• Join over 1.2 million students every month
• Accelerate your learning by 29%
• Unlimited access from just £6.99 per month
Page
1. 1
1
2. 2
2
3. 3
3
4. 4
4
5. 5
5
6. 6
6
7. 7
7

# You are to investigate the factors that affect the current through a light bulb.

Extracts from this document...

Introduction

You are to investigate the factors that affect the current through a light bulb.

Introduction:

My theory of current is that it is the rate at which charge flows around a circuit.

Current (I) =         Charge flowing (Q)

Time (T)

Current (I) =         Power (P)

Potential Difference (V)

Factors that affect current are:        Voltage or ‘The potential difference’

Resistance

Amount of charge flowing

Time

The length/thickness of the wire

Electrical circuits:

An electrical cell has two terminals. The chemical reaction the cell makes the negative terminal electron rich and the positive terminal electron short. If the terminals are joined by a piece of conducting wire to make a circuit, then electrons flow between them. The electrons flow from the negative terminal to the positive terminal. This is called the electron current.

A conventional current, which is thought of as flowing from the positive to the negative has been used for many years. Since it flows from the positive to the negative:

The conventional current flows in the opposite direction to the electron current.

Volts:

The part of the electromotive force that

Middle

0.24

not visible

0.3

0.09

0.09

0.09

0.27

not visible

0.4

0.1

0.09

0.09

0.28

not visible

0.5

0.1

0.1

0.1

0.3

not visible

0.6

0.11

0.11

0.11

0.33

not visible

0.7

0.11

0.12

0.11

0.34

Just Visible

0.8

0.12

0.12

0.12

0.36

visible

0.9

0.13

0.13

0.12

0.38

visible

1

0.15

0.14

0.14

0.43

visible

1.1

0.15

0.15

0.15

0.45

brighter

1.2

0.16

0.16

0.15

0.47

bright

1.3

0.17

0.16

0.16

0.49

bright

1.4

0.17

0.17

0.17

0.51

bright

1.5

0.18

0.18

0.18

0.54

bright

1.6

0.18

0.18

0.18

0.54

alot brighter

1.7

0.18

0.19

0.19

0.56

alot brighter

1.8

0.19

0.19

0.19

0.57

Conclusion

This graph means that as the voltage increases so does the current increase, this is shown by the graph corrolation, and by the curvature of the graph indicating that more current is produced with less voltage.

A revised theory from this graph explaining my results and graph is that current seems to increase more than the amount of voltage put in. Creating a curved line.

I believe that my predictions were almost correct, yet now I can see that I made some elementary errors.

Evalutaion:

Advantages and Disadvantages of the experiment are that it went well under planning yet I failed to conclude in sufficient detail, I expected my results and these I gained from my scientific knowledge.

I believe that I could re do the experiment to gain more reliable results, and I have found that the graph shows that my earlier theories were correct. Indecating a well planned prediction.

Patterns in the graph are that the current goes up as the voltage is increased.

Annommalies, I don’t think I have found any anomalies in my graph though if I did find any I would expect to find out that they were caused by incorrect measurements of the results or problems with the equipment, etc.

Aaron Jessop

11H

This student written piece of work is one of many that can be found in our AS and A Level Electrical & Thermal Physics section.

## Found what you're looking for?

• Start learning 29% faster today
• 150,000+ documents available
• Just £6.99 a month

Not the one? Search for your essay title...
• Join over 1.2 million students every month
• Accelerate your learning by 29%
• Unlimited access from just £6.99 per month

# Related AS and A Level Electrical & Thermal Physics essays

1. ## To Investigate How the Resistance of the Light Dependent Resistor Depends On the Current ...

And the voltage in the circuit is equal toV2 plus the voltage of R2. The Voltage in the circuit keeps the same and the voltage of R2 increases, so V2 decreases. 2. I predict that the graph of the resistance of the LDR against to the current of the light

2. ## Relationship between the current and voltage.

(The same process used for the 1-ohm resistor, to calculate the gradient was used.). The gradient for this graph was also proved to be 2.08. This is exactly the same as the figure received, when the resistance was calculated using the V=IR, which was rearranged to R=V/I.

1. ## Sensors cwk. The aim of this coursework is to construct a potential divider circuit ...

This is because the photons in the semiconductor do not have a high enough energy. Thus the electrons aren't supplied with the energy needed for them to jump the conduction band and conduct electricity, thereby lowering resistance.

2. ## Investigating how temperature affects the resistance in a wire

3. Having placed 'apparatus A' in the 250ml-measuring cylinder attach the wires from 'apparatus A' directly into the multi-meter. 4. Turn on the multi-meter and make sure that it is recording the appropriate measurement (i.e. ohms) and that it is functioning properly.

1. ## Investigating The Characteristics Of A Light Bulb.

4 volts: V/V I/A 0.30 0.27 0.34 0. 1 0.44 0.38 0.57 0.46 0.72 0.51 1.20 0.62 1.70 0.72 I then turned the power supply to 6 volts, and I noticed that the current started to get higher than the voltage.

2. ## To find the factors that affect the amount of E.M.F. being produced. The amount ...

Green wire - attached to oscilloscope carrying the electro-motive-force to it to be measure. Planning Safety precaution * Electricity is dangerous therefore be careful while connecting the circuit by having the power supply turned off at start. * Wire striper is sharp therefore while stripping careful not to cut your hand.

1. ## To investigate the effects of two different variables on a solar cell output.

Distance directly affects the intensity of the light, and as distance increases, the light intensity decreases. We can see this in the below formula which shows us to what extent the distance between the light source and solar cell affects the energy supplied.

2. ## To find which of the circuits, shown below, are most suitable to measure a ...

can assume that Circuit One is not very accurate for high resistances. For 25000?: Current in Resistor (I1) = 1 x 10-4 Resistance of R1 = 25000? Pd across Resistor from Ohms Law: V = IR V = 25000? x (1 x 10-4) V = 2.5V Current in V (I2)

• Over 160,000 pieces
of student written work
• Annotated by
experienced teachers
• Ideas and feedback to