• Join over 1.2 million students every month
  • Accelerate your learning by 29%
  • Unlimited access from just £6.99 per month

Is sulphuric acid dibasic?

Extracts from this document...

Introduction

Chemistry Planning Exercise Aim In this plan I shall demonstrate that sulphuric acid is dibasic. In order to do this affectively I will plan experiment using scientific techniques. The experiment will involve titration. I will then validate these experiments using calculations and appropriate chemistry knowledge. The reactants I have selected that will neutralise sulphuric acid are shown below in the equations: Reactants used in Titration and products obtained: H2SO4 (aq) + 2NaOH (aq) --> Na2SO4 (aq) + 2H2O (l) Background knowledge The acid (sulphuric acid) is identified by being paired with a hydrogen ion and a base (sodium hydroxide) is identified by being paired with a hydroxide group. Sodium Hydroxide neutralises the sulphuric acid to form salt and water. Sulphuric acid A dibasic acid has two hydrogen atoms in its molecule which can be ionised. Sulphuric acid is dibasic acid, because it contains two hydrogen atoms which ionise in aqueous solution to become 2H+ ions. The equation below shows an ionic equation for sulphuric acid. H2SO4 + 2H+ --> SO42- Sodium Hydroxide Sodium Hydroxide is used as a base. It is completely ionic, containing sodium ions and hydroxide ions. The hydroxide ions make sodium hydroxide a strong base which reacts with acid to form water and salt. ...read more.

Middle

Do not try to induce vomiting. Call for immediate medical help. Procedure Preparing a standard solution of sodium hydroxide: You measure accurately a sample of sodium hydroxide and use it to make a solution of concentration of 0.2M. This solution will be used to determine the volume of a solution of sulphuric acid. Procedure 1 1. Measure 50cm3 of 0.4moldm-3 of solution of sodium hydroxide into a measuring cylinder. 2. Transfers the measured sodium hydroxide solution into the volumetric flask through the filter funnel. Rinse the measuring cylinder well, making sure all liquid goes into the volumetric flask. 3. Add water until the level is 1cm of the mark on the neck of the flask. Insert the stopper and shake to mix the content. 4. Using the drooping pipette, add enough water to bring the bottom of the meniscus to the mark, as in the diagram. Insert stopper and shake thoroughly ten times to ensure complete mixing. Simply inverting the flask once or twice does not mix the contents properly and may result in a fault. 5. Label the flask with sodium hydroxide (NaOH). Procedure 2 In procedure 1 you made a standard solution of sodium hydroxide up to 100cm3. ...read more.

Conclusion

Note that this does not introduce a fourth figure; it merely makes the third figure more reliable. Suitable quantities to use in both the experiment In this experiment I have decide to use 50cm3 of 0.4M of sodium hydroxide which will be made up to 100cm3. The standard solution of sodium hydroxide will have 0.2M. 50cm3 of NaOH of 0.2M. Moles = concentration x volume = 0.4x50 = 0.2 1000 1000 Specimen calculation Titration data: Conical flask reagent Sodium hydroxide 0.2mol dm3 25cm3 Burette reagent Sulphuric acid 1.00mol dm3 Indicator Trial run Run 1 Run2 Burette reading Final 28.0 25.5 24.5 Initial 0.00 0.00 0.00 Volume used (titre)/cm3 28.0 25.5 24.5 Mean titre/cm3 25.0 Step 1: Amount of NaOH = concentration x volume Amount= 0.2moldm3 x 25.0 = 0.005mol 1000 Step 2: Amount of H2SO4 = concentration x volume Amount= 1.00moldm3 x 25.0 = 0.025 1000 Step 3: Ratio of H2SO4 to NaOH 0.0025: 0.005 1 : 2 Ratio of H2SO4 to NaOH is 1:2 2 mol of NaOH reacts with 1 mol of H2SO4 so the equation is: H2SO4 (aq) + 2NaOH (aq) --> Na2SO4 (aq) + 2H2O (l) When this reaction occurs 1 mole of sulphuric acid releases 2 moles of hydrogen ions, hence proving that sulphuric acid is dibasic. ?? ?? ?? ?? Candidate name: Manal Javed Candidate number : Centre number: ...read more.

The above preview is unformatted text

This student written piece of work is one of many that can be found in our AS and A Level Physical Chemistry section.

Found what you're looking for?

  • Start learning 29% faster today
  • 150,000+ documents available
  • Just £6.99 a month

Not the one? Search for your essay title...
  • Join over 1.2 million students every month
  • Accelerate your learning by 29%
  • Unlimited access from just £6.99 per month

See related essaysSee related essays

Related AS and A Level Physical Chemistry essays

  1. Acid-base titration. Objective To determine the concentration of sulphuric acid (H2SO4) using sodium ...

    A student said that he was supposed to dissolve the weighed sodium carbonate sample in 250cm3 of distilled water in a volumetric flask. Is there any mistake in his saying? Explain. -The student was incorrect in saying that. He was supposed to dissolve the weighed sodium carbonate in a beaker

  2. Investigating the Rate of the Reaction between Bromide and Bromate Ions in Acid Solution

    bromide solution o Measure the time taken for the methyl orange to change colour with five different concentrations of bromate solution o Measure the time taken for the methyl orange to change colour with five different concentrations of acid solution I can plot a graph of 1/time taken against concentration

  1. The Determination of rate equation

    To further make sure that the temperature does not affect the my experiment in will check the temperature of the each reagent concentration before starting each reaction, as this way I will further remove any errors and maintain the temperature well.

  2. Science at Work Research . Dulux Paints, a Hospital, a leisure centre and a ...

    What Science is involved? Chlorine: Chlorine is the chemical that is often used to keep swimmingpools free of bacteria that can be hazardous to humans. It kills bacteria through a simple chemical reaction. The chlorine solution breaks down into different chemicals including hypochlorous acid and hypochlorite ion.

  1. Investigating the Volume of a Drop

    Star Volume End Volume Difference Volume per Drop 2.00 ml 2.12 ml 0.12 ml 0.012 ml 2.12 ml 2.30 ml 0.18 ml 0.018 ml 2.30 ml 2.41

  2. Investigating the rate of reaction between peroxydisulphate(VI) ions and iodide ions

    It is important to note that any apparatus in the water bath will also be warned up. There will be metal items present in the water bath, such as clamp stands and test tube holders. Metal is a very good conductor of heat.

  1. Chemistry planning exercise

    This will be used to determine the concentration of the sulphuric (VI) acid sample. However, the weight of sodium carbonate I need to use is still unknown, so this will have to be found. Using the formula n= Vc, where, n= moles of solute (mol.)

  2. Determining the Concentration of Sulphuric acid

    This is because; methyl orange indicator gives an accurate indication of the end point using a strong acid (sulphuric acid) and a weak alkali (sodium carbonate). 2 Making up my Standard Solution As I have mentioned before, I want my standard solution to have the concentration of 0.10 moldm-3.

  • Over 160,000 pieces
    of student written work
  • Annotated by
    experienced teachers
  • Ideas and feedback to
    improve your own work