But as we lower the concentration of enzyme catalyse the rate of reaction will also be low. This is because there is a lot of hydrogen peroxide in contrast with enzymes, as a result of this, the active sites will already be occupied by some other substrate and the other substrates will need to wait for their turn. In this case the rate of reaction will be slower, i.e. low amount of oxygen will be produced.
No matter how much concentration of enzyme is present, the reaction will eventually stop, as at very high enzyme concentration the substrate concentration may become rate limiting, so the rate stops increasing. Normally enzymes are present in cells in rather low concentrations.
Substrate concentration: -
The rate of an enzyme-catalysed reaction shows a curved dependence on substrate concentration. As the substrate concentration increases, the rate increases because more substrate molecules can collide with enzyme molecules, so more reactions will take place. At higher concentrations the enzyme molecules become saturated with substrate, so there are few free enzyme molecules, so adding more substrate doesn't make much difference
Inhibitors: -
Inhibitors are substances, which alter the enzymes activation.
There are two main types of inhibitors:
- Competitive inhibitor
- Non-competitive inhibitors
Competitive inhibitors: -
Competitive inhibitors have the same shape as substrate and therefore fit into the active site of the enzymes, blocking the active site so that substrate can’t enter, also slowing down the reaction.
Non-competitive inhibitors: -
Non-competitive inhibitors don’t have the same shape as substrate and therefore don’t compete with active site. Non-competitive inhibitors bind at some other point on the enzyme molecule. This changes the shape of the active site so an enzyme substrate complex can’t be formed. As a result no enzyme-substrate complex can be formed.
These inhibitors shouldn’t effect my investigation as none are added.
Cofactors, Activators/coenzymes: -
Some enzymes, which influence the reaction, are non-protein. They are attached to the enzymes and are called a prosthetic group. Inorganic cofactors are called activators. They
Can attach them selves to the active site to make their shape more efficient. Organic cofactors are called coenzymes. Coenzyme also influences the functioning of enzymes but is not bonded to the enzymes. They transfer chemical groups from one enzyme to another.
So, both activators and coenzymes speed up the chemical reaction.
Prediction:
I predict that as the enzyme concentration increase; the rate of reaction and the volume of oxygen in two minutes will also increase.
This is because; there are more enzyme molecules available which means there is more accessibility of more active sites. So when the enzyme collision occurs, the probability of empty active site is high. This means large amount of hydrogen peroxide will be broken down. Consequently, as the enzymes breakdown hydrogen peroxide there will be little left of this substrate, resulting in the high amount of oxygen. I think if the enzyme concentration is doubled from 25% to 50% concentration the amount o oxygen produced will also double. The more the amount of enzymes means there will be more active site present, so there will more turnover number of oxygen produced.
Further as adding more water distills the enzymes concentration, less reaction will take place as there are less enzyme molecules reacting with the substrate, as there is a lot of hydrogen peroxide in comparison with enzymes. Restricted amount of enzymes means limited quantity of active site. So, even though there will be collision occurring between enzymes catalysed and substrate hydrogen peroxide, but very low reaction will occur as enzyme molecule is already occupied by another hydrogen peroxide.
For example, 50% of enzyme concentration means half of the enzyme in a solution. This should produce a volume of X, but if we double the enzyme concentration the volume of oxygen produced should be 2X in two minutes.
This is the equation of the reaction that will occur in my conical flask.
Hydrogen peroxide + celery tissue Water + Oxygen
Substrate + Enzyme catalyse Water + Oxygen
H2O2 + Enzyme catalyse H2O2 + O
I also predict that as we lower the enzyme concentration, i.e. add more distilled water the volume of oxygen produced will also decrease
Hydrogen peroxide: -
It is a colourless, heavy, strongly oxidizing liquid, H2O2, capable of reacting explosively with combustibles and used principally in aqueous solution as a mild antiseptic, a bleaching agent, an oxidizing agent, and a laboratory reagent.
Apparatus: -
All the apparatus, which involve to carry on my experiment, are listed below.
