How varying surface area affect rate of reaction - plan

Authors Avatar

        

Aim:

       The aim of this investigation is to investigate how varying surface area affects the rate of reaction (amount of Oxygen produced).

The hypothesis being tested is ‘an increase in the catalyses surface area causes the rate of Oxygen production to increase (rate of reaction).’

     In order to test this hypothesis, the substrate Hydrogen Peroxide and enzyme catalase in potato will be used. The substrate concentration will be kept constant whilst, the catalyses surface area will be varied, by changing the surface area of the potatoes. The rate of reaction used can be represented by measuring the volume of oxygen produced in a fixed period of time.

Prediction:

       I predict that an increase in surface area of potato, whilst the hydrogen peroxide concentration is kept constant will result in an increase in the amount of oxygen produced.

     

 

       The scientific reasoning behind the prediction is, as the surface area of the solid increases there is more solid available for the enzyme to react with, therefore causing an increase in the rate of reaction. The more solid substrate there is readily available, the more active sites on the enzymes can be occupied, implying frequency of reactions taking place to increase.  Fig 5.1 shows how the enzyme  molecule has a active site which combines with the substrate molecule to produce a combined enzyme substrate molecule complex. Enzymes are denatured by high temperatures so it is essential that the temperature remains constant and a reasonable amount (room temp)

Join now!

     

 Only a specific fraction of all total collisions cause chemical changes called fruitful collision. The fruitful collisions have enough energy at the moment of impact to break the existing bonds and form new bonds. This will cause the H-O bonds in the hydrogen peroxide to break down leaving water (O²) and produce Oxygen (H²O) This process  has a ΔHo of −98.2 kJ/mol and a ΔGo of −119.2 kJ/mol. This is the symbol equation of the reaction producing oxygen:

2 H2O2 → 2 H2O + O2 + Energy

   

  The rate of decomposition is dependent on the temperature and ...

This is a preview of the whole essay