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Chemistry AS-level Titration coursework


The aim of this GCE chemistry investigation was to find out the accurate concentration of sulphuric acid in a solution using, titrations. This acid solution is thought to have a concentration between 0.05 and 0.15 mol dm-3, but as part of this investigation I was asked to find out the accurate concentration of sulphuric acid.

Fair testing:

Definition:

‘Fairness’ implies that the outcome of the activity truly depends on what is being investigated, and is not being distorted by other external factors. Therefore a fair test is one where all the variables are kept constant or the same, except the variable that is being investigated. A variable is anything that can change and which may influence the outcome of the investigation.

List of variables:

The different variables are:

  • Amount of sulphuric acid
  • Concentration of sulphuric acid
  • Mass of alkali- anhydrous sodium carbonate (2.65g)
  • Indicator

Variables that needs to be controlled:

The variable that needs to be controlled are as follows:

  • The mass of the alkali (this has to be determined first before the titration)
  • The amount of sulphuric acid.

These variable needs to be controlled because even the slightest miss calculation of the mass of the alkali of the amount of sulphuric will bring about a huge change in the values that represent the titration.

Statement of fairness:

           

For the investigation to be fair, the mass of the alkali used must be exact, the temperature of the surroundings must be constant and all equipment must work properly.

Anhydrous sodium carbonate (working out the mass of anhydrous sodium carbonate).

The molecular formula for this substance is: Na2CO3

Relative masses can be used to compare the masses of any chemical species. Much of the matter is made up of compounds. The Relative Molecular Mass of a compound is the sum of the masses of all the atoms present in the molecule. It is often shortened to RMM. The RMM is used in many sorts of calculations in chemist. And for calculating this I will need to know the relative atomic mass of a substance. This is can be found by using the periodic table.  

So here I will work out the molecular mass of anhydrous sodium carbonate:

Na2 – 23.0 (atomic mass) x 2 (atoms)            = 46

   C – 12 (atomic mass)                                   = 12

 O3 - 16 (atomic mass) x 3 (mass)                    = 48

                                                                     _______

                                                                          106

To work out how much of anhydrous sodium carbonate I need to use the above information to work out the amount of a substance in moles and then calculate the molar mass.

Chemists use this quantity (amount of a substance) for counting atoms. The amount of substance is:

  • Given by the symbol n.
  • Measured using an unit called mole (mol)

A mole is the amount of substance that contains as many single particles as there are in exactly 12g of carbon 12 isotope. Below I am going to provide the formula which I used to work out the amount of moles.

Mass of a substance = amount of a substance in moles x molar mass

Amount of substance = mass of substance/ molar mass

No of moles:  volume x concentration

 

No of moles = 0.25cm x 0.1moldm3 => 0.025 mol

This amount represents the number of atoms that are present in one mol of a substance. But are 0.25cm of the substance the, the actual number of atoms which will be present in the solution can be found by the multiplying the mole by Avogadro’s constant. This is shown below:

Number of anhydrous sodium atoms: 0.025mol x 6.02x10^23 =  1023

As I have found the amount of a substance now I have to work out the molar mass of the substance to find out how much of anhydrous sodium carbonate solution I will need. This method of working out this is shown in the next page.

Molar mass, M, is the mass of one mole of a substance. The units of molar mass are   g mol-1.

The general formula for finding the molar mass is ; n = mass in grams/ molar mass

Mass= amount of substance in moles x molar mass

As we only need to find the mass of the substance we just need to multiply the amount of substance with the molar mass (which is the RMM: 106), and by working out this amount I will be able to determine what quantity of anhydrous sodium carbonate is needed and this is shown by the calculations below:

Mass = 0.025 x 106 grams

Theory

A titration is a laboratory procedure where a measured volume of one solution is added to a known volume of another reagent until the reaction is complete. Because volume measurements play a key role in titration, it is also known as volumetric analysis. A reagent, called the titrant, of known concentration (a standard solution: in this case the standard solution is 250 cm3 of sulphuric acid) and volume (in this case the volume is 250 cm3) is used to react with a solution of the analyte, (anhydrous sodium carbonate) whose concentration is not known in advance. But as I was asked to find out the accurate concentration; I was given an approximate concentration of sulphuric acid which was between 0.05 mol dm-3 and 0.15 mol dm-3. Using a burette to add the titrant, it is possible to determine the exact amount that has been reacted when the endpoint is reached.

The endpoint is the point at which the titration is complete, as indicated by the colour change in the solution as determined by the indicator used. In this investigation I used the indictor methyl orange with a ph of 2.9 to 4.6. In a most common strong acid-strong base titration; the endpoint of a titration is when the pH of the reactant is just about equal to 7, and often when the solution permanently changes color due to an indicator which satisfies if the reaction is complete or not.

This experiment or titration investigates the reaction between a strong acid (sulphuric acid) and a weak alkali (anhydrous sodium carbonate), so there fore the ph indicator which I used was methyl orange, which at the end point turns red. A ph indicator is a halochromic chemical compound that is added in small amounts to a solution so that the pH (acidity) of the solution can be determined easily. The ph indicator is a chemical detector for hydrogen ions (H+). Normally, the indicator causes the colour of the solution to change depending on the pH. PH values above 7.0 are basic, and pH values below 7.0 are acidic. Solutions with a pH value of 7.0 are neutral. But my indicators ph level was below 5.0 so it proves that the solution is acidic.

During this experiment I have used many types of equipment; as they will help me to find the precise number of results (this means that I will repeat the experiment a number of time until I find measurements close to each other or which are in a difference of 0.01cm3) which will help me to find the accurate amount of sulphuric acid concentration in the solution (this is the measurement close to the real value). So the uses of these instruments are illustrated below.

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Titrations are most commonly recorded in curves; is the independent volume of the titrant, while the dependent is the ph of the solutions. The curve is sigmoid and presents a significant variation of pH at the equivalence point, which allows an easy determination of the latter.

The progress of a titration is usually monitored with an indicator. Frequently, during a titration it is also useful to monitor the progress of the titration with a graph. This graph is known as a titration curve. Such a curve reflects the changes in pH that occur as ...

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