• Join over 1.2 million students every month
  • Accelerate your learning by 29%
  • Unlimited access from just £6.99 per month

Investigating the effect of the substrate concentration on the decomposition of Hydrogen Peroxide by the enzyme catalase.

Extracts from this document...

Introduction

Investigating the effect of the substrate concentration on the decomposition of Hydrogen Peroxide by the enzyme catalase. Planning Aim In this experiment, I am going to investigate how the concentration of hydrogen peroxide will affect the rate of the reaction. I am going to use different concentrations of hydrogen peroxide as my variable and keep the amount of the liver the same. Background knowledge The formula for catalase breaking down hydrogen peroxide is 2H2O2 ------------> 2H2O + O2 Hydrogen Peroxide is a chemical compound of Hydrogen and Oxygen and the formula for this is H2O2. When hydrogen peroxide is anhydrous it is a colourless liquid which is a strong oxidizing agent which is harmful as it can blister the skin. Catalase is an enzyme (a biological catalyst) for the conversion of hydrogen peroxide into water and Oxygen. Catalase is found in every living cell as it prevents build up of hydrogen peroxide and protects body tissue from damage by H202. Catalase is very important as hydrogen peroxide is consistently being made in metabolic reactions which are chemical reactions taking place inside each cell, catalase is found in large quantities in the liver as a lot of metabolic reactions occur here. ...read more.

Middle

Liver As it contains high amounts of catalase to break down the hydrogen peroxide. Hydrogen Peroxide The substrate in different concentrations as the variable of my experiment. Stop watch To time how long my experiment will go on which will be 60 seconds each time. Diagram Method 1) Set up apparatus( should look similar to above except without liver or hydrogen peroxide yet) 2) Weigh 1g of mashed up liver on a top pan balance and then put the liver into the conical flask. 3) Cautiously measure out 50ml of hydrogen peroxide at 0% concentration in a measuring cylinder. 4) Pour this into the conical flask and securely seal the bung immediately within 2 seconds so that gas cannot escape and start the stop watch straight away. 5) Now gently swirl the conical flask at 60 seconds take the reading of the amount of oxygen that has collected in the gas syringe 6) Clean out the conical flask thoroughly and repeat experiment with 5, 10, 15 and 20% concentrations of Hydrogen peroxide. 7) Repeat each concentration 3 times so that you acquire more accurate results. 8) Calculate the average of each concentration and make graphs. 9) Then from your results work out the rate of each reaction. ...read more.

Conclusion

If the temperature increases too much for example over 50 degrees Celsius the active sites on the enzymes will change and become denatured. This will make the break down of hydrogen peroxide stop and will give me bad results. I also presume that when the concentration gets to high there will be a point where the enzymes will be working as fast as they can all active sites will be occupied at all times and as of this they will not be able to work any faster this means enzymes will reach there Vmax( maximum rate of a enzyme). I think my results should make a sloping graph to a point where it will not rise anymore. This is because of factors like enzymes reaching there Vmax. I predict my results will show a positive correlation as higher the concentration the faster the rate of the reaction as more oxygen will be produced. Results Gas produced after 1 minute (cm�) Concentration (%) Test 1 Test 2 Test 3 0% 0 0 0 5% 4 3 5 10% 21 26 32 15% 68 85 91 20% 71 82 84 Concentration Average Gas produced after 1 minute(cm�) 0% 0.0 5% 4.0 10% 26.3 15% 81.3 20% 79.0 Concentration Average rate of reaction (cm�/s) 0% 0.0 5% 0.06 10% 0.44 15% 1.355 20% 1.316 Rate= Average Volume of Gas Time Taken Biology Coursework Page 1 ...read more.

The above preview is unformatted text

This student written piece of work is one of many that can be found in our AS and A Level Molecules & Cells section.

Found what you're looking for?

  • Start learning 29% faster today
  • 150,000+ documents available
  • Just £6.99 a month

Not the one? Search for your essay title...
  • Join over 1.2 million students every month
  • Accelerate your learning by 29%
  • Unlimited access from just £6.99 per month

See related essaysSee related essays

Related AS and A Level Molecules & Cells essays

  1. Marked by a teacher

    Beetroot Practical Write up

    3 star(s)

    The year's results show that this also supports the initial prediction. With the experiments means taken, the calculations of standard deviation could also be taken and compared. The formula used for standard deviation is shown below: The standard deviation indicates the spread of results around the mean and gives an indication of the accuracy of the experiment.

  2. Marked by a teacher

    Enzymes - investigate how the substrate concentration (H2O2) affects the activity of catalase on ...

    3 star(s)

    Therefore there are few successful collisions between substrate molecules and active sites. Few enzyme-substrate complexes are formed and the rate at which the substrate is catalysed is slow. This is also due to their being more active sites then substrate molecules, meaning that all of the active sites are not in use at any one time.

  1. The effect of Copper Sulphate concentration on Catalase activity on Hydrogen Peroxide.

    one in the water bath, the same is carried out with the beaker. This process has to be undergone for a specific length of time, measured by the stopwatch. Hydrogen peroxide solution 20% It is put in a test tube and acclimatised before making it react with catalase.

  2. WHAT EFFECT DOES SUBSTRATE HAVE ON THE RATE OF RESPIRATION IN SACCHAROMYCES CEREVISIAE?

    The substrate, Maltose will cause the saccharomyces cerevisiae solution to produce the next largest volume of CO2 per unit time is maltose. This is a disaccharide made form 2 monomers of glucose that are joined by a glycosidic bond. There are no specific carrier proteins present on the cell membrane

  1. To investigate the rate at which hydrogen peroxide is broken down by the enzyme ...

    This method of measurement is the one I have chosen, because it is quicker and easier to set up and repeat many times in quick succession, which is a real benefit due to only having 100 minutes to finish all my reactions that I plan on investigating.

  2. Investigating the effects of Copper Sulphate on the action of Catalase Enzyme breaking down ...

    the substrate, is not the right shape it will not fit in the lock, which is the enzyme. Finally the interactions between the substrate and active site of the catalase enzymes cause the hydrogen peroxide to break down into two smaller products.

  1. Investigating the effect of the Temperature on the Enzyme Catalase when it reacts with ...

    * The part of the enzyme that reacts with the substrate is known as the active centre or site. It is very important that this part of the enzyme molecule does not change shape.

  2. Investigation on how the temperature affects the activity of the enzyme catalase in the ...

    250cm3Conical flask- this is where the reaction between the hydrogen peroxide solution and enzyme catalase (in potato discs) will take place. Bung with two holes - the bung will be inserted onto the conical flask and sealed tightly so that no oxygen will escape.

  • Over 160,000 pieces
    of student written work
  • Annotated by
    experienced teachers
  • Ideas and feedback to
    improve your own work