Plan To Determine The Concentration Of A Limewater Solution

Authors Avatar

Plan To Determine The Concentration Of A Limewater Solution

        In order to determine the concentration of this limewater solution I must perform a titration (also known as volumetric analysis) between the alkali and acid given to me. In order to carry this out I must know the concentration of one of the solutions (in this case the acid, which has been given to me at 2.00 mol dm-3) and the balanced equation between my two reactants; which is:

                Ca(OH)2 (aq) + 2HCl (aq) → CaCl2 (s) + 2H2O (l)        

        For which the ionic equation would be (as with all neutralisation reactions):

                OH(aq) + H+(aq) → H2O (l)

Dilution Calculations

        

        As the concentration of my acid is 2.00 mol dm-3 I believe this will be too strong, so little will be used and my results will be more unreliable.

If I did the experiment with the 2 mol dm-3 HCl:

        I will be using 25cm3 of sodium hydroxide so there would be:

                  1    

                   74.1   =  0.0135 moles  in 1dm3 of Ca(OH)2 as there is 1g dm-3

so the concentration is 0.0135 mol dm-3

                

this means there will be    25   × 0.0135  =  0.0003375 moles in the 25cm3 Ca(OH)2 I  will use

                                                1000                                        

                so the approximate amount of HCl needed to neutralise this will be 0.000746 moles

                                Ca(OH)2 : HCl

                                            1 :  2

                                   0.0003375 :  0.000675

                

                if the concentration of HCl is 2 mol dm-3 then

                        0.000675  =  0.0003375 dm3  =  0.3375 cm3

                               2

        This is a very small volume so the measurement errors will be large:

                (the error margin for a 50cm3 burette is ± 0.1)

                     0.1      × 100 = 29.6 %

Join now!

                  0.3375  

        As I plan to use a 50cm3 burette, an ideal volume of HCl to be measured out would be between 20-30cm3; so if I want to use about 25cm3 of HCl then the concentration will need to be about:

                        0.000746  =  0.02984 mol dm-3

                           25/1000

        

        To make dilution process easier (and more accurate) I will dilute to a concentration of 0.02 mol

dm-3 .I could use a single or two fold dilution.

Dilution Method

If a single fold dilution was used:

equipment:

...

This is a preview of the whole essay