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Order of Reaction between Iodine and Propanone

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Introduction

Title: Order of Reaction between Iodine and Propanone Date: 21-2-2011 Objective: To investigate the order of reaction between Iodine and Propanone(CH3COCH3 ) Results Group A Time when reaction mixture was added to NaHCO3 (s) 315 610 886 1220 1500 1808 Volume of Na2S2O3 added (cm3) 19.95 18.70 17.90 16.80 16.10 15.20 Group B Time when reaction mixture was added to NaHCO3 (s) 369 638 858 1175 1510 1793 Volume of Na2S2O3 added (cm3) 19.50 18.70 18.60 17.50 16.90 16.30 Group C Time when reaction mixture was added to NaHCO3 (s) 339 620 912 1245 1516 1869 Volume of Na2S2O3 added (cm3) 20.60 20.00 19.10 18.60 17.70 17.30 Group D Time when reaction mixture was added to NaHCO3 (s) 323 637 922 1209 1496 1791 Volume of Na2S2O3 added (cm3) 22.30 19.35 18.20 17.65 17.15 17.00 Group E Time when reaction mixture was added to NaHCO3 (s) 312 608 933 1205 1507 1791 Volume of Na2S2O3 added (cm3) ...read more.

Middle

(volume of sodium thiosulphate added)(molarity of sodium thiosulphate added)] /(volume of reaction mixture) ?concentration of iodine in the reaction mixture = [(1/2) (volume of sodium thiosulphate added)(molarity of sodium thiosulphate added)] /(volume of reaction mixture) ?The concentration of iodine in the reaction mixture can be expressed in terms of the volume of sodium thiosulphate added. 4. Plot a graph of the time at which the 10cm3 samples of the reaction mixture were added to the sodium hydrogencarbonate solution(x-axis) against the volume of sodium thiosulphate needed to react with the remaining iodine(y-axis). Attached 5. Determine the concentration of sodium thiosulphate from the graph you plotted. From the data of Group A ,at time=0, volume of sodium thiosulphate added should be 20.75cm3. ?concentration of iodine in the reaction mixture = [(1/2) (volume of sodium thiosulphate added)(molarity of sodium thiosulphate added)] /(volume of reaction mixture) ?0.0198= [(1/2) (20.75/1000) (molarity of sodium thiosulphate added)]/(50/1000) ...read more.

Conclusion

25.0 20.0 15.0 10.0 5.0 Gradient of graph/cm3S-1 -2.92 x10-3 -2.12 x10-3 -2.17 x10-3 -2 x10-3 -1.86 x10-3 9. Plot the gradients of graphs above against the initial volume of propanone solution added. A graph showing the gradients of graphs above against the initial volume of propanone solution added. 10. What is the order of the reaction with respect to propanone? The gradient of the graph in (9)is directly proportional to the rate of reaction and volume of propanone solution is also directly proportional to its concentration. Since a straight line is plotted in the graph above, rate of reaction is directly proportional to the concentration of propanone. Thus, the order of the reaction with respect to propanone is 1. Conclusion The order of the reaction with respect to propanone is 1 and the order of the reaction with respect to iodine is 0. Reference http://fyk.hkcampus.net/~fyk-nyw/AL_documents/99ALF6Expt10.doc http://www2.hkedcity.net/sch_files/a/kss/kss-cfm/public_html/content/expts/text/expt/s6expt/s6expta/alp06a.doc http://www.nelsonthornes.com/aqagce/A2%20Sample%20material/Science/Chemistry.pdf http://qcrc.qef.org.hk/proposal/2000/2000-1245/2000-1245-D04-32141.DOC http://hk.knowledge.yahoo.com/question/question?qid=7009021900778 http://hk.knowledge.yahoo.com/question/question?qid=7007021302105 F.6 Chemistry Notes Section V by Ms Sin W L The End ?? ?? ?? ?? F.6 Chemistry/TAS 12/P.1(6) ...read more.

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