• Join over 1.2 million students every month
• Accelerate your learning by 29%
• Unlimited access from just £6.99 per month
Page
1. 1
1
2. 2
2
3. 3
3
4. 4
4
5. 5
5
6. 6
6
7. 7
7
8. 8
8
9. 9
9
10. 10
10
11. 11
11
12. 12
12
13. 13
13
14. 14
14
15. 15
15
• Level: GCSE
• Subject: Maths
• Word count: 2779

# Number Stairs.

Extracts from this document...

Introduction

## Number Stairs

 91 92 93 94 95 96 97 98 99 100 81 82 83 84 85 86 87 88 89 90 71 72 73 74 75 76 77 78 79 80 61 62 63 64 65 66 67 68 69 70 51 52 53 54 55 56 57 58 59 60 41 42 43 44 45 46 47 48 49 50 31 32 33 34 35 36 37 38 39 40 21 22 23 24 25 26 27 28 29 30 11 12 13 14 15 16 17 18 19 20 1 2 3 4 5 6 7 8 9 10

On the 10 by 10 number grid above I have drawn a stair shape. This is known as a three-step stair.

The total of the numbers inside the stair is:

55+45+46+35+36+37=254

So the stair total for this shape is 254.

The stair number for this shape is stair 35 as the number in the bottom left hand corner is 35.

Now we can investigate the relationship between the position of the stair shape on the grid and the stair total. The diagram below is stair 1 as the number in the bottom left hand corner is 1.

 21 11 12 1 2 3

As we see, the stair total for this 3-step stair1 on this 10 by 10-number grid is 50 as 1 + 2 + 3 + 11 + 12 + 21 = 50.

Below is the stair shape one square to the right of stair1. This stair is called stair2 as the number in the bottom left hand corner is 1. Stair2 is a translation of stair1 one square to the right.

 22 12 13 2 3 4

The stair total for this stair shape is 2 + 3+ 4 + 12 + 13 + 22 = 56.

Now we are going to find the step total for stair3 (a translation of stair2 one step to the right).

 23 13 14 3 4 5

The stair total for this stair shape is 3 + 4 + 5 + 13 + 14 + 23 = 62.

Now we can find the stair total for stair4 (which is a translation of stair 3 one square to the right).

 24 14 15 4 5 6

Middle

Stair Number:  1                         11                        21                        31

### Stair total:      50                          110                        170                        230

Difference:                    60                         60                               60

I can now predict that the stair total for stair 41 is going to be 230 + 60=290.

Here is the stair to prove my prediction is correct.

 61 51 52 41 42 43

The stair total for this shape is 41 + 42 + 43 + 51 + 52 + 61 = 290.

We can therefore say that every time you move the shape one square down the total decreases by 60 and when you move one square up the grid then total increases by 60. Also when you move one square to the right of the grid the total increases by 6 and when you move one square to the left the total decreases by 6.

The reason the total increases by 60 when you move the shape one square up on the grid is because since there are 6 squares in a 3-step stair and each separate number increases by 10. 6 multiplied by 10 equals 60.

The reason the total increases by 6 when you move the shape one square to the right on the grid is because there are 6 squares in a 3-step stair and each separate number increases by 1. 1 multiplied by 6 equals 6.

We can now introduce algebra in order to find a common formula to find the stair total for and 3-step stair on a 10 by 10-number grid.

 x+20 x+10 x+11 x x+1 x+2

Conclusion

7a+3b+c        ,     9a+5b+c        ,   37a+7b+c        ,         61a+9b+c

12a+2b        ,      18a+2b        ,    24a+2b

6a        ,        6a

I am now going to match the numbers in the cubic sequence formula above to the numbers that correspond to their positions in the co-efficient in front of g sequence.