-
Gas syringe 100cm3
-
Syringe of 10cm3 (small syringe) X3
- Hydrogen peroxide 6% concentrated
- Rubber bung with delivery tube
- Varying concentrations of enzyme catalyse
- Clamp stand with boss
- Digital Stop clock
- Small beakers X3
- Goggles
-
Conical flask 250cm3
Gas Syringe
I will be using the gas syringe to collect the oxygen gas released from the reaction. This is an accurate way of measuring and has a capacity of 100cm.
Small syringe
I will be using a small syringe, so that I can measure the volume of solutions I will be using precisely. With the aid of small syringe no solution will be left behind.
Conical Flask 250cm3
This is where all of my reactions will be taking place; I will also be washing theflask after each experiment.
Small beakers
I will use the assist of beakers, which will be containing the solutions, substrate and catalyse, so that I take them with the help of my small syringe.
Stop Clock
This is probably the most important gadget I will be using. It will be used to measured the time of my experiment, so that I will be able to take the readings at ten-second intervals for two minutes.
Diagram
Technique:
- Have handiness to all the apparatus listed above and make sure they are washed properly with distilled water to prevent impurity.
- Set the apparatus as shown in the diagram and have three solutions, celery tissue enzyme, hydrogen peroxide and distilled water in three separate beakers each with it’s own small syringe. Make sure that the syringes stay with the same solution.
-
With caution, pull up 10cm3 of hydrogen peroxide from the beaker and allow the syringe to rest in the beaker. Depending on the concentration of the enzyme catalyse you are using make up the solution. For this method we are using 100% of enzyme concentration. If the enzyme concentration is 80%, we will add 8cm3 of enzyme catalyse and 2cm3 of distilled water.
- Pour the syringe of enzyme catalyse into the conical flask. Double-check all the apparatus to carry on with experiment.
- Then empty the small syringe of hydrogen peroxide into the conical flask. At exactly the same time stop clock must be started and then as soon as possible the bung must be sealed to prevent any loss of oxygen.
- Record the readings at ten-second interval from the gas syringe. This must be recorded in the same table as I shown on the next page. This must go on for two minutes, regardless of whether the reaction is going on slowly or at the speed of light.
- The experiment is now complete. Now the experiment must be repeated two more times for the 100% concentration to find an accurate value. Record the answer and work out the value.
- Now the experiment should be repeated for the various concentrations of enzyme, such as above, three times for each concentration and averages worked out.
- Whole experiment is completed once. To get the exact values I am going to repeat this experiment again. I will again repeat each concentrations three times and work out the average. In this way I will be having two sets of averages for every concentration for accuration.
- My experiment is now complete.
This is for the X% concentration catalyse.
These are the results of X experiment.
Risk Assessment
As I am using hydrogen peroxide, I have to be very cautious while handling it.
Hands must be washed after the experiment. Goggles must be worn at all time to avoid any eye contact with eye. If hydrogen peroxide is split up it must be wiped and cleaned straightaway. Make sure all glass equipments are away from the table edges to avoid any breakage or falls.
Variables I will be controlling:
The variables I will control are temperature, substrate concentration, pH, light intensity, shaking, and the amount of time, reaction will go on for and the apparatus.
Temperature
As we know that the temperature increases the kinetic energy of the molecules and make them collide faster, ending in the rise in reaction time. To make sure it is a fair test all the experiments will be carried out in the same environment at a constant room temperature. This will ensure every experiment has same temperature. My experiment will be conducted in one day at once, so the temperature shouldn’t affect my experiment or my results.
Substrate concentration and volume
My substrate concentration will be constant through out the experiment. It will be 10cm3 .It will keep same, as it is a fair test. I will do this by using hydrogen peroxide from the same bottle. If there is a higher volume or concentration it will ruin my experiment.
pH
The pH changes the shape of enzyme. The enzyme we are using work at neutral condition, which is 7pH. Therefore, the pH of my solution well be 7. I will make sure that the pH is always 7, no less no more.
