• Join over 1.2 million students every month
  • Accelerate your learning by 29%
  • Unlimited access from just £6.99 per month

The aim was to become accustomed to working with the equipment and to find optimum levels of hydrochloric acid and magnesium ribbon to produce 60cm of hydrogen, a sensible amount to produce in the real experiment.

Extracts from this document...

Introduction

Aim: The aim was to become accustomed to working with the equipment and to find optimum levels of hydrochloric acid and magnesium ribbon to produce 60cm of hydrogen, a sensible amount to produce in the real experiment. We also began to investigate the effect of temperature on the rate and the result of the product (hydrogen). It also served to discover any errors in the procedure which could affect the final result and prevent us getting accurate results, thus allowing us to eliminate these errors in the real experiment. Diagram: Method: We attached a gas syringe via a plastic tube to a test tube and used a clamp and stand to hold the gas syringe in place. Having poured 25cm of hydrochloric acid (of strength 1M) into the test tube, we placed a strip of magnesium ribbon (which length varied each time we repeated the procedure) ...read more.

Middle

Amount of hydrogen gas produced (cm ) 2 39 3 44 3.5 45 4 56 4.5 63 Here are two tables showing the rate of the reaction between 25cm of hydrochloric acid and a 4.5cm strip of magnesium ribbon when the hydrochloric acid is heated to 40�C and 70�C respectively: Hydrochloric acid heated to 40�C Time (seconds) Volume of gas (cm ) 15 24 30 40 45 45 60 50 75 54 90 60 105 62 120 64 Hydrochloric acid heated to 70�C Time (seconds) Volume of gas (cm ) 15 25 30 39 45 50 60 58 75 62 90 64 105 64 120 64 Conclusion: In the first part of the pilot experiment, we discovered that the correct length of magnesium ribbon to produce approximately 60cm of hydrogen gas when allowed to react with 25cm of hydrochloric acid is 4.5cm. We also became aware of the products of the reaction, magnesium chloride and hydrogen gas. ...read more.

Conclusion

This is because the amount of hydrochloric acid and magnesium does not change, therefore the amount of magnesium chloride and hydrogen will not change, but because the temperature of the hydrochloric acid is higher, the atoms in the hydrochloric acid will be moving faster, and therefore will collide and bond (ionically) with the magnesium atoms quicker. We also discovered several points to remember in the second procedure to ensure accurate, reliable results. The hydrochloric acid was heated in a small beaker and this became very hot, so we had to use tongs to pour it into the test tube. As the reaction begins to happen even more quickly when the hydrochloric acid is heated, we had to ensure also that we were ready to immediately seal the test tube after pouring in the heated hydrochloric acid and placing the magnesium in immediately to avoid the hydrochloric acid cooling. ...read more.

The above preview is unformatted text

This student written piece of work is one of many that can be found in our AS and A Level Physical Chemistry section.

Found what you're looking for?

  • Start learning 29% faster today
  • 150,000+ documents available
  • Just £6.99 a month

Not the one? Search for your essay title...
  • Join over 1.2 million students every month
  • Accelerate your learning by 29%
  • Unlimited access from just £6.99 per month

See related essaysSee related essays

Related AS and A Level Physical Chemistry essays

  1. Investigating the Rate of the Reaction between Bromide and Bromate Ions in Acid Solution

    Also, all the measurements I will have to take should be sufficiently large to minimise the percentage error on the measurement. I am confident that the concentrations of all solutions made will be accurate, which is important when investigating how concentration affects the rate of the reaction.

  2. The Determination of rate equation

    We can see the same pattern and trend when analysing the graphs. The graphs demonstrate the reaction rate against the concentration; from this I will able to deduce the order of reaction and find out the value of X and Y in the rate equation shown below: Rate = k

  1. Investigating how concentration affects rate of reaction

    43.1 42.6 42.8 42.76 0.0234 25 28.8 28.3 27.9 28.1 28.6 28.34 0.0353 30 19.6 19.8 19.3 19.5 19.4 19.52 0.0512 35 12.1 11.5 11.9 11.7 11.9 11.82 0.0846 40 5.1 5.6 4.9 5.2 5.4 5.24 0.1908 From Graph 5 on the next page, it is clear that there is

  2. detremining the rate equation

    Safety: * Throughout the experiment safety goggles should be worn to avoid any contact with eyes. * If Sodium thiosulphate comes in contact with eyes immediately flush the eye with gently running tap water for approximately 5minutes. * If swallowed drink plenty of water, Seek medical attention if a significant quantity is swallowed.

  1. Describe the construction, operation and application of distillation equipment used in industry

    This is useful because as vapours and gases rise, some of them will condense when they pass through the liquid level on a tray at a certain temperature. Overall, it makes the distillation process a little bit more efficient as product can be collected more readily.

  2. Does the amount of hydrogen gas formed in the below reaction depend on the ...

    Method: I will take my 30cm magnesium strip and divide it up into different lengths starting with 1cm, 2cm, 3cm, and 4cm. I will repeat this twice more using all of each length. One piece of each length was used in the preliminary investigation and the other two pieces of each length in the main experiment.

  1. My aim is to find out how long it takes for magnesium to react ...

    I chose not to do the surface area as I would not be able to get an accurate measurement for the surface area because there would be no way I could measure all the reactant and get an accurate measurement, for the same reason I chose not to do catalyst.

  2. Investigating the effect on the rate of reaction when changing the acid that is ...

    [2]Example 100% HCL(g) + H20(l) CL-(aq) + H3O+(aq) As the H+ ion is fully dissociating into the water then the Ka value is very high(greater than 1). 1 x 10-5 less than 1% CH2CO2H(l) + H2O(l) CH2CO2-(aq) + H3O+(aq) As the H+ ion doesn't dissociate into the water that much then the Ka value is low.

  • Over 160,000 pieces
    of student written work
  • Annotated by
    experienced teachers
  • Ideas and feedback to
    improve your own work