• Join over 1.2 million students every month
• Accelerate your learning by 29%
• Unlimited access from just £6.99 per month
Page
1. 1
1
2. 2
2
3. 3
3
4. 4
4
5. 5
5
6. 6
6
7. 7
7
8. 8
8
9. 9
9
10. 10
10
11. 11
11
12. 12
12
13. 13
13
14. 14
14
15. 15
15
16. 16
16
17. 17
17
• Level: GCSE
• Subject: Maths
• Word count: 3039

# Investigate weather or not the co-op or walkers crisps advertise their weight more accurately.

Extracts from this document...

Introduction

Krystina Henderson

Maths Coursework-Statistics

### Introduction

This piece of coursework is my statistics coursework. For this piece of coursework I will be investigating weather or not the co-op or walkers crisps advertise their weight more accurately. Their advertised weight is 25grams.

## Hypothesis

For my hypothesis I predict that the walkers crisps will be more accurate to their advertised weight of 25grams, than the co-op crisps who’s advertised weight is also 25grams. I predict this because walkers are a bigger manufacturer and therefore I think they will try harder to be truer to the ideal weight.

## For this piece of this coursework I will be collecting data, to collect the data I will use cluster sampling to collect the data on the weight of all the crisps, and to find the weight of a empty packet of crisp. I will use random sampling to choose which pieces of data I am going to use. I will be using cluster sampling and random sampling to make sure the data is unbiased.

I am going to group the data because I feel it will be easier to work with if I group it, as I have a lot of data to work with.

Middle

27.50≤w<28.00

0

27.75

0

48

#### Total

1175.5

Estimated mean = Total MGV X Freq

Total Freq

= 1175.5

48

= 24.48958333

= 24.49 (2.d.p)

##### Walker’s Crisps

Group

Freq

MGV

MGV X Freq

20.50≤w<21.00

1

20.75

20.75

21.00≤w<21.50

0

21.25

0

21.50≤w<22.00

0

21.75

0

22.00≤w<22.50

0

22.25

0

22.50≤w<23.00

0

22.75

0

23.00≤w<23.50

0

23.25

0

23.50≤w<24.00

0

23.75

0

24.00≤w<24.50

3

24.25

72.75

24.50≤w<25.00

13

24.75

321.75

25.00≤w<25.50

18

25.25

454.5

25.50≤w<26.00

9

25.75

231.75

26.00≤w<26.50

2

26.25

52.5

26.50≤w<27.00

1

26.75

26.75

27.00≤w<27.50

0

27.25

0

27.50≤w<28.00

1

27.75

27.75

48

###### Total

1208.5

Estimated mean = Total MGV X Freq

Total Freq

= 1208.5

48

= 25.17708333

= 25.18 (2.d.p)

I am now going to do a cumulative frequency graph also known as a c.f. graph. I am using this because I want to find the median for both the CO-OP crisps and the Walker’s crisps.

CO-OP Crisps

 Group Frequency 22.00≤w<22.50 1 22.50≤w<23.00 1 23.00≤w<23.50 2 23.50≤w<24.00 7 24.00≤w<24.50 10 24.50≤w<25.00 17 25.00≤w<25.50 7 25.50≤w<26.00 2 26.00≤w<26.50 1 26.50≤w<27.00 0 27.00≤w<27.50 0 27.50≤w<28.00 0
 Group C.F 22.00≤w<22.50 1 22.50≤w<23.00 2 23.00≤w<23.50 4 23.50≤w<24.00 11 24.00≤w<24.50 21 24.50≤w<25.00 38 25.00≤w<25.50 45 25.50≤w<26.00 47 26.00≤w<26.50 48 26.50≤w<27.00 48 27.00≤w<27.50 48 27.50≤w<28.00 48

From this cumulative frequency graph I can see that the median weight for the CO-OP crisps is 24.6grams. This is lower than the advertised weight, which means the CO-OP are overestimating the weight of their crisps by an average of 0.4g, but this could still make a big difference! The upper-quartile range is 24.9, and the lower quartile range is 24.00g.

