• Join over 1.2 million students every month
• Accelerate your learning by 29%
• Unlimited access from just £6.99 per month
Page
1. 1
1
2. 2
2
3. 3
3

# The aim of this experiment is to prove that a falling body has a constant force of gravity on it, no matter what the distance or time taken for the object to fall. The value of gravity or &quot;g&quot; will be determined.

Extracts from this document...

Introduction

AIM

The aim of this experiment is to prove that a falling body has a constant force of gravity on it, no matter what the distance or time taken for the object to fall. The value of gravity or "g" will be determined.

THEORY

The most simple example of linear motion is a body falling to Earth. When the body is dropped from a height we know that the object will always fall directly towards the centre of the Earth. This though will not happen if a feather is dropped as due to its shape and the forces of drag, upthrust and various others act upon it with greater effect. So providing these forces in our experiments and calculations are negligible by using suitable materials it is fair to say an object falls towards the Earths centre.

When the plastercine passes through gate A the computer will immediately start the clock.

Middle

The range of results will be from 0.3m to 0.6m. This is because at a smaller distance the computer is unable to register the speeds fast enough, and at a greater distance the light gates do not connect with the computer. By taking 5cm intervals enough results can be taken to plot a graph.
In order for my results to be reliable I shall take three readings for each distance. An average can the be taken and error reduced as anomolous results would be illiminated.
As the computer only displays the velocities the most suitable equation of motion to determine "g" would be V² = u² + 2as or V² = u² + 2gs. This equation can be re-aranged to prove "g" is constant by making gravity the subject.
 V² = u² + 2gsV² - u² = 2gsV² - u² = g2s

CONCLUSION

Using the equation would need an average gravity of each reading.

Conclusion

Using the line of best fit it can be seen that there is an anomolous result when 2s is equal to 1.0m, which is a distance to fall of 0.5m. This meant that the line of best fit has to be brought down to a lower gradient. So the true gradient should be a little steaper. This would increase the acceleration due to gravity. This could be proved by retaking the readings at this point and calculating a new average.

To further this investigation and prove totally that gravity is a constant force a second experiment could be carried out. Of the several available to measure g, it would be possible to select one which does not rely on linear motion but simple harmonic motion instead. By setting up a simple pendulum it is possible to calculate a value of g by measuring the average time for a single pendulum oscillation. If the length of the pendulum is known, it is possible to plot graphs and get a value for g.

This student written piece of work is one of many that can be found in our AS and A Level Mechanics & Radioactivity section.

## Found what you're looking for?

• Start learning 29% faster today
• 150,000+ documents available
• Just £6.99 a month

Not the one? Search for your essay title...
• Join over 1.2 million students every month
• Accelerate your learning by 29%
• Unlimited access from just £6.99 per month

# Related AS and A Level Mechanics & Radioactivity essays

1. ## Torsional Pendulum final experiment

3 star(s)

This is what I obtained. This shows that I should obtain exactly 0.5 as the gradient and the R squared correlation should be as close to 1 as possible to represent a strong correlation Method: * Set up the apparatus shown above, connect lead into laptop and open sensing science software, select com1.

2. ## The acceleration of a ball down various inclines

3 star(s)

Because of the incline I made the ball roll down, it was rolling on a 2� incline at first. Its acceleration was 34.8cm/s2, so g is 28. 2 times larger than g on a 2� incline. Although they are not exactly proportionally, as g should be 45 times larger than

1. ## SHM: determining acceleration due to gravity

Sixthly, the experiment involves measurement error. The apparatus for measurement is not enough, for example, the metre rule can just measure the length of string which is correct to the nearest 0.1 cm. By the following equation, The largest possible error: From this experiment, we can also know that period is independent of the mass of

2. ## Use of technology in a hospital radiology department. The department of imaging is one ...

MRI scans may not be advisable in early pregnancy unless there are special circumstances, because there is a small theoretical risk to the foetus in the first 12 weeks of pregnancy and therefore scans are not performed on pregnant women during this time.

1. ## Investigating the factors affecting tensile strength of human hair.

By taking all the observed values of stress from tables 57, 58, 59 and 60, I can work out the expected value for each hair colour. I can then place these values in a table and work out the value for X2, using the chi squared formula.

2. ## CIRCULAR MOTION - revision notes and calculations

94 I /1(a) The figure below shows a car travelling over a hump, which is an arc of a vertical circle. Compared with travelling on a level road, would a passenger feel heavier, lighter or same as usual when the car passes the top of the hump? Explain your answer.

1. ## Evaluating a Torsional Pendulum experiment

Therefore the error on the gradient is approximately [{(0.5+3)/2}+{(0.12+2.4)/2}]=3.01%, this was using the average of the reading and experimental errors. From the percentage errors above I believe the main source of error was the diameter of the wire, this had the highest total percentage error and as seen from the

2. ## Physic lab report - study the simple harmonic motion (SHM) of a simple pendulum ...

Also plot a graph of acceleration against time. Results and Measurements: (Copied from the data of MVA software) Values of velocity is found by the equation: (x2-x1)/(t2/t1), whereas x1=-7.54E-02 x2= -4.08E-02, t1=0.00E+00 ,t2=6.67E-02 Values of acceleration is found by the equation: (v2-v1)/(t2-t1)

• Over 160,000 pieces
of student written work
• Annotated by
experienced teachers
• Ideas and feedback to