The experiment involves the determination, of the effective mass of a spring (ms) and the spring constant (k).

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Investigation of the Properties of a Spring  14/11/99.

Introduction

The experiment involves the determination, of the effective mass of a spring (ms) and the spring constant (k).

 

It is known that the period (T), of small oscillations of a mass (m) at the end of a helical spring is given by the formula:

T= 2π(m+ms)

          k

In this experiment the same clamp was used for all readings to make sure there were no miss-readings taken due to differences in the way the clamp and stand reacted to the movement of the mass.  Also the spring in all readings was the same as, after all the ms and k of two different springs is going to be different and lead to different readings.

The things that were varied in the experiment were, the number of slotted masses on the end of the spring and the number of oscillations of the mass to be counted.   The number of oscillations (T) will be measured using a stopcock.  Which was varied to give a number between 20 and 30.   To keep the number of oscillations, for every mass as similar to each other as possible.  To help keep the experiment fair.      

So to find ms and k the following experiment was devised and carried out:

A clamp and stand were used to hold a spring in position, onto which varying sizes of mass were placed.

These masses were allowed to bob on the bottom of the spring and a specified number of oscillations were timed using a stop clock.  These measurements were then noted in a copy of the following table:

The quantities could then be derived in the following ways.  To find the quantities first it was necessary to draw a graph of the results taken and to get the graph to be a straight line graph and so as to be of use the equation of T2 had to be rearranged as shown below:


T= 2π(m+ms)

          k

(square the equation)

T2= 4π2m+4π2ms

   k         k

So then a straight-line graph of T2/S2 against mass could be plotted.   This graph would be used to calculate the gradient of the graph and therefore the value of constant k.   Which could be found by rearranging the equation and using information from the graph as shown below:

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From the equation it can be shown that:

 

Gradient of line = 4π2 

                               k

k = 4π2     

        grad’

To find the value of ms the intercept’s on the y-axis and x-axis can be used can be shown that, on the y-axis where the x value of the graph is ...

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