Light intensity
Light gives out heat energy as well as light. And we know that heat produces the kinetic energy which increases the level at which the reaction is taking place. I can not control light but I will try to make sure that light is constant through out experiment.
Shaking
If the conical flask is shaken the particles are provided with kinetic energy which increases the rate of reaction. As it is a fair test, I am going to make sure that the conical flask isn’t disturbed in any way to prevent it being an unfair test.
Reaction time
No matter how fast or slow the reaction was, I am going to stop the reaction time at two minutes. I will then record the oxygen collected. If the reaction goes on longer then two minutes, the experiment is going to be an unfair one. It will produce bias results between the concentrations.
Apparatus
I will be using the same apparatus for each experiment. If I have the same apparatus the experiment will be same. Further more, it will rule out any chance of it being an unfair test.
The one variable that will change
Enzyme concentration:
Enzyme concentration greatly affects the rate of reaction and is the only variable I will be changing in my experiment. It’s so because I want to measure the rate of reaction i.e. the oxygen produced in different enzyme concentrations.
To change the enzyme concentration I will dilute it with distilled water. This will give different concentrations of enzyme.
This is the way we make different concentrations of enzymes.
10cm3 = 100% concentration
8cm3 + 2cm3 = 80% concentration
6cm3 + 4cm3 = 60% concentration
4cm3 + 6cm3 = 40% concentration
2cm3 + 8cm3 = 20% concentration
My hypothesis for this is the more the concentration of enzyme, the more rate of reaction, as with more enzymes we will also have more active sites available to catalyse the substrate, hydrogen peroxide. As we lower the enzyme concentration the rate of reaction will also decrease, as there are only a restricted amount of active sites. . So, although there will be collision occurring between enzyme catalyse, and substrate hydrogen peroxide but very low reaction will occur as enzyme molecule is already occupied by another hydrogen peroxide, as a result of this the rate of reaction will be lower and the amount of oxygen produced will be less.
Implementing Results
The results of experiment 1 and 2 are given below and so are the concentrations.
Analysis
As I now have all the information I needed, I can now contrast my results with my predictions.
I predicted that as the enzyme concentration increases; the rate of reaction and the volume of oxygen in two minutes will also accelerate.
By observing my first graph briefly, it can be clearly seen that as the amount of enzymes increases, the rate of reaction increases, i.e. there is more amount of oxygen collected.
Looking at my 20% graph, I can clearly see that the amount o oxygen produced is minimum, meaning the rate of reaction is slowest of all. The reason of this can be explained by my background knowledge. Firstly I know there is a lot of hydrogen peroxide in contrast with enzymes. Limited amount of enzymes means limited amount of active site. So, although there will be collision occurring between enzyme catalyse, and substrate hydrogen peroxide but very low reaction will occur as enzyme molecule is already occupied by another hydrogen peroxide.
In the above situation as the enzyme’s active site is already being occupied by another substrate, it’s not possible for colliding substrate to be broken down.
In contrast I can also see that when the concentration of enzyme is 100%, the rate of reaction is higher. This is because a large amount of enzymes means availability of more active sites available is high. So when the enzyme collision occur, the probability of empty active site is high. This means large amount of hydrogen peroxide will be broken down. Consequently, as the enzymes breakdown hydrogen peroxide there will be little left of this substrate, resulting in the high amount of oxygen.
It should be noticed that regardless of enzymes concentration the data of oxygen collected begins to level off. The reason for it is that the amount of hydrogen peroxide
Left is reduced as it is broken down. In this situation the amount of substrate present is limiting the rate of reaction. As a result amount of oxygen produced becomes less.
In conclusion when the concentration of substrate is constant, the enzymes are responsible for the rate of reaction. But when there is large amount of enzymes present, and then there are the increase enzyme-substrate complexes. Naturally, ending up as the increase in the volume of oxygen. Finally, it should also be noticed that high amount of oxygen means high rate of reaction. We notice, that in the end volume of oxygen is levelling off. This is because the limited amount of substrate, hydrogen peroxide left. This limits the rate of reaction and accordingly volume of oxygen in the syringe.
