Measuring Vitamin C content in different substances

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Biology


Aim: I’m going to investigate the concentration of Vitamin C (ascorbic acid; C6H8O6) in various fruit juices and to compare them. This experiment will see the following fruit juices going under experimentation: pineapple, orange and papaya juice. I’m going to use these juices because I expect these to have large amounts of vitamin C and this should allow me to get good results.

Hypothesis: I predict that the orange juice will have the highest Vitamin C concentration. From my own knowledge, a citrus fruit such as the orange is rich in ascorbic acid, more commonly known as Vitamin C. Much is not known about the pineapple or the papaya, therefore I can safely assume that the orange juice will have the highest concentration of vitamin C in it out of the 3 fruit juices.

Apparatus:

  • Standard 1% Vitamin C solution (Acts as the control)
  • Pineapple Juice (From a fresh, brand new carton)
  • Orange Juice (From a fresh, brand new carton)
  • Papaya Juice (From a fresh, brand new carton)
  • 1% DCPIP (Dichlorophenol-indophenol) solution (Turns colourless when in the presence of Vitamin C)

Standard lab glassware/equipment:

  • Measuring cylinder (To measure out accurately the volumes of fruit juice),
  • Pipettes (Used to extract the juices from carton with contaminating the juice),
  • Test tubes (To contain the solutions),
  • Stopwatch (To measure the time for the DCPIP to turn colourless),
  • Glass rod (To stir the contents of the test tube to ensure that it is distributed evenly),
  • Test tube rack (They are needed to hold the quantity of test tubes used to accommodate the solutions)

Method:

  1. Measure out 15cm³ of Vitamin C solution and pour into a test tube. Measure out 1cm³ of DCPIP, pour it into test tube with the Vitamin C solution and stir it evenly with the glass rod.
  2. IMMEDIATELY start the stopwatch and record the time taken for the mixture to turn colourless. Preferably at least three people should perform on one juice at a time. One would pour the DCPIP, another would time the decolourisation and the last would observe the solution as it changed colour and stirs the content at an even pace.
  3. This is going to be the control, because we know that it has a high concentration of vitamin C, therefore you can later compare the times taken for other substances to change colour. Results close to these will help deduce which fruit juices have the highest and lowest vitamin C content. It will give us an idea whether enough fruit juice has been added, or if more will be needed.
  4. Next, pipette out some juice from the carton and measure out 15cm³ of orange juice and pour that into a test tube. Measure out 1cm³ of DCPIP, pour it into the test tube with orange juice and stir evenly.
  5. Record the time for the mixture to turn colourless.
  6. Do exactly the same for the other 2 fruit juices: pineapple and papaya. Don’t forget to record their times accurately.
  7. Repeat the entire experiment 2 more times, resulting with 3 sets of results for each fruit juice.
  8. Find the average times and compare each fruit juice average.
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Safety/Risks:

  • During the experiment, make sure that none of the solutions are ingested. Even if the DCPIP hasn’t been added to the fruit juice, there should be no reason to drink the juice, because other toxic chemicals might have accidently poured into it by mistake.
  • DCPIP itself is a toxic chemical which will cause death.
  • Wear goggles and gloves so that the DCPIP does not touch your eyes/skin etc
  • Clean up any DCPIP solution spills immediately.
  • All DCPIP solutions, after the experiment, should be poured into a waste bucket. Wash out the test tubes with water thoroughly.
  • Be ...

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Dialect and level of words used are not to a very high scientific standard. Grammar is okay but stumbles in some places. Punctuation and spelling are fine.

Aim is not very well researched, and should actually research the different already published values of different values in the different fruits to make an educated opinion on which fruits to use, rather than assuming they have quite a lot of vitamin C in them. The candidate admits to little knowledge about two of the fruits so I am not sure they were a safe comparison in this instance. Does not investigate if the amount of fruits contained in the fruit juice are consistent throughout so not to bias the amount of vitamin C found in them. Includes chemical equations and pictures which boosts up the level of the candidates work. Graph used to compare results is quite hard to understand and not appropriate to show the results from the experiment. Could do more statistical tests to prove or reject the hypothesis such as the chi squared test. Considers a range of different improvements and things that may have gone wrong with the experiment but could have expanded by calculating possible percentage errors of the different equipment.

Adequate essay. Response to the question overall is average for this level and presents the information in a adequate way to a high standard exploring different methods of presenting the data. One or two things could be improved such as the scientific research behind the data and types of tests used.