2x3 squares
(3 = width)
1x13= 13
11x3= 33
18x10= 180
8x20= 160
66x58= 3828
56x68= 3808
The difference is always 20.
Nn n+1 n+2 n+3
Ln+10 n+11 n+12 n+13
Hn(n+13) Difference is 20
(n+3) (n+10)
3x3 Squares
1x23= 23
21x3= 63
43x65= 2795
63x45= 2835
68x90= 6120
88x70= 6160
The difference is always 40.
n n+1 n+2
n+10 n+11 n+12
n+20 n+21 n+22
Hn(n+22) Difference is 40
(n+2) (n+20)
2(w)xL Difference The numbers step up in 10
2 10
3 20 >10
4 30 >10
I predict that a 2x5 square will have a difference of 40.
4x4
-
2 3 4 1x14=44
11x4=44
11 12 13 14
The difference is 40. Now I need to test out my prediction:
1 2 3 4 5 1x15= 15
11x5=55
11 12 13 14 15
The prediction was correct, the difference is 40.
So that means that if you want to work out the answer for a 2x11 square, you’ll look at the above results and find a formula.
(Wx10) –10 = difference
So a 2x11 square would have a difference of 100, and that can be worked out by doing the following:
11x10 = 110
-10 = 100
3(w) xL Difference
2 20
3 40
4 60
3x4
1 2 3 1x33= 33
31x3= 93
- 12 13
21 22 23
31 32 33
The difference is 40.
I predict that a 3x5 square will have a difference of 80.
1 2 3 1x43=43
41x3=123
11 12 13
21 22 23
31 32 33
41 42 43
The difference is 80 which means that my prediction was correct.
4x4 Squares
1x34= 34
31x4= 124
27x60= 1620
30x57= 1710
52x85= 4420
55x82= 4510
The difference is always 90
n n+1 n+2 n+3
n+10 n+11 n+12 n+13
n+20 n+21 n+22 n+23
n+30 n+31 n+32 n+33
Hn(n+33) Difference is 90
(n+3) (n+30)
General Formula
The general formula is the formula that helps you work out the formula needed to calculate the difference for the square numbers.
Square number (w) _ Formula
2 (wx10) –10 = difference
3 (wx20) – 20 = difference
4 (wx30) – 30 = difference
5 (wx40) – 40 = difference
I predict that a 5x5 square will have a formula of:
(wx40) – 40
This is because I have made a formula to work out the general formula, and tested it out:
w[10(w – 1)] – [10(w – 1)]
w – 1
Square number = 2 (w)
- – 1 = 1
x 10 = 10
x 2 = 20
– 1 = 1
x 10 = 10
20 – 20 = 10
divided by 2 – 1 = 10
All you do is write out this equation: (wx__) - __ and replace the two blank spaces with the number that you have found
That proves to be correct, so now I will see if the theory for the 5x5 square is correct.
I predicted that the formula would be:
(wx40) – 40 = difference
5[10(5 – 1)] – [10(5 – 1)]
5 – 1
5(4x10) – (4x10)
4
40x5 = 200 – 40 = 160
160 divided by 4 = 40
The formula proves to be correct.