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Investigating the Gradients of Graphs of the Form ‘y=ax’

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Introduction

Investigating the Gradients of Graphs of the Form 'y=ax' Aim To find a formula for the gradient of a 'y=ax' graph. To do this I will take a number of values of 'a' find the gradients and form a conclusion. Having done this I will test my theory with a different value of 'a'. The values of 'a' that I will test are: 1,2,3 and 5 Then a fraction and a negative number: 1/5 and -4. ...read more.

Middle

1 2 3 4 5 6 7 8 9 10 a=2 x 0 1 2 3 4 5 6 7 8 9 10 y 0 2 4 6 8 10 12 14 16 18 20 a=3 x 0 1 2 3 4 5 6 7 8 9 10 y 0 3 6 9 12 15 18 21 24 27 30 a=5 x 0 1 2 3 4 5 6 7 8 9 10 y 0 5 10 15 20 25 30 35 40 45 50 a=1/5 x 0 1 2 3 4 ...read more.

Conclusion

Conclusion I conclude that the gradient is equal to the value of 'a' and that therefore the gradient function equals 'a'. To test this conclusion I will draw a graph of 'y=8x' where 'a' equals 8. Results II a Gradient 8 8 Conclusion II This proves my theory so I can now say that in a graph of the form 'y=ax' the gradient equals 'a'. This can also be referred to as the gradient function(G.F.). G.F. = a ...read more.

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