Emma's Dilemma

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James Clark 11LG Maths Coursework


14th January 2002

Emma’s Dilemma

The Problem:

Emma is playing with arrangements of the letters of her name.

One arrangement is

EMMA

A different arrangement is

MEAM

Another arrangement is

AEMM

Experiment:

For my investigation I have been asked to work out the number of different arrangements of the letters from the name Emma.

EMMA AMEM  

EMAM AMME

EAMM

MEMA

MMEA

MMAE

MAME

MEAM

MAEM

AEMM

I have found out that when the letter “E” is at the front of the name Emma, then there are three different combinations. The same rule applies when the letter “A” is at the front of the name Emma. There is an exception though, when the letter “M” is at the front of the name Emma then there are six different combinations.

Overall there are 12 different combinations for the name Emma.

For the second part of my investigation I have been asked to work out the number of different arrangements of letters from the name Lucy.

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LUCY UYCL YCLU

LCUY UYLC YULC

LCYU CULY YLCU

LYCU CUYL YLUC

LYUC CLYU

LUYC CLUY

ULCY CYLU

UCLY CYUL

UCYL YUCL

ULYC YCUL

From this second experiment I have found out that when the letter “L” is at the front of the name Lucy then there are six different combinations. The same rule applies to the letters “U”, “C” and “Y” in the name Lucy.

Overall there are 24 different combinations for the name Lucy

From the first two experiments I have noticed that the name Emma has half the number of combinations when compared with ...

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