This sums up the results of my first two graphs. I will now write down initial rate of reaction in first thirty seconds of my two experiments with the various concentrations of enzymes.
These results are also plotted on the graphs with enzymes against the initial rate of reaction.
By looking at the graphs we can see the in the initial 30 seconds of the reaction most oxygen has been collected. This is because at the start of the reaction lots of active sites are available and are ready to breakdown hydrogen peroxide, which in turn gives oxygen as a product. This means at the initial stage the reaction is quite fast. After this initial stage, substrates fill up the active sites of the enzymes, and other substrates have to wait for their turn to be broken down.
The graphs also show us that there are various volumes of oxygen produced with different concentrations of enzymes. With fewer enzymes there is low rate of reaction. This is because low enzymes means low active sites and as a result less enzyme-substrate complexes are formed ending in less oxygen. When there is an increase in enzymes concentration there is more oxygen produced, as more enzymes means exactly the opposite of first situation.
Now I have put up the table showing the total volume of oxygen collected in two minutes in various concentrations of enzymes.
Here are two graphs that I have drawn so I can see my results more easily.
Now observing these graphs we can see that oxygen collected over two minutes is approximately the same as the initial rate of reaction. This is because the amount of oxygen stored in first thirty seconds must be the maximum amount of oxygen produced during the reaction enzyme catalyse and hydrogen peroxide, substrate. The main reason of the reaction slowing down after 30 seconds is that as the reaction goes on there is quite a less amount of substrate left. This mainly happens in 100% enzyme concentration. So in this case substrate concentration is limiting the reaction.
In addition, the reaction becomes faster as the enzyme concentration increases ending in more volume of oxygen. Although there is a limited amount of hydrogen peroxide, but as it is in excess amount enzymes can’t breakdown all of it. This is clearly demonstrated in my previous graphs, where oxygen produced in two minutes by 100% enzyme concentration was about 82cm3, while oxygen produced by 20% enzyme concentration is about 12cm3. This shows that hydrogen peroxide has the capacity to be broken down by enzymes and to produce large amount of oxygen.
Ratings: -
I think my experiment was a success. I found the results I was looking for. My experiment could be improved by using the other equipments available to me.
I have also got a few anomalous results. This may the result of some delusions in my experiment. One of these is that there is a lot of difference between the oxygen collected at different enzyme concentrations. Although, the enzyme concentration is only decreasing from 100% to 80%, but the volume of oxygen produced decreases dramatically. Another flaw could be that I was timing my reaction with a digital clock; the clock didn’t start until the bung was firmly placed on the conical flask. This means some of the oxygen produced might not have been recorded. This error would be present in each of my experiments. I think the readings for the first 10 seconds might not be authentic.
This experiment was particularly hard as I was carrying the experiment individually. It was difficult to get everything done at the same time. One example of it is initiating the task by starting the clock, putting hydrogen peroxide in the conical flask and securing the bung at the same time. This was a main defect in my experiment and it might have affected the reliability of my experiment. To get accuracy in my result I repeated each concentration three times and then plotted the averages on my graph. I then repeated the whole experiment one more time. I think this would have improved the reliability of my experiment.
Another restriction of my experiment was the gas syringe. This also might have prevented me from getting the accurate ratings. The thing, which could be more precise and accurate, would be gas burette. This unfortunately was not available to me. Another flaw was that experiment was conducted in the open air; this means I couldn’t see if there was any oxygen escaping. To prevent this problem I could have conducted the experiment under water. This way I could see if there is any oxygen escaping in the form of water bubbles. If there were any bubbles I could have stopped and made the improvements in my apparatus. Also different celery sticks have different amount of enzyme concentrations. So to improve this I could have got the entire enzyme at once and mix them all up in the blender; this would make the enzyme concentration spread out evenly. By this way all the experiment would roughly have the same amount of enzyme concentration. Another limitation was that oxygen was escaping from the conical flask, before I could fix the bung. Consequently, there would be less oxygen in the conical flask at the final stage then there should be. However this error shouldn’t really undermine my end result as I repeated the experiment twice, but only make the initial rate of reaction a more gradual line than a steep line.