6a = 1

a   = 1/6

12a+2b = 3

12(1/6) + 2b = 3

2 + 2b = 3

2b = 1

b = 0.5

7a+3b+c= 3

7(1/6)+3(1/2)+c = 3

c= 1/3

a+ b + c + d = 1

1/6 + ½ + 21/3 + d = 1

d = 0

Therefore the equation for this part of the sequence will be :

(1/6 n3 + 1/2n2 + 1/3n) = coefficient of g

Section 3 : The Sequence For The Constant

The sequence for the constant will go exactly the same as the sequence for the co-efficient of g as all these values are the same. Therefore the equation for this part of the sequence will be :

(1/6 n3 + 1/2n2 + 1/3n) = the constant

Conclusion

##### Now that we have finished the three parts of the sequence we can put them together in order to make one equation for any size step-stair on any size grid.

(1/2 n2  + 3/2n + 1)x + (1/6 n3 + 1/2n2 + 1/3n)g + (1/6 n3 + 1/2n2 + 1/3n)= stair total

x means the number of squares in the stair shape.

g stands for grid size.

n is the equation number. ( If you don’t know the equation number it is the same number as the number of squares in the 2nd column from the left of the stair shape).

-  -

This student written piece of work is one of many that can be found in our GCSE Number Stairs, Grids and Sequences section.

## Found what you're looking for?

• Start learning 29% faster today
• 150,000+ documents available
• Just £6.99 a month

Not the one? Search for your essay title...
• Join over 1.2 million students every month
• Accelerate your learning by 29%
• Unlimited access from just £6.99 per month

# Related GCSE Number Stairs, Grids and Sequences essays

1. ## For other 3-step stairs, investigate the relationship between the stair total and the position ...

Using any of the algebra equation from the above table, e.g. 6x-36 or 6x-44 we can prove the results for any 3-step grid. The follow exercises in table 11 shows the expected results: Table 11 33 FORMULA = 6x - 36 43 44 1: ( 6 x 53)

2. ## Number Stairs

=15x So to get the value of (n) I will add the numbers together. 1+2+3+4+10+11+12+13+20+21+22+30+31+40 =220 So I think the Stair Total for any 5-Step Stair is 15x+220=t And I predict that if x= 1 then, 15(1)+220= 235. And if x=4 then,15(4)+220 =280 To see if I am right I will draw the two stairs I predicted and input their original numbers.

1. ## Algebra Investigation - Grid Square and Cube Relationships

Testing: Using the experimental number box above, it is possible to prove that the formula works, and is correct. The box had a height and width of 2x2, and was based on the 6x6 grid in question. As the number box clearly demonstrates, a difference of 6 should be present.

2. ## Number stairs

3-step stair I can start to establish if there is a pattern I need to find a pattern so that I can find an algebra formula to represent this pattern and use the formula for the 12 by 12 Number Grid By looking at the 3 step stair diagram we

1. ## Maths - number grid

60x96 - 56x100 5760 - 5600 Difference = 160 2) 6x42 - 2x46 252 - 92 Difference = 160 By looking at these calculations it can be assumed that they are correct because they give the same defined difference of 160.

2. ## Number Stairs

And those are: Stair number = 61 Stair total = (6x61) + 40 = 406, or alternatively, 61+62+63+70+71+79= 406 Stair number=7 Stair total= (6x7) + 40= 82 With out the nth term the stair total= 7+8+9+16+17+25=82 Stair number=55 With out the nth term stair total= 55+56+57+64+65+73= 370 With nth term, stair total= (6x55)

1. ## Maths-Number Grid

73 74 75 83 84 85 93 94 95 3 � 3 Grids:- 1 2 3 11 12 13 21 22 23 74 75 76 84 85 86 94 95 96 52 53 54 62 63 64 72 73 74 From the above grid I have found out that my

2. ## Maths Grids Totals

+ x(n-1) + 10(n-1)2. x[x+11(n-1)] = x2 + 11x(n-1). When multiplied out, this becomes: x2 + 10x(n-1) + x(n-1) + 10(n-1)2 - x2 - 11x(n-1). x2 = x � x. 10x(n-1)= x � 10(n-1). x(n-1) = x � (n-1). 10(n-1)2 = 10(n-1) � (n-1).

• Over 160,000 pieces
of student written work
• Annotated by
experienced teachers
• Ideas and feedback to