# To Determine the Spring Constant of a Helical Spring and a Value for the Earth's Gravitational Field Strength

Extracts from this document...

Introduction

A2 COURSEWORK AIM: To Determine the Spring Constant of a Helical Spring and a Value for the Earth's Gravitational Field Strength OUTLINE: I will be using a coiled spring and using its elastic properties to determine a value for its spring constant and it's oscillating properties to calculate a value for the earth's gravitational field strength, to compare to the actual value for the earth's gravitations field strength. *SPRING CONSTANT* Hooke's Law states - "The Force a Spring Exerts on a Body is Directly Proportional to the Displacement of the System (The Extension of the spring)" i.e. Force Extension So... Force = K x Extension F = Ke So K = F/e * For this experiment I will have to use the same spring throughout because the spring constant values vary from spring to spring. ...read more.

Middle

so they don't have to be reweighed each time they are used. * The length of the spring will be measured without any weights on it to establish a point to which the extensions can be compared. (This value is to be recorded) * The first weight is then to be added, (10g) and the extension recorded. (The extension is the original reading taken from the new recorded length) * This procedure is to be repeated until 100g is the weight. * These weights are then replaced by a 100g weight, and the experiment will continue using 100g weight changes. * When a value of 800g is reached, the experiment is to be repeated in reverse (i.e. ...read more.

Conclusion

274 296 275 274.667 800 322 301 321 300 320 299 300.0 My graph will be Extension against Mass as below, but these results will only include my results from 100g upwards because the results below this value are insignificant values on my graph: Extension (m) (x10-3) 28.0 73.7 109.0 149.0 187.3 255.3 274.7 300.0 Mass (kg) (x10-3) 100 200 300 400 500 600 700 800 ANALYSIS OF RESULTS AND GRAPH: There don't appear to be any anomalous results from my graph. From my graph I can calculate the value for K, the spring constant from the formula: K = F/e From the formula F = mg, we can see that: K = mg/e The graph shows mass (m) against extension (e), so: K = mg/e = 740x10-3 x 9.81/285x10-3 =25.47 *EARTH'S GRAVITATIONAL FIELD STRENGTH* ...read more.

This student written piece of work is one of many that can be found in our AS and A Level Waves & Cosmology section.

## Found what you're looking for?

- Start learning 29% faster today
- 150,000+ documents available
- Just £6.99 a month