• Join over 1.2 million students every month
  • Accelerate your learning by 29%
  • Unlimited access from just £6.99 per month

To investigate the amount of O2 released at different of concentration of enzyme catalyse in (Yeast).

Extracts from this document...


To investigate the amount of O2 released at different of concentration of enzyme catalyse in (Yeast) Scientific background: Introduction: Many chemical reactions take place inside a cell. The speeds at which the cell reactions take place are controlled by catalyst called enzymes, or we can say enzymes are biological catalyst. Enzyme speed up the rate of reaction without it self being used. Some enzymes, such as pepsin and trypsin, which bring about the digestion of meat, control many different reactions, whereas others such as urease are extremely specific and may accelerate only one reaction. Enzymes are large proteins that speed up chemical reaction. In their round structure, one or more polypeptide chains twist and fold, bringing together a small number of amino acids to form the active site, enzyme active site is the method of key and lock this means the active site is lock if the shape of substrate do not match exactly. This ensures that the enzyme is not specific for that chemical reaction. There are thousand of enzymes in living organisms, and they are specific, this means that each enzyme catalyses a certain chemical reaction. An enzyme has an active site, which has a unique shape into which only a substrate of same unique shape can be fit. ...read more.


Method: There are many ways in which the amount of Oxygen released could be affected. I have chosen the concentration of enzyme. 10 ml of 4 % yeast has been taken and accepted it as 100 percent to calculate the different concentration. First the dilute yeast has been made. Five different concentration of yeast that are 100%, 80%, 60%, 40% and 20% are made as I have shown on the table of yeast concentration. To collect out data I measured the amount of O2 produced from the reaction, by letting it pass through a tube and let it displace the water in the measuring cylinder. The experiment carried out three times for each concentration with 3ml of yeast and hydrogen peroxide. The step bellow followed for recording the O2 released during the reaction. a. The 3 ml of hydrogen peroxide taken in small syringe. b. 3 ml of yeast has taken in a small syringe. c. Pure the yeast in test tube. d. Add 3 ml of hydrogen peroxide. e. The test tube closed immediately and the stopwatch started. f. The time keeps constant for 1 minute. g. The amount of O2 released from the reaction measured by the 100 ml Glass cylinder. ...read more.


Again when I see the graph it is not straight line. I have drawn the graph for the average of 3 experiments that I did for each concentration. There are a few different results that can be determined when I add straight line. I can say there are two anomalous average results, which are far from the straight line drawn. And I think it is not possible to take precise readings from the graph between the plotted points since insufficient readings. To do a more accurate experiment in the future. Several precautions or alteration can be made. For example for experiment of enzyme with hydrogen peroxide. I can use another enzyme like potato discs. And I can use more potato disc to provide more enzymes for decomposing H2O2.The average readings could be improved by repeating to reduce the average of anomalous results. The increase in rate of reaction is the reason of existing more catalyse enzyme that provide the more active site for decomposition of hydrogen peroxide. In this experiment 5 enzyme concentrations were considered. The formula for this chemical reaction is as follows. 2H2O2 H2O+ O2 My result supports the scientific knowledge that I have written about the enzyme and hydrogen peroxide. As concentration increase if provide more active site and the theory of key a lock apply here, because it is the same enzyme to work for decomposition of hydrogen peroxide to water and oxygen gas. 1 ...read more.

The above preview is unformatted text

This student written piece of work is one of many that can be found in our AS and A Level Molecules & Cells section.

Found what you're looking for?

  • Start learning 29% faster today
  • 150,000+ documents available
  • Just £6.99 a month

Not the one? Search for your essay title...
  • Join over 1.2 million students every month
  • Accelerate your learning by 29%
  • Unlimited access from just £6.99 per month

See related essaysSee related essays

Related AS and A Level Molecules & Cells essays

  1. In this experiment I will be investigating and analyzing the factors affecting the rate ...

    Temperature: varies rate of reaction due to more collision * ·PH: shape of active site For my preliminary work I chose to do temperature. This is because temperature can be explained scientifically in a much more complex manor this would help me gain more marks in this experiment as there is more to talk about.

  2. Investigating and analyzing the factors affecting the rate of decomposition of hydrogen peroxide by ...

    As there are several factors affecting the rate of decomposition of hydrogen peroxide, I only needed to investigate and experiment one. Some the factors that affect enzyme activity are: * Enzyme concentration: must maintain this by keeping bead size the same * Substrate concentration: varys the rate of reaction *

  1. I am going to investigate how the temperature affects the catalyse enzyme on hydrogen ...

    the enzyme will react differently to each temperature this is due to the collision theory, the collision theory is when lots of collisions are made the rate of reaction will be higher than when the is relatively few collisions. Analysis I have drawn two graphs, one showing the total of

  2. Hydrogen Peroxide and catalyse.

    chloroplasts and mitochondria, the three organelles often being in close proximity within the cell. The photorespiratory pathway is shown on the right. This shows how hydrogen peroxide is produced and the functions of the peroxisome as part of the photorespiratory pathway.

  1. Hydrogen peroxide (H2O2) an Enzymes Investigation

    Transferring energy from one organism to another supplies kinetic energy to the reacting molecules and so they move with more speed. If you through a ball twice and caught it there would be a higher chance of dropping it if you were only to do it once.

  2. effect of different concentration of H2O2

    I.e. you could have 0% inhibitors to 100% inhibitors. This would show you what affect in inhibitors have on enzyme activity. Catalase Enzymes is very important to life as if it did happen your body would allow Hydrogen Peroxide to build up in the cells. This would cause harm to your body.

  1. Catalyse Investigation

    This meant that if the test for glucose proved negative, then sucrose could not be digested without the presence of the active enzyme sucrase and that it was only the effect of temperature on the enzyme that was being measured in this investigation.

  2. An experiment to investigate the effect of enzyme concentration on the rate of milk ...

    Also the same amount of milk and bile must be added to maintain a constant pH. However the pH throughout the test will be different due to the increased amounts of enzyme being used causing a quicker pH change further towards acidic conditions.

  • Over 160,000 pieces
    of student written work
  • Annotated by
    experienced teachers
  • Ideas and feedback to
    improve your own work