investigation: In order to make it a fair test I am going to only change one factor which is the strength of the solution. The factors which I am going to keep the same are; the size of the chips, the weight of the chips, the same amount of liquid and how long we keep the chips in the solution for. My prediction I think that in my investigation the chips in the dilute (Hypotonic) solutions will increase in weight and be much more firm and rigid. Although the chips in the concentrated (Hypertonic) solution will become flimsy and smoother and weigh less. I think this because osmosis will occur which is when the water inside the test tube goes to a level of lower concentration which would be in the cell vacuole. This would cause the cell to become turgid and gain weight in the hypotonic solution but in the hypertonic solution the water inside the vacuole will go out as it will go to an area of lower concentration, this would cause the chips to decrease in weight. ...read more.

Middle

* Next I filled up 6 test tubes with the different types of molar solution. The solutions ranged from 0molar, 0.2molars, 0.4molars, 0.6molars, 0.8molars and 1.0 molar. I labelled each test tube so I didn't get confused. * I then cut 12 chips out from the potato, these were long and thin as I mentioned earlier because of the preliminary test. I then weighed them and they were approximately 2.8g in weight. * I then put two chips in each test tube as this would ensure the results are more reliable. * We put them in a test tube rack and left them over night until the next lesson. * Finally I removed all the chips and weighed them separately. I then recorded all my results and calculated the increase or decrease in weight and drew the results up on a graph to find out where the isotonic point is. My results Molar of solution Weight before test Weight after test Increase or decrease in percentage 0 2.8g 2.8g 3.0g 3.4g 14.3% increase 0.2 2.8g 2.8g 3.0g 2.9g 5.4% increase 0.4 2.8g 2.8g 2.5g 2.5g 10.7% decrease 0.6 2.8g 2.8g 2.2g 2.5g 16.1% decrease 0.8 2.4g 2.4g 1.8g 1.8g 25% decrease 1.0 2.6g 2.6g 1.8g 1.8g 30.8% decrease My graph is on a separate sheet and reveals 2 anomalous results. ...read more.

Conclusion

They should be able to fit into the lines of best fit. I think these anomalies might have occurred because I cut the sizes different although they were the same weight and long and thin. Or they might be because of two of the chips were the wrong weights. If I had to use my results as evidence then I think they give a great example of osmosis occurring and water entering and leaving the vacuole and that in different types of solutions cells can become turgid or flaccid. The reason I think this is because my results fit with osmosis and show that in a dilute solution the chip will get bigger as water enters the vacuole as it is of a lower concentration but in a concentrated solution the chips shrink as water leaves the vacuole to go to a place of lower concentration. If I did my investigation again I would improve it by being as accurate as I can in cutting my chips and make sure they are long, thin, the same size and the same weight and if I did this then I think I wouldn't get any anomalous and therefore my results would be reliable and perfect. In order to try and get further evidence I would try different types of food instead of chips like peas, bits of apples or carrots. ...read more.

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