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Redox Titration Aims/Objective : To determine the molar concentration of the given KMnO4 solution.

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Chemistry TAS Report 1. Experiment Number : 16 2. Date : 30/04/2008 3. Title : Redox Titration 4. Aims/Objective : To determine the molar concentration of the given KMnO4 solution. 5. Introduction / Theory: 6. Relevant Equations/Chemical Reactions Involved : Half-equation : MnO4-(aq) + 8H+(aq) + 5e- � Mn2+(aq) + 4H2O(l) C2O42-(aq) � 2CO2(g) + 2e- Overall equation : 2MnO4-(aq) + 16H+(aq) + 5C2O42-(aq) � 2Mn2+(aq) + 8H2O(l) + 10CO2(g) 7. Chemicals : Oxalic dehydrate acid crystal 1.58 g KMnO4 solution 80 cm3 1 M dilute sulphuric acid 80 cm3 8. ...read more.


by distilled water. 3. 25 cm3 of oxalic acid was pipetted in a conical flask. About 25 cm3 of 1 M dilute sulphuric acid was added to it so that the solution was acidified. 4. The mixture was heated to about 60 oC by Bunsen burner. 5. The hot mixture was titrated with KMnO4 solution until the colour changed form colourless to pink. 6. Steps 3 to 5 were repeated for two more times. 10. Observations : The colour changed from colourless to pink at the end point. 11. Data, Calculation and Results : Trial 1 2 Final burette reading / cm3 22.20 42.45 43.65 Initial burette reading / cm3 2.00 22.25 23.50 Volume of titrant / cm3 20.20 20.20 20.15 Volume of titrant = (20.20 + 20.15) ...read more.


of mole of oxalic dihydrate acid crystal = 1.58 / 126 = 0.0125397 mol Molarity of the prepared oxalic dihydrate acid solution = 0.0125397 / (250 x 10-3) = 0.05 M No. of mole of potassium permanganate solution = No. of mole of 25 cm3 of oxalic dihydrate acid solution x 2/5 = 0.05 x 25 x 10-3 x 2/5 = 5 x 10-4 mol Molar concentration of the given KMnO4 solution = 5 x 10-4 / 20.175 x 10-3 = 0.0248 M 12. Conclusion : The molar concentration of the given KMnO4 solution was found to be 0.0248 M. 13. Discussion : 1. In this redox titration, no indicator is required as the end point can be determined by the colour change of reactant (KMnO4 solution). 2. ...read more.

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