Conclusion

### Analysis

Summary Table

 Walker’s Co-op Estimated mean 25.18 (2.d.p) 24.49 (2.d.p) Estimated mode 25.2 24.7 Median 25 24.6 Interquartile range 0.7 0.9 Standard Deviation 0.8 0.7

My data shows that the Walkers estimated mean is 25.12 as this is over 25 it suggest that walkers are overestimating the weight of their crisps while the Co-op estimated mean is 24.49 which suggest the opposite they are underestimating the weight of their crisps. The estimated mode for walkers is 25.2 and the estimated mode for Co-op is 24.7, which again suggest walkers are overestimating and the Co-op is underestimating the weight of their crisps.

All this data suggest that my hypothesis is correct. As Walkers crisps are truer to their advertised weight and there is extra in their crisps as well. From my data it seems that the Co-op underestimate the weight of their crisps.

The factors that could have effected my results would be any outliers, or incorrect readings.

This is my result from my standard deviation for the Co-op crisps.

### Co-op

##### Standard deviation = 0.772211260  - 0.77(2.d.p)

Mean                     = 24.0445625   - 24.04

This is my result from my standard deviation for the Walkers crisps.

### Walkers crisps

Standard deviation = 0.853581466  - 0.85(2.d.p)

Mean                     = 25.18288462 – 25.18 (2.d.p)

I am now going to show the results of my Standard deviation on a table.

This student written piece of work is one of many that can be found in our GCSE Height and Weight of Pupils and other Mayfield High School investigations section.

## Found what you're looking for?

• Start learning 29% faster today
• 150,000+ documents available
• Just £6.99 a month

Not the one? Search for your essay title...
• Join over 1.2 million students every month
• Accelerate your learning by 29%
• Unlimited access from just £6.99 per month

# Related GCSE Height and Weight of Pupils and other Mayfield High School investigations essays

1. ## A hypothesis is the outline of the idea/ideas which I will be testing and ...

by 20= 4 Below are the Results of my Sample Surname Forename Right Handed IQ Level SAT's Results Robinson Luke Left 100 4 4 4 Lister Kuta Left 104 4 5 4 Abejurouge Henry Right 89 3 3 3 Aberdeen Richard Right 103 4 5 4 Acton Jenny Right 108

2. ## Maths Data Handling

This suggests that the correlation is better for girls than for boys. > The points on the scatter graph for boys and girls are less dispersed than the points on the scatter graph for the mixed sample of boys and girls.

1. ## mayfeild statistics

1 84 2 86 2 The median and mode are not influenced by outliers, but the mean is influenced by outliers. This means that the value of the mean may not be accurate as there may be outliers in my set of results.

2. ## maths coursework t-shapes

21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 Table of Results (Seven Number Grid) T-Number (n) T-Total First Difference Second Difference Formula 16 (1+2+3+9+16)= 31 5 31-(5*16)= -49 5n-49

1. ## Reaction Times.

Standard Deviation: Although the conclusions of each graph so far have been unanimous, I feel it is necessary to take a measure of dispersion, which will take into account all the data values. Year 7: Mean = 99 (0dp) Reaction Time (?)

2. ## statistics coursework

40 3 40 < w ? 50 22 50 < w ? 60 12 60 < w ? 70 2 70 < w ? 80 1 80 < w ? 90 0 I will use tally to represent my data.

1. ## Mayfield data

1.62 51 11 Little James 1.65 47 11 Vincent Nigel 1.8 62 2) Female Stratified Sample Results Year Group Surname Forename 1 Height (m) Weight (kg) 7 Butler Leanne 1.65 40 7 Earnshaw Catherine 1.45 41 7 Meager Becky 1.64 47 7 Miles Amanda 1.46 40 7 Richards Abbie 1.53

2. ## Maths Coursework - Statistics

median lower and upper quartile values than of the first form data. I feel that the 5th formers mean value for the height head will be closer to the median value because of the age and their growth development level.

• Over 160,000 pieces
of student written work
• Annotated by
experienced teachers
• Ideas and feedback to