Proving the lens formula.

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Jack Webdale        02/05/2007     Page

Proving the lens formula

Background information

When light passes from air to a denser material it slows down. In a concave lens the light has to travel further through the middle then through the sides. This has the affect of pushing the waves back in the middle and forward around the edge therefore effectively adding curvature to the wave. A similar thing happens when passing through a concave lens but obviously vice-versa, taking away curvature of the wave.

The curvature that the lens adds or takes away is the Power of the lens, measured in dioptres. P=1/f, P is the power of the lens and f is the focal length. The focal length of a lens is the distance from a lens to its focal point, which is where the image of a distant object is formed. The shorter the focal length the more powerful the lens.

The following formula is what I am going to attempt to prove that it is valid. It is used to give the focal length, and hence where the image is focused.

1/v+1/u=1/f

Where v is the distance from the lens to its focal point, u is the distance from the object to the lens and 1/f is the power of the lens. This follows from the above, the power shows how much curvature is added to the wave. As a wave moves further away from an object the curvature of it decreases.

This formula may also help me with my progress, as I can use it to calculate the magnification of the lens.

m=v/u (when in focus)

Where m is the magnification, v is the distance from the lens to the image and u is the distance from the lens to the object. The further away the image is from the lens the lower the magnification, and the closer the image is to the lens the higher the magnification.

Hypothesis

The lens formula for a convex lens valid.

Apparatus

I will use the following equipment during me experiment.


A Convex lens and lens holder – Small convex lens used to focus the image on the screen. Small plastic holder used to keep the lens in place.
A Metre rule –
Will be used to measure both the object distance (U) and the image distance (V). It has millimetre units, although large and hard to take a precise measurement in mm.
A 30 cm rule –
Will be used to increase the accuracy of the measurements, where the metre rule proves difficult to use to get an accurate result. 
A Small screen –
Flat white screen on a stand, used for the image to focus on. Image distance measured from the front of the screen.
A Light source (Mains or Low Voltage) –
small Lamp, 40-watt bulb. Used to emit light and is part of the object.
A wire mesh on a stand –
Used to create a clear, sharp focus-able image that I can take measurements from. Placed in front of the light source.

Jack Webdale        02/05/2007     Page 2

Most of the apparatus I will use are self explanatory due to the background information. I will use the Wire mesh on a stand as part of the object, as I am satisfied that it will be easy to produce a clear, sharp image with it. If I was to use A light bulb with text printed on it, it may be harder to get a clear image as if I used ink, it may smudge or become blurred due to the heat of the lamp. I have also chosen to use a 30cm rule as well as a metre rule, as the metre rule may be inaccurate or cause problems when trying to measure to mm. A 30cm rule could be used to do this easily and to a better degree of accuracy.

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Prediction

I would choose to predict that the formula is valid. Avoiding the fact that people have used the formula for years, especially opticians, and I gather it must work as they still use it! However, my task is to prove that it works. The diagram below shows what occurs when light travels through a converging lens. It shows where the focal points image and object distances are represented.

Due to the proportions of the diagrams I have studied, it would seem logical that two reciprocals added together would produce a reciprocal which it’s decimal value would be less, ...

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