Investigate the reaction of the enzyme catalase with the metabolic poison hydrogen peroxide, and a factor affecting the rate of the reaction.

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I intend to investigate the reaction of the enzyme catalase with the metabolic poison hydrogen peroxide, and a factor affecting the rate of the reaction.

There are 6 variables that may affect the rate of the reaction. They are:

  1. concentration of enzyme
  2. concentration of hydrogen peroxide
  3. temperature conditions of reaction
  4. pressure conditions of reaction
  5. pH conditions of reaction
  6. physical state of solid substrates (e.g. surface area of particles)

I intend to investigate the effects on the reaction rate upon altering the concentration of the enzyme.

In order to do this while also ensuring a fair test, I shall aim to maintain all other latent variables constant.

PREDICTIONS:

I expect that the time taken to evolve a set volume of gas will decrease as the concentration increases. This, in other words, means that to increase the concentration, will increase the rate of the reaction.

I would expect that if the concentration is doubled, so too is the rate of the reaction:

Rate of reaction  concentration

JUSTIFICATION:

Enzyme molecules have a very specific method of converting those molecules upon which they work (the substrate molecules).

Enzyme molecules are proteins that act as biological catalysts, so they are not themselves used up when converting substrate molecules. On every enzyme molecule is an active site where the substrate molecules are joined to the enzyme molecule, and converted to product molecules.

Every enzyme is specifically shaped to fit the substrate upon which it works, and therefore they do not work in conditions that denature the molecules (e.g. very high temperatures).

The graph  shows how rates are affected by substrate and enzyme concentrations.
 

The equation below shows the reaction that takes place when catalase is added to hydrogen peroxide.

Hydrogen peroxide  water + oxygen

2H2O2  2H2O + O2 

Enzyme catalase

The equation and graph show some of the science behind the reaction that will take place in the experiment I shall do.

The red annotations on the graph show that at a fixed substrate (hydrogen peroxide in this case) concentration, the rate of reaction (time-1) is higher for the enzyme at concentration y than for the enzyme at concentration x. The reason for this is because the enzyme at concentration y contains more molecules than the enzyme at concentration x. There are therefore more collisions taking place between substrate and enzyme molecules, and subsequently the rate of reaction increases. This is known as the Collision Theory.

METHOD:

Apparatus:

Retort stand, Boss, Clamp, Boiling tube, small 100cm3 beaker, syringes (1ml and 5ml), 2 50ml measuring cylinders, stopwatch, water bath, delivery tube with bung, mortar and pestle, electronic weighing scales, 10 vol. hydrogen peroxide, liver [contains enzyme catalase], water, sand

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Procedure:

  1. I will set up the apparatus shown above.
  2. Using the electronic weighing scale, I shall weigh 10g of liver.
  3. Using the mortar and pestle, I will grind the liver with 20ml of water (measured using one of the measuring cylinders) and a pinch of sand (this helps the grinding process to work).
  4. When the enzyme is ground into a solution, I will pour it from the mortar into the 100ml beaker. [This solution I will use as 100%-concentration liver solution, even though some water has been added for grinding purposes.]
  5. I will ...

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