Objective; To determine the concentration of hydrogen peroxide, H2O2, in aqueous solution.

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To determine the concentration of hydrogen peroxide, H2O2, in aqueous solution.

In this practical examination I am provided with a ‘100-volume’ hydrogen peroxide solution. Taking the ‘100-volume’ into consideration I have to plan two experiments that would enable me to determine the exact concentration of H2O2, in mol dm-3.

Titration:

The first experiment I shall carry out will be a redox titration; between hydrogen peroxide and potassium manganate (VII). A titration will enable the reacting volumes of H2O2 and KMnO4 to be accurately determined. From this information and the stoichiometric ratio I will then be able to determine the concentration of H2O2.

Prior to going into detail we must first understand what a‘100-volume’ solution is.  By definition this means that 1cm3 of H2O2 will decompose to produce 100cm3 of O2 at STP. In simple terms it is just another way of indicating the strength of H2O2.

2H2O2 (aq)                2H2O(l) + O2(g)                                        Equation 1.

Consequently, we can understand that ‘100-volume’ represents a very strong concentration of H2O2. Thus, before carrying out the titration the solution of H2O2 must be diluted.

A reasonable dilution factor for this experiment is 100; hence from a 100-volume to a 1-volume solution. As I know the strength of the original (C1) and the new solution (C2), I can use the below formula:

C1V1= C2V2                                                                Formula 1.

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where V1 is the original volume (dm3)

           V2 is final volume (dm3)

To make up a 1-volume H2O2, we would need to use a graduated pipette to transfer 0.01dm3 of the 100-volume H2O2 into a 1dm3 volumetric flask. As we know 3 of the 4 quantities in formula 1 we can work out V2:

100(0.01) = 1(V2)

 V2 = 1 dm3

As the final volume is 1 dm3, the volumetric flask needs to be filled up to the top with distilled water.

The principle behind a redox titration is ...

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