• Join over 1.2 million students every month
• Accelerate your learning by 29%
• Unlimited access from just £6.99 per month
Page
1. 1
1
2. 2
2
3. 3
3
4. 4
4
5. 5
5
6. 6
6

The objectives of this experiment are to Verify Kirchhoffs laws Determine the equivalent resistance of a network &amp; Study the maximum power transfer theorem.

Extracts from this document...

Introduction

EE2721 Electric Circuit Analysis

Group 5

Introduction:

The objectives of this experiment are to

Verify Kirchhoff’s laws

Determine the equivalent resistance of a network

Study the maximum power transfer theorem

Apparatus:

DC power supply

Multi-meter (DMM)

Experimental board

Experiment 1:(Kirchhoff’s laws)

Theory:

According to the Principle of conservation of Charges, since charges do not accumulate at any point in a network, the charges cannot be created or destroyed.

This bring the Kirchhoff’s First Law, the algebraic sum of the current at a junction of a circuit is zero. Therefore, the current arriving a junction equals the current leaving the junction.

This law also assumed to be positive if it flows into a point and negative if it flows out from the point.

There is also a Kirchhoff’s second law relates the total e.m.f in a closed loop.

Round a closed loop, the algebraic sum of the e.m.

Middle

=21.5Ω

The power supply was removed, we measured again the equivalent resistance

=28.4Ω

The result in step 1 is smaller than in step 2.In step 1 , the power supply has not been removed, and it consists internal resistance. As it connects parallel to

the circuit, the equivalent resistance will be smaller than without parallel internal resistance.

The star-to delta or the delta –to –star transformation was used to calculate the equivalent resistance of network shown in figure 3.

equivalent resistance of

:

The

we calculate is close to step 1 but smaller than step 2. When we calculate the equivalent resistance of

,we don’t know the internal resistance of power supply and we assumed the internal resistance is zero and ignore it in calculation, so the result we calculate is similar to data with removal of power supply.

Experiment 3(Maximum power transfer theorem)

Procedures:

The circuit as shown in figure 7 with

Conclusion

span="1" rowspan="1">

8.909

9.98

11.198

12.475

14.851

0.55

0.566

0.573

0.587

0.596

0.612

0.609

0.603

0.601

0.600

Maximum power: 0.6127mW

9.2

Total resistance:9.2+10=19.2

=20KΩ(with

varying from 15KΩ to 25KΩ)

 2.153 2.2155 2.2779 2.3403 2.4028 2.5351 2.5973 2.6597 2.722 2.784 0.142 0.1388 0.1357 0.1326 0.1294 0.1265 0.1236 0.1205 0.1174 0.1143 15.121 15.962 16.786 17.649 18.569 20.04 21.014 22.072 23.186 24.356 0.307 0.308 0.309 0.31 0.311 0.321 0.321 0.32 0.319 0.318

Maximum power: 0.0215mW

20.05

Total resistance:20.05+20=40.05

Discussion:

aI) minimum sources voltage:

V=400x2x

=40v

aII) there is not significant risk of this type of accident to occur, as the voltage of personal computer is 17v, it is smaller than the minimum source voltage that can produce electrical shock.

b) The criterion for maximum power transfer from a source to a load is the load resistance equals to the internal resistance of the source. If we are free to select

without changing the source voltage, we can decrease the

in order to maximize the power delivered to the load.

E=i(R+

iE=

=

=

The smaller the

, the higher the power supply

C)

=

=

=

The maximum power output occurs when

=

=0

=0

=2R

=

The maximum power output

=

=

This student written piece of work is one of many that can be found in our AS and A Level Electrical & Thermal Physics section.

Found what you're looking for?

• Start learning 29% faster today
• 150,000+ documents available
• Just £6.99 a month

Not the one? Search for your essay title...
• Join over 1.2 million students every month
• Accelerate your learning by 29%
• Unlimited access from just £6.99 per month

Related AS and A Level Electrical & Thermal Physics essays

1. Investigating the E.m.f and Internal Resistance of 2 cells on different circuit Structures.

after each reading and I only realised the effects of this during the practical investigation so therefore I restarted the practical to evade erroneous results. I also changed the unit measurement of current I was going to use. In my original plan, I intended to use current to the nearest

2. The Resolving Power Of The Eye

However, it is common sense to stay safe by not putting electrical equipment next to or in a sink in use as is not running around in the darkened lab.

1. Design and Carry Out an experiment to determine the EMF and Internal Resistance of ...

SAFETY The experiments in this investigation are fairly safe in that not safety equipment (apron, goggles, etc.)

2. The potato - a source of EMF

or is close to the internal resistance calculated from the other graphs. With the amount of data I have been given I believe I cannot prove the Maximum Power Theorem but, if the peak does equal the internal resistance then the experiment will agree with the theory.

1. The aim of the experiment is to verify the maximum power theorem and investigate ...

To find out the static friction, we can make use of the following formula: fL = �s R where �s = coefficient of static friction. As the coefficient of static friction is constant, by the formula of the static friction, the magnitude of the static friction is direct proportional to the normal reaction force.

2. Kirchhoff's Laws - Ohm's law - Resistance - Impedance

A circuit of this type is termed a closed circuit, and a circuit in which the current path is not continuous is called an open circuit. A short circuit is a closed circuit in which a direct connection is made, with no appreciable resistance, inductance, or capacitance, between the terminals of the source of electromotive force.

1. Find The Internal Resistance Of A Power Supply

And I is the current flowing through the circuit. We know that: V = IR This equation can be substituted into equation (1) to give us the equation: EMF = terminal potential difference + lost volts E = V - Ir (2) Using this equation, we know that the internal resistance of the power supply is constant.

2. PID Control Case Study - Balanced beam demonstration

the requirement to provide enough current to actually balance the beam for a given weight. Thus, the only design variable left is d, the differential gain. By measuring K of the system, which was around 80s-2 (Diag.9, Section 4.0), the optimum value of d was found by simulation to be around 0.8 seconds.

• Over 160,000 pieces
of student written work
• Annotated by
experienced teachers
• Ideas and feedback to