Investigating how the length of a Wire affects its resistance.

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By Logan Jayabalan 11Br Set 10.5

Investigating how the length of a Wire affects its resistance.

Aim : The aim of this investigation is to find out how the resistance of wire is affected by its length.

Hypothesis : I predict that when the length of a wire is increased, its resistance will also increase. I also think that the rate at which the resistance increases will be constant and directly proportional to the length.

References to books and the internet have been made to support the prediction:

“…However, the electron does not accelerate for ever. Eventually, it crashes into one of the atoms in the wire. Since atoms are far more massive than electrons, the electron loses all forward momentum every time it hits an atom (just as we would lose all forward momentum if we ran into a brick wall).. Immediately after the electron hits an atom its forward velocity is zero. The electron is then accelerated by [the battery]…” from the website: http://farside.ph.utexas.edu/~rfitzp/teaching/302l/lectures/node42.html

We can conclude from this that the longer the piece of wire is, the more chance there is of the electron colliding with other atoms. The more collisions that happen, the more resistive the piece of wire is. This text quoted from the science journal confirms this.

“Resistance is caused by electrons bumping into ions. If the length of the wire is doubled, the electrons bump into twice as many ions so there will be twice as much resistance. So

If the cross-sectional area of the wire doubles there will be twice as many ions and twice as many electrons bumping into them, but also twice as many electrons getting through twice as many gaps. If there are twice as many electrons getting through, as there is twice the current, the resistance must have halved. This means that              ” from the website : http://www.sci-journal.org/vol1no1/v1n1k42.htm

The Scientific reason why more wire means more resistance can be complicated. Basically, knowledge about structure of atoms is needed to fully explain this. Resistance of wire based on its cross sectional area will be hypothesised and scientifically proven with theory first to help clarify why increasing the length of wire also increases its resistance.

An Atom is made up of a comparatively large nucleus surrounded by shells of electrons. In a metal, these electrons are free to move around. A battery or power supply provides EMF or Electromotive Force. This repels the negatively charged electrons away from the negative terminal and towards the positive. The positively charged nucleuses stay where they are, however, they are still being attracted to the negative terminal.

The electrons have to pass through the gaps in the stationary nucleuses in order to get to the positive terminal and enable electricity to flow. In doing so, they sometimes collide with the nuclei on the way. This slows down their overall speed. In a given time, it cannot go as far. It also impedes the flow of other electrons. This is called resistance. Less electrons (and thus current) can pass through the wire.         The electron that has hit the nucleus is holding up other electrons as well as blocking a passage which electrons can take to get to the positive terminal. This means that fewer electrons can flow through the material.

It can be concluded that thinner wire has less spaces as there are less nuclei. This greatly increases the probability of a collision (or resistance) because there are fewer spaces to go through. The more spaces a wire has (i.e. the thicker it is) the more gaps there are available and the greater number of electrons that can flow with fewer collisions (it will have less resistance). Basically, thinner wires will have larger resistance than thicker wires, which will allow larger current flows.

When an electron collides with a nucleus (as stated in the first quote) it will lose all kinetic energy only to be speeded up by the battery again. This has a negative implication. When an electron hits a nucleus, its kinetic energy is transferred into heat energy. This is witnessed as the wire heating up when it is too thin or when there are too many collisions. When the thickness is increased, this heating effect is lessened greatly. This is because the number of collisions is reduced greatly.

The reason why the heating effect can be increased dramatically with only a small decrease in diameter is because although

(Ecq1) Resistance = k ____1_____              ,   (Ecq2) Resistance = k   ______1_____

                                 Cross-sectional area     ,                                              diameter2

This means that resistance is inversely proportional to cross sectional area squared. When the cross sectional area is decreased, the resistance increases in squares. This is because when the diameter of a wire is increased by 2, the surface area is increased by 4, or 22. This means if a 4 mm wire has a resistance of 8 ohms; a 2 mm wire has a resistance of 32 ohms. Wire diameter is thus very important as it can have varying levels of resistances depending on its width and also regulate the amount of current that can pass through it.

In a similar way, resistance is affected by length of wire. In a longer length of wire, there are more chances for the electron to bump into a nucleus. If a wire of 4 cm has a resistance of 4 ohm, then in an 8 cm wire, it would be expected to have a resistance of 8 ohms. This is because if the length is doubled, there are twice as many chances for the electrons to bump into a nucleus. Because the resistance is how the material resists the flow of electrons, a twofold increase in length would mean two times as many nuclei to bump into which would also increase the resistance by two also. All of these factors give rise to the formula:

(Ecq3)      

Resistance of conductor (R) = Resistivity of Material in Ohm-meters × length (m)

                                                               Cross Sectional Area in (m2)

The fact that the diameter is squared to give the cross sectional area confirms that equation (ecq) 2 is correct and that the cross sectional area and/or area squared is directly proportional to resistance.

        Equation 3 will be tested using test values to confirm my hypothesis.

Test values: resistivity of wire = resistivity of constantan = 2.8

Diameter = 0.05m = 5 cm

Length of the wire doubled.

__2.8_×_4m____ = 224 ohms                   __2.8_×_8m____ = 448 ohms

       0.05                                                            0.05

                   

This confirms that my hypothesis is correct as the equation confirms that doubling the length doubles the resistance when all other factors are kept the same.

The same equation can be used to check whether doubling the cross sectional area halves the resistance

___2.8_×_4m___                                                     ___2.8_×_4m____

           0.05          = 224 ohms                                              0.10             = 112 ohms

This confirms that when you double the cross-sectional area, the resistance halves. This is important in proving my hypothesis correct because if we know and can prove that changing certain values can change the way wire behaves, then we know that keeping it constant will decrease the amount of anomalous results and help prove my hypothesis correct.

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For this reason, it is important to clarify what changing certain values will do to results, if only in theory. Changing the cross-sectional area and/or length will cause the resistance to vary. Length is what will be examined during the course of this investigation. Cross-sectional area is to be decided upon in some sort of preliminary experiment. As has already been explained, the smaller the piece of wire, the higher the resistance. As resistance causes heating, smaller wires will heat up more and more quickly depending on the current/electrons flowing through them. Cross-sectional area needs to be balanced between ...

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