• Join over 1.2 million students every month
• Accelerate your learning by 29%
• Unlimited access from just £6.99 per month
Page
1. 1
1
2. 2
2
3. 3
3
4. 4
4
5. 5
5
6. 6
6
• Level: GCSE
• Subject: Maths
• Word count: 1322

# For this investigation, I have to find the relationship between a point of any non-linear graph and the gradient of the tangent, which is the gradient function.

Extracts from this document...

Introduction

For this investigation, I have to find the relationship between a point of any non-linear graph and the gradient of the tangent, which is the gradient function. First of all, I have to define the word, ‘Gradient’. Gradient means the slope of a line or a tangent at any point on a curve. A tangent is basically a line, curve, or surface that touches another curve but does not cross or intersect it. To find a gradient, observe the graph below:

All you have to do to find the gradient is to divide the change in X with the change in Y. In this case, on the graph above, AB and you would have gotten the

BC

gradient for that particular point of the graph.

I am going start by finding the gradient function of y=x², y=2x², and then y=ax². I will move on finding the gradient function of y=x³, y=2x³, and finally y=ax³. I will then find the similarities and generalise y=axⁿ where ‘a’ and ‘n’ are constants, and then investigate the Gradient function for any curves of my choice.

...read more.

Middle

1

8

f

3

12

1

12

From the table, you can see that the gradient of the point is always 4 times that of the amount of X. Which means that the gradient function for y=2x² is f ‘(x)=4x.

Now that I have found both the gradient functions for y=x² and y=2x², I shall draw the y=ax² graph (page 5) to show the equation used to find the gradient function for y=x² graphs. I will use a table to present my findings:

 Point X Change in Y Change in X Gradient a -3 6a -1 -6a b -2 4a -1 -4a c -1 2a -1 -2a d 1 2a 1 2a e 2 4a 1 4a f 3 6a 1 6a

As you can see, this information above is very similar to y=x² ‘s information. Its is simply adding an ‘a’ to the Y-axis. But nevertheless, you can see that the gradient function for y=ax² is f ‘(x)=2ax, where ‘a’ is a constant. This gradient function can be used for any graph as long as it is a similar graph to y=x². i.e. y=4x², y=10x² or even y=250x².

The graph y=x² is a rather simple one, when trying to find the gradient function. That is why I will use the graph y=x³ and y=2x³ to find the gradient function of y=ax³, and hopefully be able to find the gradient function for all graphs, namely y=axⁿ. I will, obviously start with y=x³ and shall use a program called, “autograph”, to draw the graphs for me from now on as the graphs are noticeably more accurate than drawing by hand.

 x -3 -2 -1 1 2 3 gradient 27 12 3 3 12 27
...read more.

Conclusion

Observe the picture below:

You should be able to see that the gradient of the chord (in red) will be the gradient of the function, as h tends to zero.

To find the gradient function of any curve, the equation is:

f(x+h) - f(x)

(x+h) - x

= ( f(x+h) - f(x) )

h

## Which means that the gradient of the function at x should be the limit, as h tends to zero.

When we substitute x² into the equation, the equation would be:

f ‘(x)=  (x+h)²-x²

h

= x²+2xh+h²-x²

h

= 2xh+h²

h

f ‘(x)= 2x+h

But if h tends to 0, h=0, then it would be

f ‘(x)= 2x +0 = 2X, where y=x²

If I substituted y=x³ into the equation, I would get f ‘(x)=3x². If I did the same for y=x4, it would be f ‘(x)=4x³. This now shows a very obvious link which would help me generalise y=axn. In the equation, the square would move down in front of ‘x’ and the square of ‘x’ would be a digit lower than the original square. This means that the gradient function of y=axn is f ‘(x)=anx(n-1) .

...read more.

This student written piece of work is one of many that can be found in our GCSE Gradient Function section.

## Found what you're looking for?

• Start learning 29% faster today
• 150,000+ documents available
• Just £6.99 a month

Not the one? Search for your essay title...
• Join over 1.2 million students every month
• Accelerate your learning by 29%
• Unlimited access from just £6.99 per month

# Related GCSE Gradient Function essays

1. ## The Gradient Function Coursework

5 star(s)

If it is not, then I will have to change my formula. The result of my formula for the first example below was calculated like this: m=nax^n-1 => m=-1*1*1^-2 => m= -1 I typed it in as a formula, so that Excel will automatically calculate the result of the formula for me.

2. ## The Gradient Function

The change in x is -1 units. The change in y is 2 units. We now once again have to substitute these values into the equation. The Change in y = 2 = -2 The Change in x = -1 As you can see, the answer to the gradient of the tangent at x = -1 is -2.

1. ## Investigate gradients of functions by considering tangents and also by considering chords of the ...

According to this, I predict that the formula for y=x3 will be g=2x as well. First I will draw the graph to make it clear that how the line will be like. x 1 2 3 4 y 1 8 27 64 Let me obtain the results.

2. ## The Gradient Function Investigation

A second chord, nearer to the point where the gradient is to be calculated can then be drawn and its gradient calculated. After a series of these chords has been drawn, the latter of which will be only a very small X value increase away from the point where the gradient is to be taken, the gradients can be examined.

1. ## Gradient function

An example of this is when x is 10, the gradient is 20 and if I divide them I get 2. Another example of this is when my x is 2, the gradient is 4 and if you divide them you get 2.

2. ## Aim: To find out where the tangent lines at the average of any two ...

Intersection = (1.5,0) (Up to here so far, I have observed that the tangent line at the average of the two roots, -3 & -1.5 happen to intersect the cubic function at its third root, but I am not sure if this is always the case, so I will be

1. ## Gradient Function

5.29 3.71 -0.7 -5.3 -2.2 4.84 4.16 -0.8 -5.2 -2.1 4.41 4.59 -0.9 -5.1 -2 4 5 -1 -5 Power: 2 Coefficient: 1 Fixed point: -3 Observation For the equation Y=X2, the coefficient is 1 the power is 2. I have used 3 different fixed points which are (2, 4), (5, 25)

2. ## The Gradient Function

To improve the tangent I moved A closer to P so it is at A1. The tangent drawn then becomes more accurate as does the gradient. The closer A is to P the more accurate the tangent is. P=(1,1) A1 A2 A3 A4 A5 A6 x1 1.5 1.1 1.01 1.001

• Over 160,000 pieces
of student written work
• Annotated by
experienced teachers
• Ideas and feedback to
improve your own work