• Join over 1.2 million students every month
• Accelerate your learning by 29%
• Unlimited access from just £6.99 per month
Page
1. 1
1
2. 2
2
3. 3
3
4. 4
4
5. 5
5

# Fencing Problem

Extracts from this document...

Introduction

Fencing Problem Introduction I am going to find out which shape will give the maximum area only using 1000m of fencing. I will also prove that the shape I find is the correct one. Triangles - isosceles To find the area of an isosceles triangle I multiplied the base and the height then divided the answer by 2. I already had the base but not the height so I had to figure out the height using the base and 2 sides. To do this I halved the base and focused on 1 half of the triangle. I then used Pythagoras to figure out the height of the triangle. Once I had the height of my triangle I multiplied it by the base and divided it by 2 to figure out the area. ...read more.

Middle

To find the area we will use spreadsheets to find out all the different areas of each triangle. To figure out the height of each triangle we used the formulae =SQRT((POWER(B2,2))-(POWER(A2/2,2))) To figure out the area of each triangle we used the formulae =(A2*B2)/2 E.g. (449.5�-0.5�=249500) (V249500=499.4997) Squares/Rectangles To find the area of a square I had to multiply 250 x 250 because 1000 � 4 = 250. In theory this should give me the largest area of a polygon with a perimeter of 1000m. To find the area of a rectangle I will use a spreadsheet to try and find the rectangle with the largest area. To work out the area of a rectangle I will use the equation L x W = A We used squares and rectangles because they are 2 of the easiest shapes to calculate and the rectangle also gives a large range of outcomes. ...read more.

Conclusion

To do this we cut the triangle in half to give us 2 right angled triangles then we do the calculation: - 83.33333335 � tan30 = 144.34 (2 d.p) To find the area of one triangle we do the calculation: - 0.5 x 166.6666667 x 144.34(H) = 12028.3 We used hexagons to give us a greater range of answers to find are largest area from. However there is only one possible answer for the regular hexagon. The more sides we investigate in a polygon the smaller the increase in area will be. We no this because the graph shows the increase slowing and the area stop increasing. Also the more sides the more it looks like a circle. This will explain why the area stops increasing because it will reach the same amount of area as a circle. ?? ?? ?? ?? Jon Campling Maths Coursework Mr.McEvoy ...read more.

The above preview is unformatted text

This student written piece of work is one of many that can be found in our GCSE Fencing Problem section.

## Found what you're looking for?

• Start learning 29% faster today
• 150,000+ documents available
• Just £6.99 a month

Not the one? Search for your essay title...
• Join over 1.2 million students every month
• Accelerate your learning by 29%
• Unlimited access from just £6.99 per month

# Related GCSE Fencing Problem essays

1. ## Fencing Problem

get 2 triangles and a rectangle as well, except one of the triangles is flipped upside down in a trapezium. Quadrilateral Area (m�) Perimeter (m) Dimensions (m) Comment Square 62500 1000 metres 250 x 250 The largest quadrilateral of all of them.

2. ## Fencing problem.

the triangle from the centre of the heptagon can be found by dividing 3600 by the number of sides of the shape that has been shown above: Exterior angles = 3600 � Number of sides Exterior angles = 3600 � 7 Exterior angles = 51.40 I shall now find the interior angles of the above shape.

1. ## The Fencing Problem

h 333 167 10) h 332.75 167.25 11) h 332.5 167.5 12) h 332.25 167.75 13) h 332 168 14) h 331.75 168.25 ^ Once more, we have discovered a higher area between the gaps. Judging by the measurements, I can predict that the largest area would be that of an equilateral triangle. Base (m) Sloping Height (m)

2. ## The Fencing Problem

I also know that each side of the hexagon is 1000/6=166.7m. I will use tangent to work out the height of the triangle because I know the adjacent (83.35m) and I want to find out the opposite. height of triangle = 83.35m * tan60?

1. ## Math Coursework Fencing

I predict that the closer the shape gets to a square, the bigger area it will provide. The general formula for calculating the area for a kite is: * If d1 and d2 are the lengths of the diagonals, then the area is However because we don't have the lengths of the two diagonals.

2. ## Geography Investigation: Residential Areas

we get results that show more live with their family and children. However Cumberland Avenue had 80% of its residents over 60 and only 50% still live with their family/children. So when I said that if age is higher there will be more people who own their homes, this is

1. ## Maths Fencing Coursework

SIN 80�= x 200 200 SIN 80� = x x= 196.9615506 x 200 Area=39392.31012 m2 9. SIN 90�= x 200 200 SIN 90� = x x= 200 x 200 Area=40000 m2 10. SIN 100�= x 200 200 SIN 100� = x x= 196.9615506 x 200 Area=39392.31012 m2 11.

2. ## Fencing Problem

are not given the height therefore we have to use Pythagoras' Theorem a2+ b2= c2 (in this case a is the height) H2= c2- b2 rearranging it. (Just a reminder, b = 1/2 B and c = L) H = V (c2- b2)

• Over 160,000 pieces
of student written work
• Annotated by
experienced teachers
• Ideas and feedback to