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Investigating the effect of one variable on the rate of an enzyme reaction.

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Introduction

Investigating the effect of one variable on the rate of an enzyme reaction. Aim The aim of the experiment is to find out how the level of hydrogen peroxide which is the substicute for catalose, effects the rate of reaction when mixed with 5cm3 of yeast. So my aim is going to be, to measure the amount of oxygen given off when the two react, to come to a conclusion of what effect does the amount of hydrogen peroxide have on the yeast (catalase). Prediction Hydrogen Peroxide catalase water + oxygen 2H2o2 2H20 O2 This is the reaction that is being investigated to find out how the concentration of hydrogen peroxide affects the rate of reaction if at all. In this reaction between hydrogen peroxide and the catalase the compounds of water (2H2o) and oxygen (02) are given off, which I will measure to come to this conclusion. The way hydrogen peroxide and the catalase react is through the collision theory, which will now be explained. The yeast cell has many enzymes but it is only the catalase inside the yeast, which is capable of breaking down the hydrogen peroxide, this is because this enzyme is specific for hydrogen peroxide. ...read more.

Middle

For the experiment to work you must firstly pour water into the 100cm3 cylinder and turn it upside down ready to lose oxygen if my prediction is correct. Then you must pour 15cm3 of 100% H202 into the test tube, and as soon as 5cm3 of yeast is added and the lid is put on the timer will be started. Then every 30 seconds a result will be taken of how much oxygen has been lost from the measuring cylinder, this happens as the oxygen pushes out the water from the reaction between the catalyse and the hydrogen peroxide. This will then complete the experiment after 180 seconds are gone and the results can be examined to be out into a results chart graph, and a conclusion to this. Results Analysing the evidence The results show that any given variable of Hydrogen Peroxide will make the enzyme react. And the more concentration of hydrogen peroxide the faster rate of oxygen is given off in a chemical reaction. The trend that I can see in my results shows that with the concentration of acid at its strongest, the oxygen is given off at a rate, which is fast, but not a consistent amount each 30 seconds. ...read more.

Conclusion

Overall though the experiment has been very successful with the question of how does one variable affect an enzyme reaction being answered, with the answer of it reacting with H202 to give off oxygen and water. And further work shows that the higher the concentration of H202 the faster the amount that oxygen is given off to end this investigation. Apparatus The equipment needed for this experiment is. X 1 100cm3 cylinder (measure) X 1 a Bunsen burner tubing X 1 water bath X 1 test tube Method Set up the experiment as shown in the diagram. For the experiment to work us must firstly pour water into the 100cm3 cylinder and turn it upside down ready to lose oxygen if my prediction is correct. Then you must pour 15cm3 of 100% H2O2 into the test tube, and as soon as 5cm3 of yeast is added and lid is put on the timer will then be started. Then every 30 seconds a result will be taken of how much oxygen has been lost from the measuring cylinder, this happens as the oxygen pushes out the water from the reaction between the catalyse and the hydrogen peroxide. This will then complete the experiment after 180 seconds are gone and the results can be examined to be put into result charts graphs and an conclusion to this ...read more.

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