Emma's dilemma.

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Investigation

To start my investigation I am going to start with something a little easier than Lucy this will help with trying to establish a general pattern and in turn the general formula.

I will start with the word IT

This is very simple the word has 2 letters and 2 possible arrangements for the letters.

Now I will try IAN

The number of letters that I have used has now increased to 3 but the number of arrangements has changed it has become 6.


I will now try the name LUCY

With Lucy the number of letters has increased to 4 and the number of arrangements has increased to 24. This is a strange result.

Ian 3x2x1=6 (number of combinations)

Lucy 4x3x2x1= 24 (number of combinations)

I can best describe how I came to this theory by using an example involving cards and spaces. If I have 4 cards and four spaces and I place one of the cards in one of the spaces I have three cards and three spaces. If I put another card  down I have two cards left along with two spaces if I do this again I have one remaining card and one space. If I fill this space then I have no cards and no spaces. This is the same with the letters for example of Lucy’s name. I found that by multiplying the number of places and letters there were to fill the places I could get the total number of arrangements for the word. This is called factorial notation and is symbolised by an !

Join now!

Factorial notation is multiplying the total number of letters by the previous consecutive numbers giving the total number of positions and therefore arrangements of the words.

Therefore the formula for total number of combinations for a word with no repeats is C=T! Where C is the total number of combinations and T is the total number of letters factorial. This is my theorem I must now test it.

My formula for a word with no repeats is C=T!

I will now investigate the name PAUL

Using my new formula I can estimate how many arrangements their ...

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