The aim in this experiment is to estimate the total number of microbial cells in a culture and estimate the number of living cells. This will be done using a counting chamber and microscope. There will be a total count and a viable count

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MC-2 molecules to cells.

Estimation of the number of microbial cells

Aim

 The aim in this experiment is to estimate the total number of microbial cells in a culture and estimate the number of living cells. This will be done using a counting chamber and microscope. There will be a total count and a viable count. The Total count will require a microscope to count the number of cells in a sample. These cells are living and dead. A haemocytometer will be used. A haemocytometer has a known volume of chamber and area  which is etched on the glass. A cell suspension is able to be above the known area. The chamber is then filled with a yeast suspension then covered with a cover slip. An average number of microbes can then be counted in the ruled area to give the number of yeast cells per cm3.

This is a view through a microscope of a grid on a haemocytometer. Most of  the cells in the grid are counted other than from the cells that are represented in black.

b)

In a viable count a set of known dilutions are set up of yeast, tenfold serial solutions are prepared. A sample from each dilution is then added using a pipette onto a labelled area of the agar medium culture where the Miles Misra method is to be used. These dilutions are made up with sterile saline to produce a 5cm3 volume. These dilutions on the agar are then incubated at 30c for 24-48 hours until there are visible signs of colonies formed. The single colonies are counted, not the converged colonies. This will estimate the number of living cells only.  

Results

Viable count

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These are the results for 10-5 yeast dilution

The number of colonies in 10-5 yeast dilution = 14

1cm3 of the original suspension: 14*50*105=  7*108 cfu cm ¯³

These are the results for the 10-6 dilution

The number of colonies in 10-6 yeast dilution = 11

1cm3 of the original suspension: 11*50*106= 5.5*108

I have used the 10-5 and 10-6 dilutions as these were the only dilutions that shown single colonies. The others were to numerous to count or there was no growth.  

Total count

Total number of cells ...

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