TN= N+(N-9)+(N-19)+(N-18)+(N-17)
6 + 7 + 8 + 16 + 25 = 62
Therefore the T-Total for 25 is 62.
My estimation was spot on.
To find the rule, first I multiplied 5 by the T-Number.
For example:-
Step 1
5 x 20 = 100
Then I took away the T-Total from the figure I got once I had multiplied 5 by the T-Number.
For Instance:-
Step 2
100 – 37 = 63
As a result the rule in Algebraic form is:
TN= N+(N-9)+(N-19)+(N-18)+(N-17)
(By adding all the n’s together you get 5n)
TN= N+(N-9)+(N-19)+(N-18)+(N-17)
(by doing the equation you get –63)
5n – 63
In witch n represents the T-Number
I experimented this rule for another T-Shape selected at random here are the results :-
5 x 69 = 345
345 – 63 = 282
Hence I think the T-Total for T-Number 69 will be 282:-
TN= N+(N-9)+(N-19)+(N-18)+(N-17)
50 + 51 + 52 + 60 + 69 = 282
My rule for gird size 9 by 9 is precise.
Now I am going to investigate the relationship between the T-Total and the T-Number on a variety of grids of different sizes.
8 by 8 grid
TN= N+(N-8)+(N-16)+(N-15)+(N-17)
1 + 2 +N- 3 +10 +18 =
T18=34
TN= N+(N-8)+(N-16)+(N-15)+(N-17)
2 + 3 + 4 + 11 + 19=
T19=39
TN= N+(N-8)+(N-16)+(N-15)+(N-17)
3 + 4 + 5 +12 + 20=
T20=44
Here is the results table for the 8 by 8 grid :-
The T-Total increase’s by 5 so the rule for the 8 by 8 grid would be found in the similar way to the 9 by 9 grid.
To work out the rule for this grid I multiplied 5 by the T-Number and took away the T-Total.
e.g.
5 x 18 = 90
90 – 34 = 56
As a result the rule for the 8 by 8 grid is :-
TN= N+(N-8)+(N-16)+(N-15)+(N-17)
(By adding together all the n’s you get 5n)
TN= N+(N-8)+(N-16)+(N-15)+(N-17)
(By doing the equation you get left with –56)
5n – 56
Now I am going to do a 10 by 10 grid.
The working out for the rule
TN= N+(N-10)+(N-20)+(N-21)+(N-19)
1 + 2 + 3 + 12 + 22 =
T22=40
22 x 5 = 110
110 – 40 = 70
Therefore the rule for the 10 by 10 grid is:
TN= N+(N-10)+(N-20)+(N-21)+(N-19)
(By adding together all the n’s you get 5n)
TN= N+(N-10)+(N-20)+(N-21)+(N-19)
(by doing the equation you get –70)
5n – 70
Now I am going to do a 11 by 11 grid
TN= N+(N-11)+(N-23)+(N-22)+(N-21)
1 + 2 + 3 + 13 + 24 =
T24=43
5 X 24 =120
120 – 43 =77
The rule for the 11 by 11 grid Is :-
TN= N+(N-11)+(N-23)+(N-22)+(N-21)
(By adding together all the n’ s you will get 5n)
TN= N+(N-11)+(N-23)+(N-22)+(N-21)
(By doing the equation you get –77)
5n – 77
Now I am going to draw a results table for the rules of different grid sizes
Results table
As you can see from the results the rule increases by 7 in each grid. Also the last figure is obtained by multiplying the grid size by 7.
For example:-
The rule for the 8 by 8 grid is 5n – 56
7 x 8 = 56
Therefore to show this in algebraic form it would be:
7g
Were as the algebraic equation for all of it would be:
5n – 7g
Now I am going to test this rule to see if it works on any grid size. I will do this on a 12 by 12 grid.
12 by 12 grid
5t – 7g is my rule here is the working out
5 x 26 =130
7 x 12 =84
Therefore I think the rule for the 12 by 12 grid will be :
130 – 84
Now I am going to see if I am right
TN=N+(N-12)+(N-24)+(N-23)+(N-25)
TN= 1+ 2+ 3 + 14 + 26=46
5 x 26 = 130
130 – 46 = 84
Therefore this proves that the rule works on any size grid.