Investigate the affects of the surface area: volume ratio on the cooling of an organism.

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Surface Area to Volume Ratio

Plan

Question:

Investigate the affects does the surface area: volume ratio on the cooling of an organism.

Apparatus:

  • 80ml beaker
  • 250ml beaker
  • 500ml beaker
  • 800ml beaker
  • Thermometer
  • Kettle
  • Stop clock
  • Water

Diagram:

Method:

  1. Collect a 80ml beaker
  2. fill with 75ml of boiling water
  3. place a thermometer in the beaker
  4. Wait for temperature to stay constant
  5. record the starting temperature
  6. Time for five minutes
  7. then record the temperature
  8. now work out the decrease in temperature
  9. repeat this three time to work out an average
  10. Repeat all the above using a 250ml,500ml and 800ml size beakers
  11. now work out the surface area of each beaker using the formula (c*h)+(πr²)

Variables:

 

To keep my experiment fair I have to only change one variable and that will be the surface area. All the rest I will keep the same. Therefore my results should be more accurate.

Prediction:

I predict that the beaker with the smaller will lose heat faster than the larger beaker.  This is because of the differences in surface area relative to volume. In a larger object, of the same shape, the amount of surface area per unit of volume is less than in an object of a smaller size. This can be more easily seen with cubes.

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Surface area to volume ratios of above cubes

 Small cube 1: 6                large cube 1: 3

The smaller cube has a volume of 1 unit³ and surface area of 6 units², while the larger cube has a volume of 8 units³ and a surface area of 24 units², this is the same as each unit of volume having 3 units of surface area. In this example the larger cube has half the relative surface area. This means that the smaller cube can loose heat to its environment over a relatively greater area than can the larger cube.

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