Emma's Dilemma

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Maths Coursework                                                                                  

                                       Emma’s Dilemma

I will be investigating the different arrangements of letters of words, which don’t have any identical letters in them and those that do. Then I will try and find a formula that can calculate the total arrangements of letters of any word, which does not have any identical letters in it. I will also try and find a formula to find the total arrangements of words, which have some identical letters in them.

Firstly I will look at those words, which have no identical letters in them and then work out a formula that can find the total arrangements of letters in them. So I will begin by finding the total arrangements of a one-lettered word to finding the total arrangements of a four-lettered word. Thereafter I will try and predict the total arrangements of a five-lettered word and then I will check if I was correct by finding the total arrangements of it’s letters

Part 1

One-lettered word               
A               =1
There is only one arrangement for a one-lettered word.
Two-lettered word   
WE              
EW              =2                           

There are two different arrangements for a two-lettered word whose letters are all different.

Three-lettered word 

CAR CRA    

ACR ARC       =6

RCA RAC

There are six different arrangement for a three-lettered word whose letters are all different.

Four-lettered word 

LUCY LUYC LYUC LYCU LCYU LCUY  

ULCY ULYC UCLY UCYL UYCL UYLC    

CLUY CLYU CULY CUYL CYUL CYLU    

YUCL YULC YCUL YCLU YLCU YLUC      =24

There are 24 different arrangement for a four-lettered word whose letters are all different.

In a four-lettered word the total arrangements is 24 because in the word LUCY there are 4 letters and you can only get 6 different arrangements with each letter at the beginning. So the calculations for this would be 4 x 6 = 24.

For a five-lettered word there are 24 different arrangements with each letter at the beginning. So 5 x 24 =120. So I predict that a five lettered word, which has no repeated letters in it will have a total of 120 different arrangements.

Five-lettered word          
KEANO KAENO KANEO KANOE KAEON KAOEN KAONE KEAON KEOAN   KEONA KENOA KENAO KNEAO KNEOA KNAEO KNAOE KNOAE KNOEA KOEAN KOENA KONEA KONAE KOANE KOAEN

EKNAO EKNOA EKONA EKOAN EKAON EKANO ENKAO ENKOA ENOKA ENOAK ENAOK ENAKO EANKO EANOK EAKNO EAKON EAONK EAOKN EOAKN EOANK EONAK EONKA EOKNA EOKAN

AKENO AKEON AKOEN AKONE AKNOE AKNEO ANKEO ANKOE ANOKE ANOEK ANEOK ANEKO AENKO AENOK AEKNO AEKON AEONK AEOKN

AOKNE AOKEN AONKE AONEK AOENK AOEKN

NKAEO NKAOE NKOAE NKOEA NKEAO NKEOA NEKOA NEKAO NEAKO NEAOK NEOKA NEOAK NAKEO NAKOE NAEKO NAEOK NAOKE NAOEK NOKAE NOKEA NOEKA NOEAK NOAEK NOAKE

OKEAN OKENA OKNEA OKNAE OKANE OKAEN OEKAN OEKNA OENKA OENAK OEAKN OEANK OAKEN OAKNE OANKE OANEK OAEKN OAENK ONKAE ONKEA ONEKA ONEAK ONAEK ONAKE              = 120

                                                                                                       

So the total number of arrangement for a five-lettered word whose letters are all different is 120. So my prediction was correct.

Six lettered-word

PAULIE PAULEI PAUELI PAUEIL PAUIEL PAUILE PALUIE PALUEI PALIUE PALIEU PALEIU PALEUI PAILUE PAILEU PAIULE PAIUEL PAIELU PAIEUL PAELUI PAELIU PAEULI PAEUIL PAEIUL PAEILU

PUALIE PUALEI PUAELI PUAEIL PUAILE PUAIEL PULEIA PULEAI PULIEA PULIAE PULAEI PULAIE PUILEA PUILAE PUIELA PUIEAL PUIAEL PUIALE PUELIA PUELAI PUEALI PUEAIL PUEIAL PUEILA

PLUAEI PLUAIE PLUEAI PLUEIA PLUIEA PLUIAE PLAUEI PLAUIE PLAIUE PLAIEU PLAEIU PLAEUI PLIAUE PLIAEU PLIEAU PLIEUA PLIUEA PLIUAE PLEIAU PLEIUA PLEAIU PLEAUI PLEUIA PLEUAI

PILEAU PILEUA PILUEA PILUAE PILAEU PILAUE PIAULE PIAUEL PIAEUL PIAELU PIALEU PIALUE PIUALE PIUAEL PIULEA PIULAE PIUEAL PIUELA PIEUAL PIEULA PIEAUL PIEALU PIELAU PIELUA

Join now!

PEAULI PEAUIL PEALIU PEALUI PEAILU PEAIUL PEULIA PEULAI PEUALI PEUAIL PEUILA PEUIAL PELUIA PELUAI PELAUI PELAIU PELIAU PELIUA PEILUA PEILAU PEIALU PEIAUL PEIUAL PEIULA

APULIE APULEI APUELI APUEIL APUILE APUIEL APLIUE APLIEU APLUIE APLUEI APLEUI APLEIU APILUE APILEU APIULE APIUEL APIELU APIEUL APELIU APELUI APEULI APEUIL APEIUL APEILU

AUPLIE AUPLEI AUPILE AUPIEL AUPELI AUPEIL AULPIE AULPEI AULEPI AULEIP AULIEP AULIPE AUIPLE AUIPEL AUIEPL AUIELP AUILEP AUILPE AUEPLI AUEPIL AUELIP AUELPI AUEIPL AUEILP

ALPIEU ALPIUE ALPUIE ALPUEI ALPEUI ALPEIU ALUPIE ALUPEI ALUEPI ALUEIP ALUIPE ALUIEP ALIPUE ALIPEU ALIEPU ALIEUP ALIUPE ALIUEP ALEPIU ALEPUI ALEUPI ALEUIP ALEIPU ALEIUP

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