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IGCSE Modeling Project bouncing ball
The first 200 words of this essay...
IGCSE Modeling Project bouncing ball
The aim of this investigation is to find out the equation that is suitable for the parabola on the graph. According to my experiment I find out that using a quadratic formula can use be suitable for parabola. The following equation proves my analysis:
f(x)= ax²+bx+c ( this is a quadratic formula, this is the final equation that we will get for the parabola)
For the first parabola the equation is y= -1.725x²+10.02x+1.99
This equation if you type it into a autograph program it will draw a parabola that lies on the points of the first bounce:
to find the values for the equation I use this formula:
= P (x-m) (x-n)
= P (x²-nx-mx+mn)
= P (x²+x(-n-m)+mn)
This formula will turn to a quadratic formula after solving it, and then it would be the equation for the parabola.
For example for the second parabola if you plot in the lowest and highest X coordinate in the bounce it should come out like this: = P (x-6) (x-12)
Then if you solve the equation it should turn out
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