My gas syringe could measure up to + - 0.5 cm3. This is accurate but still an error in accuracy of results. This is not a high error for such a large quantity of gas it collects. It is so minute that it may even still question the precise measurements. This error is low such a highly precise piece of equipment. This wouldn’t affect my experiment, as I was collection oxygen it doesn’t have to be more accurate. This wouldn’t affect the curve of my result as same gas syringe was used for each experiment.
I also didn’t know the exact concentration of enzyme. I varied the concentrations by diluting its volume and mass. This may have affected the over all results, as some enzyme solution may have been slightly more concentrated then others. This might also have affected my trend line, as more hydrogen peroxide would be broken down then others. I tried my best to keep all the concentrations same by carefully diluting enzyme catalyse by distilled water. The oxygen gas I collected was collected at room temperature. This might have made the oxygen expand in the gas syringe and the volume of oxygen look more then it actually was. This error was overlooked, as the error would be very small and wouldn’t count. If these errors were solved, I think my results will remain the same. This wouldn’t affect my overall results. The syringe I used to measure oxygen was accurate up to + -0.04cm3 . This error might have been more significant if I had used different apparatus to measure the quantity of hydrogen peroxide more precise. Hydrogen peroxide is very strong oxidizing agent; too much or too little of it could affect my end results. Using the syringe makes the quantity of hydrogen peroxide more precise. The error of the syringe is so small I believe it wouldn’t change my line of best fit or invalidate my conclusion.
Any of the errors I have mentioned above could have caused the eccentric results in my investigation. The error most significant was the fact that we didn’t know the exact concentration of enzyme catalyse in the solution each time for different experiments. From our background knowledge we know that a small amount of enzyme can bring a lot of change. I don’t think I could do any thing about this error, as it is impossible to measure the concentration of enzyme in each solution.
I think the results I achieved are substantially authentic. This is because the values for each experiment over the amount of oxygen were not so spread out. Also as the experiment was repeated twice it cut down quite a lot of anomalous results. I also calculated average; it should have improved the accuracy.
The results I got were also fairly accurate. This is because they were as I was expecting them to be. All the repetitions were closed to each other and this strengthened my overall end results. This gave me the line of best fit in my graphs.
Precision is a component of accuracy, but it is not the same as accuracy. It can be seen in the equipments I used. This can again be seen in the concentration of enzyme concentration as I have explained above. I have listed my limitations and errors and how I could overcome them. My conclusion does agree with my hypothesis in that, the amount oxygen as well as the initial rate of reaction increases, as the rate of reaction gets higher. On the whole my experiment is a well-grounded success, in spite of all the errors and restrictions.
References
Collins Advanced Science _ Kathryn Senior and Mike Boyle
Comprehensive Biology _ Lam Peny Kwan
Biology 1 _ Mary Jones, Richard Fosbery and Dennis Taylor
New Understanding Biology _ Glenn and Susan Toole
Class Notes
Advanced Biology _ Michael Kent
Content page
- Front Page
- Content Page
- Aim and background knowledge
- Background knowledge
- Background knowledge
- Background Knowledge
- Background knowledge
- Background knowledge, prediction
- Prediction
- Apparatus
- Apparatus
- Diagram
- Methodology
- Risk assessment and the variables I will control
- The variables I will control and the variable I will be changing
- Result
- Result
- Result
- Result
- Result
- Graph figure 1
- Graph figure 2
- Analysis of results
- Analysis of results
- Graph Figure 3
- Graph Figure 4
- Analysis of graph
- Graph figure 5
- Graph Figure 6
- Analysis of graph
- Ratings
- Ratings
- Ratings and References
Biology Investigation
The
Breakdown
of hydrogen peroxide,
substrate, with
celery tissue
enzymes,
catalase
By
Tayyeba Shoaib
Tayyeba Shoaib
Biology coursework