• Join over 1.2 million students every month
  • Accelerate your learning by 29%
  • Unlimited access from just £6.99 per month

Investigating the Emf and the internal resistance of a dry cell.

Extracts from this document...

Introduction

Wendy Croft 12NB

Investigating the Emf and the internal

resistance of a dry cell

        The objective of this coursework is to find the Emf of the circuit and the internal resistance of a cell. I am going to use this by measuring the resistance (ohms), current (Amps) and voltage (volts) of a circuit.

        The below diagram shows how I am going to set up my experiment:

Apparatus:   Wires

Switch

Dry cell

Ammeter

Variable Resistor

Voltmeter

By using the variable resistor above, I will measure eleven different readings on an Ammeter and a Voltmeter. I am able to do this as the variable resister measures resistance from 0 to 10 ohms. I will then reverse this procedure by taking the readings from the Voltmeter and the Ammeter when the resistance goes from 10 to 0 ohms. I will do this because by doing this I can view whether or not the original results were reliable. I predict that the results, both ways, will be very close to being the same.

        To make it a fair test, I will make sure that the cell is not left running.

...read more.

Middle

0.23
1.24
5
0.22
1.33
6
0.20
1.55
7
0.18
1.58
8
0.16
1.59
9
0.15
1.60
10
0.14
1.61

From these results in the above table I am going to produce a

y = mx + c graph. From the graph I will calculate the internal resistance and the Emf of the dry cell in my circuit.

On the graph I have plotted the above results, but due to the sensitivity of the meters used there may have been some inaccuracy in the data. Consequently I have drawn error boxes around the results. The size of these is 0.1v big.

By using the error boxes I have been able to also draw on to the graph three lines of best fit: a maximum line, a minimum line and a normal line of best fit. These will enable to do my calculations later on.

As you can see on the graph, there are four anomalous results, these have been highlighted in the results table. These anomalous may have been down to a number of problems: human error when reading the meters, the cell running down and the sensitivity of the meters.

Analysis of results and graph

...read more.

Conclusion

Hence, the maximum line of best fit has the bigger difference.

   Emf = 1.75 – 1.68

                        = 0.07

Therefore the Emf of the dry cell = 1.68    0.07

Conclusion

        Even though not all my results on my graph are in a straight line, like I had previously predicted, you can expect this due to inaccuracies and human errors when reading the meters. Although, by using a line of best fit I could still calculate the Emf and the internal resistance of a dry cell. If you do not take into account the anomalous results then the results are in a straight line.

By using a maximum and minimum line of best fit as well as normal line of best fit I was able to also calculate the error of the results. This made my final calculations even more accurate than if I had just calculated the Emf and the internal resistance by using the y-intercept and the gradient of the normal line of best fit.

As you can see from the graph the voltage and current are inversely proportional to each other. You can tell this due to the negative slope of the straight line.

...read more.

This student written piece of work is one of many that can be found in our AS and A Level Electrical & Thermal Physics section.

Found what you're looking for?

  • Start learning 29% faster today
  • 150,000+ documents available
  • Just £6.99 a month

Not the one? Search for your essay title...
  • Join over 1.2 million students every month
  • Accelerate your learning by 29%
  • Unlimited access from just £6.99 per month

See related essaysSee related essays

Related AS and A Level Electrical & Thermal Physics essays

  1. Marked by a teacher

    Internal Resistance of a cell

    5 star(s)

    We will be able to deduce the EMF of each cell. Apparatus * 2 large dry cells (one new and one old 1.5 volts) * Rheostat * Voltmeter 0-5 or 0-3 V) * Ammeter (0-500mA) * Switch * Connecting wires * Graph paper Independent variables: * current (symbol I)

  2. Peer reviewed

    To determine the internal resistance of a dry cell using an ammeter and a ...

    3 star(s)

    slope of the graph = - r (1.30-1.34) / (0.0450-0.0250) = - r 2.00 ohm = r The internal resistance of cell X is 2.00 ohm. V = ? - Ir 1.34 =?- 0.025 X 2.00 1.39 V =?

  1. In this experiment, we will measure the e.m.f. and the internal resistance of a ...

    internal resistance and the e.m.f of the dry cell by both mathematical and graphical methods. For mathematical method, It is possible to work out the current that flows when a power source is connected to an external resistor, R. R and r are in series and given that the current

  2. Investigating the E.m.f and Internal Resistance of 2 cells on different circuit Structures.

    for graphs: I expect the graphs to follow the following trend below. I have derived this from preliminary work on current and voltage using a wide range of resistors. The readings should obey ohms law. V I Apparatus: For this investigation I will need the following apparatus: * Several resistors ranging from 12 ohm to about 220 ohm.

  1. Measuring the e.m.f. And Internal Resistance of a Cell

    ?x 0.78 Gradient of minm line = ?y = - 0.425 = -0.45 (2dp) ?x 0.95 ?m = mmax - mmin = 0.487 - 0.447 = 0.040 = 0.02 (2dp) 2 2 2 ? Gradient (m) = -0.47�0.02 Since V = -r I + ?

  2. Free essay

    Finding the internal resistance of a solar cell

    Another error which would increase accuracy if reduced is parallax error, this cannot be counteracted as the ammeter and voltmeter being used are on a multimeter which has a digital display. To increase the sensitivity I have decided to use the multimeter as the multimeter has variable settings to match the maximum sensitivity for the values of both variables.

  1. Characteristics of a Photovoltaic Cell.

    Where the theory suggests that for infinite resistance, voltage should give the maximum results; i.e. reflecting the EMF produced, the I-V graphs show a dip for the first result - where voltage = 0. These unexpected results seem to correct themselves as light intensity increases, so where Lux = 15050, the short circuit does give maximum current.

  2. The aim of the experiment is to verify the maximum power theorem and investigate ...

    in horizontal position as much as possible, we also can measure the degree of the direction of the applied force to the horizontal by using the projector. Besides, the roughness of the sand paper is not the same over the whole sand paper.

  • Over 160,000 pieces
    of student written work
  • Annotated by
    experienced teachers
  • Ideas and feedback to
    improve your own work