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# In my coursework I am going to investigate the amount of words, letters and paragraphs in each sub-story on the pages where the main headlines are about the 'American Sniper'.

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Introduction

Data Handling Coursework In my coursework I am going to investigate the amount of words, letters and paragraphs in each sub-story on the pages where the main headlines are about the 'American Sniper'. The first paper has four stories in it the second has one and the third has two. I will need to collect the following information; the amount of words in the sub-headlines, the amount of letters in each of those words, the amount of words in the story, the amount of letters in the story and the amount of words with a certain amount of letters, in each story (using a tally chart) Paper Date Story Number Words in Headline Amount of letters in each Monday, Oct 18th 1 4 5,3,4,5 Monday, Oct 18th 2 4 5,2,5,4 Monday, Oct 18th 3 3 5,3,7 ...read more.

Middle

6 10 7 7 8 6 9+ 9 Story 5 Letters in word Tally Frequency 1 12 2 26 3 14 4 31 5 22 6 15 7 19 8 8 9+ 12 Story 6 Letters in word Tally Frequency 1 6 2 18 3 25 4 23 5 18 6 15 7 12 8 9 9+ 9 Now that I have collected my data I will first calculate the mean number of letters to every word in the headlines. Next I will plot a scatter grapgh with all of the information collected in the tally charts. Followed by the type of correlation they show. Thirdly I will make a cumulative frequency table and a cumulative frequency graph along with the lower and upper quartiles and the interquartile range. ...read more.

Conclusion

= 3.6 letters Lower Quartile = 2.3 letters Inter quartile range = Upper Quartile - Lower Quartile = 5.6 - 2.3 = 3.3 letters Histogram (histogram on page 8) Amount of letters Frequency Frequency density 1> L <3 257 257 - 3 = 86 4> L <5 218 218 - 2 = 109 6> L <9+ 218 218 - 4 = 55 Standard Deviation x x - x ( x - x ) 101 -15 225 110 -6 36 96 -20 400 95 -21 441 159 43 1849 135 19 361 x - x = 696 = 116 ( x - x ) = 3312 6 ( x - x ) = 3312 = 552 ( x - x ) = 552 = 23.5 n 6 n Page 1 Center Number: 16327 Karl Buckroyd Candidate Number: 8023 ...read more.

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